C 针对小输入优化SHA-1
我希望为8位MCU(基于8051)优化SHA-1的实现。输入数据只有8字节,因此我想知道是否可以采取措施来改进此宏:C 针对小输入优化SHA-1,c,encryption,cryptography,sha,8051,C,Encryption,Cryptography,Sha,8051,我希望为8位MCU(基于8051)优化SHA-1的实现。输入数据只有8字节,因此我想知道是否可以采取措施来改进此宏: #define S(x,n) ((x << n) | ((x & 0xFFFFFFFF) >> (32 - n))) 致: 致: 以下是完整的代码: #include <string.h> #include "sha1.h" #define GET_UINT32(n,b,i) \ {
#define S(x,n) ((x << n) | ((x & 0xFFFFFFFF) >> (32 - n)))
致:
致:
以下是完整的代码:
#include <string.h>
#include "sha1.h"
#define GET_UINT32(n,b,i) \
{ \
(n) = ( (uint32) (b)[(i) ] << 24 ) \
| ( (uint32) (b)[(i) + 1] << 16 ) \
| ( (uint32) (b)[(i) + 2] << 8 ) \
| ( (uint32) (b)[(i) + 3] ); \
}
#define PUT_UINT32(n,b,i) \
{ \
(b)[(i) ] = (uint8) ( (n) >> 24 ); \
(b)[(i) + 1] = (uint8) ( (n) >> 16 ); \
(b)[(i) + 2] = (uint8) ( (n) >> 8 ); \
(b)[(i) + 3] = (uint8) ( (n) ); \
}
void sha1_starts( sha1_context *ctx )
{
ctx->total[0] = 0;
ctx->total[1] = 0;
ctx->state[0] = 0x67452301;
ctx->state[1] = 0xEFCDAB89;
ctx->state[2] = 0x98BADCFE;
ctx->state[3] = 0x10325476;
ctx->state[4] = 0xC3D2E1F0;
}
void sha1_process( sha1_context *ctx, uint8 data[64] )
{
uint32 temp, W[16], A, B, C, D, E;
GET_UINT32( W[0], data, 0 );
GET_UINT32( W[1], data, 4 );
GET_UINT32( W[2], data, 8 );
GET_UINT32( W[3], data, 12 );
GET_UINT32( W[4], data, 16 );
GET_UINT32( W[5], data, 20 );
GET_UINT32( W[6], data, 24 );
GET_UINT32( W[7], data, 28 );
GET_UINT32( W[8], data, 32 );
GET_UINT32( W[9], data, 36 );
GET_UINT32( W[10], data, 40 );
GET_UINT32( W[11], data, 44 );
GET_UINT32( W[12], data, 48 );
GET_UINT32( W[13], data, 52 );
GET_UINT32( W[14], data, 56 );
GET_UINT32( W[15], data, 60 );
#define S(x,n) ((x << n) | ((x & 0xFFFFFFFF) >> (32 - n)))
#define R(t) \
( \
temp = W[(t - 3) & 0x0F] ^ W[(t - 8) & 0x0F] ^ \
W[(t - 14) & 0x0F] ^ W[ t & 0x0F], \
( W[t & 0x0F] = S(temp,1) ) \
)
#define P(a,b,c,d,e,x) \
{ \
e += S(a,5) + F(b,c,d) + K + x; b = S(b,30); \
}
A = ctx->state[0];
B = ctx->state[1];
C = ctx->state[2];
D = ctx->state[3];
E = ctx->state[4];
#define F(x,y,z) (z ^ (x & (y ^ z)))
#define K 0x5A827999
P( A, B, C, D, E, W[0] );
P( E, A, B, C, D, W[1] );
P( D, E, A, B, C, W[2] );
P( C, D, E, A, B, W[3] );
P( B, C, D, E, A, W[4] );
P( A, B, C, D, E, W[5] );
P( E, A, B, C, D, W[6] );
P( D, E, A, B, C, W[7] );
P( C, D, E, A, B, W[8] );
P( B, C, D, E, A, W[9] );
P( A, B, C, D, E, W[10] );
P( E, A, B, C, D, W[11] );
P( D, E, A, B, C, W[12] );
P( C, D, E, A, B, W[13] );
P( B, C, D, E, A, W[14] );
P( A, B, C, D, E, W[15] );
P( E, A, B, C, D, R(16) );
P( D, E, A, B, C, R(17) );
P( C, D, E, A, B, R(18) );
P( B, C, D, E, A, R(19) );
#undef K
#undef F
#define F(x,y,z) (x ^ y ^ z)
#define K 0x6ED9EBA1
P( A, B, C, D, E, R(20) );
P( E, A, B, C, D, R(21) );
P( D, E, A, B, C, R(22) );
P( C, D, E, A, B, R(23) );
P( B, C, D, E, A, R(24) );
P( A, B, C, D, E, R(25) );
P( E, A, B, C, D, R(26) );
P( D, E, A, B, C, R(27) );
P( C, D, E, A, B, R(28) );
P( B, C, D, E, A, R(29) );
P( A, B, C, D, E, R(30) );
P( E, A, B, C, D, R(31) );
P( D, E, A, B, C, R(32) );
P( C, D, E, A, B, R(33) );
P( B, C, D, E, A, R(34) );
P( A, B, C, D, E, R(35) );
P( E, A, B, C, D, R(36) );
P( D, E, A, B, C, R(37) );
P( C, D, E, A, B, R(38) );
P( B, C, D, E, A, R(39) );
#undef K
