如何删除用户在c中选择的2d数组的N个行和列
我正在编写一段代码，它使用一个包含2d数组和预定函数的结构，我已经列出了这些函数，并给出了描述函数功能的注释如何删除用户在c中选择的2d数组的N个行和列,c,pointers,multidimensional-array,C,Pointers,Multidimensional Array,我正在编写一段代码，它使用一个包含2d数组和预定函数的结构，我已经列出了这些函数，并给出了描述函数功能的注释 struct matrix { char name; int mValues[10][10[; int nrows; int ncols; }; /** Function Prototypes**/ // Lets user name, choose dimensions and populates matrix from a 10x10 .txt fi
struct matrix
{
char name;
int mValues[10][10[;
int nrows;
int ncols;
};
/** Function Prototypes**/
// Lets user name, choose dimensions and populates matrix from a 10x10 .txt file
void matrixInput(struct matrix *matA);
// Asks the user to choose how many rows to delete and select which rows
// Asks the user to choose how many columns to delete and select which columns.
// The result should be a sub matrix of the input matrix stored in a new struct matrix
void subMatrix(struct matrix m1, struct matrix *m2);
// What the Input/Output should look like
How many rows do you want to delete? : 2
Please enter, one per row, the number(s) of the 2 rows you want to delete : 2
Please enter, one per row, the number(s) of the 2 rows you want to delete : 1
How many columns do you want to delete? : 3
Please enter, one per column, the number(s) of the 3 columns you want to delete : 4
Please enter, one per column, the number(s) of the 3 columns you want to delete : 2
Please enter, one per column, the number(s) of the 3 columns you want to delete : 5
// Displays sub matrix
请注意，欢迎提供有关如何提高问题质量的任何提示。如果您知道要删除哪些列和行，并且确定结果将适合新矩阵，则只需执行嵌套循环，并告诉它忽略特定的值范围
但是您真正想要做的是在复制函数中创建新的矩阵并返回它。如果它们是动态创建的，您可以忽略以相同方式复制的列或行的分配（嵌套循环），并使其完全符合您需要的大小。您不能轻松地将删除信息存储在矩阵中，因为
矩阵->值[0][0]m1void subMatrix（结构矩阵m1，…）m1void子矩阵（const struct matrix*source，…）值[10][10]struct matrix {
int **data;
int rows;
int cols;
};
void create(struct matrix *m, int rows, int cols)
{
m->rows = rows;
m->cols = cols;
m->data = malloc(rows * sizeof(int*));
for(int r = 0; r < rows; r++)
m->data[r] = malloc(sizeof(int) * cols);
}
void destroy(struct matrix *m)
{
for(int i = 0; i < m->rows; i++)
free(m->data[i]);
free(m->data);
}
void print(const struct matrix *m)
{
for(int r = 0; r < m->rows; r++)
{
for(int c = 0; c < m->cols; c++)
printf("%4d", m->data[r][c]);
printf("\n");
}
printf("\n");
}
void change(struct matrix *new, struct matrix *m, int *delete_rows, int *delete_cols)
{
int rows = 0;
for(int row = 0; row < m->rows; row++)
if(!delete_rows[row])
rows++;
int cols = 0;
for(int col = 0; col< m->cols; col++)
if(!delete_cols[col])
cols++;
create(new, rows, cols);
int next_row = 0;
for(int row = 0; row < m->rows; row++)
{
if(delete_rows[row]) continue;
int next_col = 0;
for(int col = 0; col < m->cols; col++)
{
if(delete_cols[col]) continue;
new->data[next_row][next_col] = m->data[row][col];
next_col++;
}
next_row++;
}
}
int main(void)
{
struct matrix m;
create(&m, 10, 10);
for(int r = 0; r < m.rows; r++)
for(int c = 0; c < m.rows; c++)
m.data[r][c] = r * 100 + c;
print(&m);
//get delete information
int delete_rows[10] = { 0 };
int delete_cols[10] = { 0 };
delete_rows[0] = 1;//delete row 0
delete_cols[7] = 1;//delete col 7
struct matrix new;
change(&new, &m, delete_rows, delete_cols);
print(&new);
destroy(&m);
destroy(&new);
return 0;
}
nrowsncolsstruct矩阵