C 通过for循环读取字符串时获得随机重复
不管我怎样C 通过for循环读取字符串时获得随机重复,c,arrays,string,comparison,iteration,C,Arrays,String,Comparison,Iteration,不管我怎样 Down, down, down. Would the fall NEVER come to an end! 'I wonder how S1: line 1, bytes = 68 S2: line 1, score = 5.000 --- many miles I've fallen by this time?' she said aloud. 'I must be getting S1: line 2, bytes = 72 S2: l
Down, down, down. Would the fall NEVER come to an end! 'I wonder how
S1: line 1, bytes = 68
S2: line 1, score = 5.000
---
many miles I've fallen by this time?' she said aloud. 'I must be getting
S1: line 2, bytes = 72
S2: line 2, score = 4.000
SO: query = fall down
---
Down, down, down. Would the fall NEVER come to an end! 'I wonder how
S1: line 1, bytes = 68
line 1, score = 0.000000
---
many miles I've fallen by this time?' she said aloud. 'I must be getting
S1: line 2, bytes = 72
: line 2, score = 0.000000
---
SO:query=fall-down
---
下来，下来，下来。秋天永远不会结束我想知道怎么做
S1：第1行，字节=68
下来，下来，下来。难道秋天永远不会来临吗？崩溃，倒下，倒下。秋天永远不会结束我不知道该怎么办⌠“”S2:第1行，分数=0.000000
---
“到现在为止，我已经跌了好几英里了？”她大声说我一定是疯了
S1：第2行，字节=72
“这次我已经走了多少英里了？”她大声说，“这次我走了多少英里了。”我一定是疯了⌠“”S2：第2行，分数=0.000000
---
int
打印行（字符查询[最大查询]）{
int line_num=0；
int query_len=strlen（查询）；
内线长度=0，i，y，z=0，位置，c=0；
int limit=query\u len>line\u len？line\u len:query\u len；
双倍分数=0，最大值；
char score_list[15]=“”；
字符行[最大行]；
而（（行长度=读取行（行））！=EOF）{
c=0；
行_num++；
printf（“S1：第%d行，字节=%d\n”，第n行，第n行）；
/*循环查询和行并比较字符
*如果相同，则会增加分数
*一旦到达不同的字符，分数将重置
*/
对于（i=0；i最大值）{
最大值=得分列表[位置]；
}
}
/*将分数列表重置回零
*/
而（c<15）{
评分表[c]=0；
C++；
}
printf（“S2：第%d行，分数=%f\n”，第n行，最大值）；
printf（“--\n”）；
}
返回0；
}
读取行while打印行whileline\u lenEOFEOF换行符换行符EOFMAX\u LINEread\u lineSO: query = fall down
---
Down, down, down. Would the fall NEVER come to an end! 'I wonder how
S1: line 1, bytes = 68
Down, down, down. Would the fall NEVER come tDown, down, down. Would the fall NEVER come to an end! 'I wonder how °·) ⌠"" S2: line 1, score = 0.000000
---
many miles I've fallen by this time?' she said aloud. 'I must be getting
S1: line 2, bytes = 72
many miles I've fallen by this time?' shmany miles I've fallen by this time?' she said aloud. 'I must be getting °·) ⌠"" S2: line 2, score = 0.000000
---
int
print_lines(char query [MAX_QUERY]){
int line_num = 0;
int query_len = strlen(query);
int line_len = 0,i,y,z = 0, position,c = 0;
int limit = query_len > line_len ? line_len : query_len;
double score = 0, maximum;
char score_list[15] = "";
char line[MAX_LINE];
while((line_len = read_lines(line)) != EOF){
c = 0;
line_num ++;
printf("S1: line %d, bytes = %d \n",line_num,line_len);
/* Loops through the query and line and compares the characters
* If it is the same, it adds to the score
* Once it gets to different character the score is reset
*/
for (i = 0; i < limit; i++){
for (y = 0; y < limit; y++){
if (query[i] == line[y]){
score++;
}
else if(score != 0 && query[i] != line[y]){
score_list[z] = score;
z++;
}
}
}
/* Finds the largest score in the array
*/
maximum = score_list[0];
for (position = 1; position < 15; position++){
if (score_list[position] > maximum){
maximum = score_list[position];
}
}
/* resets the score list back to zero
*/
while (c < 15){
score_list[c] = 0;
c++;
}
printf("S2: line %d, score = %f\n",line_num,maximum);
printf("---\n");
}
return 0;
}
int query_len = strlen (query);
...
