Bash Bazel genrule：在命令中使用换行符

我使用的genrule有很多源代码，它们有一个很长的标识符。该命令需要明确列出所有源，这将导致一个非常长的cmd。因此，我尝试使用换行符（如bash或shell命令所示）。。。 然而，bazel抱怨字符串未端接

genrule(
  name = "Aggregate_Reports",
  srcs = ["//really/long/path/to/module/ModuleA/src:CoverageHtml",
          "//really/long/path/to/module/ModuleA/src:TestRun",
          "//really/long/path/to/module/ModuleB/src:CoverageHtml",],
  outs = ["UT_Summary.txt"],
  message = "Create unified report",
  tools = [":Create_Summary"],
  cmd = "$(location :Create_Summary) -t \
              $(location //really/long/path/to/module/ModuleA/src:TestRun) \
              $(location //really/long/path/to/module/ModuleB/src:TestRun) \
                                     -c \
              $(location //really/long/path/to/module/ModuleA/src:CoverageHtml) \
              $(location //really/long/path/to/module/ModuleB/src:CoverageHtml) \
              -o $(@)",
  executable = True,
  visibility=["//visibility:public"],
)

---

用$转义\不会改变任何东西…

在Python中，可以使用三重引号保留换行符：

  cmd = """$(location :Create_Summary) -t \
              $(location //really/long/path/to/module/ModuleA/src:TestRun) \
              $(location //really/long/path/to/module/ModuleB/src:TestRun) \
                                     -c \
              $(location //really/long/path/to/module/ModuleA/src:CoverageHtml) \
              $(location //really/long/path/to/module/ModuleB/src:CoverageHtml) \
              -o $(@)""",

---

与Python中一样，可以使用三重引号保留换行符：

  cmd = """$(location :Create_Summary) -t \
              $(location //really/long/path/to/module/ModuleA/src:TestRun) \
              $(location //really/long/path/to/module/ModuleB/src:TestRun) \
                                     -c \
              $(location //really/long/path/to/module/ModuleA/src:CoverageHtml) \
              $(location //really/long/path/to/module/ModuleB/src:CoverageHtml) \
              -o $(@)""",