C 使用sys信号量的输出同步
您的代码中存在一些问题,请参阅代码中的注释以了解说明C 使用sys信号量的输出同步,c,synchronization,mutex,semaphore,shared-memory,C,Synchronization,Mutex,Semaphore,Shared Memory,您的代码中存在一些问题,请参阅代码中的注释以了解说明 void display(char *str) { char *p; for (p=str; *p; p++) { write(1, p, 1); usleep(100); } } 您的代码中存在一些问题,请参阅代码中的注释以了解说明 void display(char *str) { char *p; for (p=str; *p; p++) { write(1, p, 1);
void display(char *str)
{
char *p;
for (p=str; *p; p++)
{
write(1, p, 1);
usleep(100);
}
}
您的代码中存在一些问题,请参阅代码中的注释以了解说明
void display(char *str)
{
char *p;
for (p=str; *p; p++)
{
write(1, p, 1);
usleep(100);
}
}
int main()
{
int i;
struct sembuf up = {0,1,0};
struct sembuf down = {0,-1,0};
int sem0 = semget(IPC_PRIVATE,1,0600);
int sem1 = semget(IPC_PRIVATE,1,0600);
if (fork())
{
for (i=0;i<10;i++)
{
display("ab");
semop(sem1,&up,1);
semop(sem0,&down,1);
//wait(NULL); //MAYUR: wait() suspends the execution until one of its children terminates. But this was unnecessary here. I removed it.
} //MAYUR: There was no brackets for "for loop". Added it in both the blocks.
}
else
{
for (i=0;i<10;i++)
{
semop(sem1,&down,1);
display("cd\n");
semop(sem0,&up,1);
//semop(sem1,&down,1); //MAYUR: You are doing wait for sem1 in two places. This is was leading to deadlock. Removed it.
}
}
semctl(sem0,0,IPC_RMID);
semctl(sem1,0,IPC_RMID);
return 0;
}
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