int limit = query_len > line_len ? line_len : query_len;
查询行行int read_lines (char line[MAX_LINE])
{
int line_len = 0;
int c;
while ((c = getchar ()) != '\n' && c != EOF) {
line[line_len] = c;
line_len++;
if (line_len == MAX_LINE - 1) break;
}
line[line_len] = 0;
if (line_len)
printf ("%s\n", line);
return line_len ? line_len : c == EOF ? EOF : line_len;
}
分数的单个循环设置限制。（注意：所有长度int
变量实际上应该是typesize\t
或unsigned
，因为不能有负长度。对于只包含正值的计数器，如循环计数器，也是如此…）
然后，对于实际处理，为了处理最后一行文本的所有情况，您可以将循环重新构造为：
SO: query = fall down
---
Down, down, down. Would the fall NEVER come to an end! 'I wonder how
S1: line 1, bytes = 68
Down, down, down. Would the fall NEVER come tDown, down, down. Would the fall NEVER come to an end! 'I wonder how °·) ⌠"" S2: line 1, score = 0.000000
---
many miles I've fallen by this time?' she said aloud. 'I must be getting
S1: line 2, bytes = 72
many miles I've fallen by this time?' shmany miles I've fallen by this time?' she said aloud. 'I must be getting °·) ⌠"" S2: line 2, score = 0.000000
---
int
print_lines(char query [MAX_QUERY]){
int line_num = 0;
int query_len = strlen(query);
int line_len = 0,i,y,z = 0, position,c = 0;
int limit = query_len > line_len ? line_len : query_len;
double score = 0, maximum;
char score_list[15] = "";
char line[MAX_LINE];
while((line_len = read_lines(line)) != EOF){
c = 0;
line_num ++;
printf("S1: line %d, bytes = %d \n",line_num,line_len);
/* Loops through the query and line and compares the characters
* If it is the same, it adds to the score
* Once it gets to different character the score is reset
*/
for (i = 0; i < limit; i++){
for (y = 0; y < limit; y++){
if (query[i] == line[y]){
score++;
}
else if(score != 0 && query[i] != line[y]){
score_list[z] = score;
z++;
}
}
}
/* Finds the largest score in the array
*/
maximum = score_list[0];
for (position = 1; position < 15; position++){
if (score_list[position] > maximum){
maximum = score_list[position];
}
}
/* resets the score list back to zero
*/
while (c < 15){
score_list[c] = 0;
c++;
}
printf("S2: line %d, score = %f\n",line_num,maximum);
printf("---\n");
}
return 0;
}
int query_len = strlen (query);
...
int limit = query_len > line_len ? line_len : query_len;
这意味着在第一次通过时，score\u列表
被重置，但是对于随后的每一次通过，c
已经是15
，并且该代码从未执行
如果你解决了这些问题，你可能会让你的代码做你想做的。值得一提的是，在编译时，在启用警告的情况下编译。至少-Wall-Wextra
。然后修复所有警告。如果你有任何问题，请尝试一下，让我知道。最大的问题是阅读的设计_行
和while
循环，在打印行
中调用它。不能返回（1）行
，也不能返回（2）EOF
并在while
循环中测试EOF
，因为这两者不是相互排斥的。例如，通常情况下，您的文件在最后一行的文本后面没有换行符。（POSIX规定所有文件都应该有一个结尾换行符
，但许多编辑会很乐意编写没有结尾的文件）。如果出现这种情况，并且您正在循环中测试EOF
，那么您就错过了最后一行文本
此外，如果您在任何地方读取的字符数超过了MAX\u LINE
，则不进行测试。要解决此问题，您可以重新设计read\u LINE
，如下所示：
SO: query = fall down
---
Down, down, down. Would the fall NEVER come to an end! 'I wonder how
S1: line 1, bytes = 68
Down, down, down. Would the fall NEVER come tDown, down, down. Would the fall NEVER come to an end! 'I wonder how °·) ⌠"" S2: line 1, score = 0.000000
---
many miles I've fallen by this time?' she said aloud. 'I must be getting
S1: line 2, bytes = 72
many miles I've fallen by this time?' shmany miles I've fallen by this time?' she said aloud. 'I must be getting °·) ⌠"" S2: line 2, score = 0.000000
---
int
print_lines(char query [MAX_QUERY]){
int line_num = 0;
int query_len = strlen(query);
int line_len = 0,i,y,z = 0, position,c = 0;
int limit = query_len > line_len ? line_len : query_len;
double score = 0, maximum;
char score_list[15] = "";
char line[MAX_LINE];
while((line_len = read_lines(line)) != EOF){
c = 0;
line_num ++;
printf("S1: line %d, bytes = %d \n",line_num,line_len);
/* Loops through the query and line and compares the characters
* If it is the same, it adds to the score
* Once it gets to different character the score is reset
*/
for (i = 0; i < limit; i++){
for (y = 0; y < limit; y++){
if (query[i] == line[y]){
score++;
}
else if(score != 0 && query[i] != line[y]){
score_list[z] = score;
z++;
}
}
}
/* Finds the largest score in the array
*/
maximum = score_list[0];
for (position = 1; position < 15; position++){
if (score_list[position] > maximum){
maximum = score_list[position];
}
}
/* resets the score list back to zero
*/
while (c < 15){
score_list[c] = 0;
c++;
}
printf("S2: line %d, score = %f\n",line_num,maximum);
printf("---\n");
}
return 0;
}
int query_len = strlen (query);
...
int limit = query_len > line_len ? line_len : query_len;
接下来，除了注释中给出的关于使用警告编译的所有好理由外，您还通过完全不带空格或注释的方式使代码无法阅读。您也没有以简洁的方式处理循环限制。如果查询的长度超过行
，则会不断循环在读取行
中的最后一个字符后，不做任何操作。一个简单的：
int read_lines (char line[MAX_LINE])
{
int line_len = 0;
int c;
while ((c = getchar ()) != '\n' && c != EOF) {
line[line_len] = c;
line_len++;
if (line_len == MAX_LINE - 1) break;
}
line[line_len] = 0;
if (line_len)
printf ("%s\n", line);
return line_len ? line_len : c == EOF ? EOF : line_len;
}
将为您可以执行的单个循环设置限制