C 2x2矩阵乘法
我正试图写一个程序来计算两个矩阵的和和和积,但我不能让它的积工作。总数很好。我正在使用VisualStudio 以下是我的节目:C 2x2矩阵乘法,c,visual-studio,matrix,matrix-multiplication,C,Visual Studio,Matrix,Matrix Multiplication,我正试图写一个程序来计算两个矩阵的和和和积,但我不能让它的积工作。总数很好。我正在使用VisualStudio 以下是我的节目: #include <stdio.h> #include <stdlib.h> int main() { float a[2][2], b[2][2], c[2][2], d[2][2], sum; int i,j,k; for(i = 0; i < 2; i++) { for(j = 0; j
#include <stdio.h>
#include <stdlib.h>
int main()
{
float a[2][2], b[2][2], c[2][2], d[2][2], sum;
int i,j,k;
for(i = 0; i < 2; i++) {
for(j = 0; j < 2; j++) {
d[i][j] = 0;
}
}
printf("Enter the elements of 1st matrix\n");
/*
* Reading two dimensional Array with the help of two for loop. If there
* was an array of 'n' dimension, 'n' numbers of loops are needed for
* inserting data to array.
*/
for (i = 0; i < 2; ++i)
for (j = 0; j < 2; ++j) {
printf("Enter a%d%d: ", i + 1, j + 1);
scanf("%f", &a[i][j]);
}
printf("\nEnter the elements of 2nd matrix\n");
for (i = 0; i < 2; ++i)
for (j = 0; j < 2; ++j) {
printf("Enter b%d%d: ", i + 1, j + 1);
scanf("%f", &b[i][j]);
}
printf("\nMatrix 1:\n");
for (i = 0; i < 2; ++i)
for(j = 0; j < 2; ++j) {
printf("%.1f\t", a[i][j]);
if (j == 1) /* To display matrix sum in order. */
printf("\n");
}
printf("\nMatrix 2:\n");
for(i = 0; i < 2; ++i)
for(j = 0; j < 2; ++j) {
printf("%.1f\t", b[i][j]);
if (j == 1) /* To display matrix sum in order. */
printf("\n");
}
for (i = 0; i < 2; ++i)
for(j = 0; j < 2; ++j) {
/* Writing the elements of multidimensional array using loop. */
c[i][j]=a[i][j]+b[i][j]; /* Sum of corresponding elements of two arrays. */
}
printf("\nSum Of Matrix:\n");
for (i = 0; i < 2; ++i)
for(j = 0; j < 2; ++j) {
printf("%.1f\t",c[i][j]);
if (j == 1) /* To display matrix sum in order. */
printf("\n");
}
for(i = 0 ; i < 2 ; i++) {
for(j = 0 ; j < 2 ; j++) {
sum = 0 ;
for(k = 0 ; k < 2 ; k++) {
sum = sum + a[i][k] * b[k][j];
printf("a: %d; b: %d\n", a[i][k], b[k][j]);
printf("%d", sum);
}
d[i][j]=sum;
}
}
printf("\nThe multiplication matrix is : \n\n") ;
for(i = 0; i < 2; i++) {
for(j = 0; j < 2; j++) {
printf("%d \t", d[i][j]) ;
}
printf("\n") ;
}
system("PAUSE");
return 0;
}
我看不出矩阵A和B的问题在哪里。首先,我不会将for循环的终止硬编码为常量,而是将其编码为
sizeof(A)/sizeof(A[0])
。其次,问题是您试图打印浮点,因为ints-第68行显示:
printf(“a:%d;b:%d\n”,a[i][k],b[k][j])代码>
但应该是这样
printf(“a:%.1f;b:%.1f\n”,a[i][k],b[k][j])代码>
这些问题存在于第68、69和79行。如果您将%d更改为%f,您应该不会有问题。是的,或者甚至是%.1f
来匹配前面的语句。感谢@WeatherVane,将您的建议合并到编辑中。优秀的编译器会警告有关格式说明符和参数不匹配的问题,如float sum。。。printf(“%d”,总和)代码>。节省时间,确保编译器警告完全启用或考虑一个新编译器。
Matrix 1:
1.0 2.0
3.0 4.0
Matrix 2:
5.0 6.0
7.0 8.0
Sum Of Matrix:
6.0 8.0
10.0 12.0
a: 0; b: 1072693248
0a: 0; b: 1073741824
0a: 0; b: 1072693248
0a: 0; b: 1073741824
0a: 0; b: 1074266112
0a: 0; b: 1074790400
0a: 0; b: 1074266112
0a: 0; b: 1074790400
0
The multiplication matrix is :
0 0
0 0