如何使用C在bash中实现逻辑运算符？

我是C编程新手。我试图用逻辑运算符编写一个简单的命令行解释器。它的工作原理如下：

command1 ; command2 || command3 && command4
if ; second command will be executed after first command
if || second command only be executed if first command failed
if && second command will only be executed if first one succeeded

例如：

echo one ; echo one || echo two && echo four

输出应如下所示：

command1 ; command2 || command3 && command4
if ; second command will be executed after first command
if || second command only be executed if first command failed
if && second command will only be executed if first one succeeded

一个

一个

四

任何提示都将不胜感激。

int命令\u执行（无效）{
int command_execute(void){
int i;
int next = 0;
int previous = 0;
while(moperator >= 0){ //moperator recorded the numbers of logical operators
    if(execute(words[next], next)== 0){ //words stored the tokenize string 
        moperator--;                    
        for(i = previous; i < nwds; i++){
            if(!strcmp(cwords[i], ";")){ //cwrods is a copy of words  
                previous = i;
                next = i + 1;
                moperator--;
                break;
            }else if(!strcmp(cwords[i], "||")){
                continue;
            }else if(!strcmp(cwords[i], "&&")){
                moperator--;
                previous = i;
                next = i + 1;
                break;
            }
        }
    }else{
        for(i = previous; i < nwds; i++){
            if(!strcmp(cwords[i], ";")){
                previous = i;
                next = i + 1;
                break;
            }else if(!strcmp(cwords[i], "||")){
                previous = i;
                next = i + 1;
                break;
            }else if(!strcmp(cwords[i], "&&")){
                    continue;
                }
        }    
      }
    }
    return 0;
}

int i；
int next=0；
int-previous=0；
而（moperator>=0）{//moperator记录了逻辑运算符的数目
if（execute（words[next]，next）==0）{//存储在标记化字符串中的单词
摩托车手；
对于（i=先前；i

---

这是我编写的用来调用以执行命令的方法。输入已通过删除空格进行标记。

显示您迄今为止的尝试。为什么您不能将此添加到您的问题中，而不是将其作为答案？