Bash 递归grep和sed
文件1: 我想在有text3的行中将text1替换为say NEW only 最终输出应为Bash 递归grep和sed,bash,awk,sed,grep,Bash,Awk,Sed,Grep,文件1: 我想在有text3的行中将text1替换为say NEW only 最终输出应为 some line1 some line2 text1 text2 text3 some line3 text1 text2 text4 some line3 我正试着处理格雷普和塞德,但没有帮助 感谢您的帮助。您可以使用sed: some line1 some line2 NEW text2 text3 so
some line1
some line2
text1 text2 text3
some line3
text1 text2 text4
some line3
我正试着处理格雷普和塞德,但没有帮助
感谢您的帮助。您可以使用
sed
:
some line1
some line2
NEW text2 text3
some line3
text1 text2 text4
some line3
您可以使用
sed
:
some line1
some line2
NEW text2 text3
some line3
text1 text2 text4
some line3
你要求做的事情没有递归性。你读过关于sed的手册/doc/jelp/man吗?你要求做的事情没有递归性。你读过关于sed的手册/doc/jelp/man吗?
$ sed '/text3/s/text1/NEW/' file
some line1
some line2
NEW text2 text3
some line3
text1 text2 text4
some line3
$ awk '/text3/{sub(/text1/,"NEW")}1' file
some line1
some line2
NEW text2 text3
some line3
text1 text2 text4
some line3