#undef F
#define F(x,y,z) ((x & y) | (z & (x | y)))
#define K 0x8F1BBCDC
P( A, B, C, D, E, R(40) );
P( E, A, B, C, D, R(41) );
P( D, E, A, B, C, R(42) );
P( C, D, E, A, B, R(43) );
P( B, C, D, E, A, R(44) );
P( A, B, C, D, E, R(45) );
P( E, A, B, C, D, R(46) );
P( D, E, A, B, C, R(47) );
P( C, D, E, A, B, R(48) );
P( B, C, D, E, A, R(49) );
P( A, B, C, D, E, R(50) );
P( E, A, B, C, D, R(51) );
P( D, E, A, B, C, R(52) );
P( C, D, E, A, B, R(53) );
P( B, C, D, E, A, R(54) );
P( A, B, C, D, E, R(55) );
P( E, A, B, C, D, R(56) );
P( D, E, A, B, C, R(57) );
P( C, D, E, A, B, R(58) );
P( B, C, D, E, A, R(59) );
#undef K
#undef F
#define F(x,y,z) (x ^ y ^ z)
#define K 0xCA62C1D6
P( A, B, C, D, E, R(60) );
P( E, A, B, C, D, R(61) );
P( D, E, A, B, C, R(62) );
P( C, D, E, A, B, R(63) );
P( B, C, D, E, A, R(64) );
P( A, B, C, D, E, R(65) );
P( E, A, B, C, D, R(66) );
P( D, E, A, B, C, R(67) );
P( C, D, E, A, B, R(68) );
P( B, C, D, E, A, R(69) );
P( A, B, C, D, E, R(70) );
P( E, A, B, C, D, R(71) );
P( D, E, A, B, C, R(72) );
P( C, D, E, A, B, R(73) );
P( B, C, D, E, A, R(74) );
P( A, B, C, D, E, R(75) );
P( E, A, B, C, D, R(76) );
P( D, E, A, B, C, R(77) );
P( C, D, E, A, B, R(78) );
P( B, C, D, E, A, R(79) );
#undef K
#undef F
ctx->state[0] += A;
ctx->state[1] += B;
ctx->state[2] += C;
ctx->state[3] += D;
ctx->state[4] += E;
}
void sha1_update( sha1_context *ctx, uint8 *input, uint32 length )
{
uint32 left, fill;
if( ! length ) return;
left = ctx->total[0] & 0x3F;
fill = 64 - left;
ctx->total[0] += length;
ctx->total[0] &= 0xFFFFFFFF;
if( ctx->total[0] < length )
ctx->total[1]++;
if( left && length >= fill )
{
memcpy( (void *) (ctx->buffer + left),
(void *) input, fill );
sha1_process( ctx, ctx->buffer );
length -= fill;
input += fill;
left = 0;
}
while( length >= 64 )
{
sha1_process( ctx, input );
length -= 64;
input += 64;
}
if( length )
{
memcpy( (void *) (ctx->buffer + left),
(void *) input, length );
}
}
static uint8 sha1_padding[64] =
{
0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
};
void sha1_finish( sha1_context *ctx, uint8 digest[20] )
{
uint32 last, padn;
uint32 high, low;
uint8 msglen[8];
high = ( ctx->total[0] >> 29 )
| ( ctx->total[1] << 3 );
low = ( ctx->total[0] << 3 );
PUT_UINT32( high, msglen, 0 );
PUT_UINT32( low, msglen, 4 );
last = ctx->total[0] & 0x3F;
padn = ( last < 56 ) ? ( 56 - last ) : ( 120 - last );
sha1_update( ctx, sha1_padding, padn );
sha1_update( ctx, msglen, 8 );
PUT_UINT32( ctx->state[0], digest, 0 );
PUT_UINT32( ctx->state[1], digest, 4 );
PUT_UINT32( ctx->state[2], digest, 8 );
PUT_UINT32( ctx->state[3], digest, 12 );
PUT_UINT32( ctx->state[4], digest, 16 );
}
#ifdef TEST
#include <stdlib.h>
#include <stdio.h>
/*
* those are the standard FIPS-180-1 test vectors
*/
static char *msg[] =
{
"abc",
"abcdbcdecdefdefgefghfghighijhijkijkljklmklmnlmnomnopnopq",
NULL
};
static char *val[] =
{
"a9993e364706816aba3e25717850c26c9cd0d89d",
"84983e441c3bd26ebaae4aa1f95129e5e54670f1",
"34aa973cd4c4daa4f61eeb2bdbad27316534016f"
};
int main( int argc, char *argv[] )
{
FILE *f;
int i, j;
char output[41];
sha1_context ctx;
unsigned char buf[1000];
unsigned char sha1sum[20];
if( argc < 2 )
{
printf( "\n SHA-1 Validation Tests:\n\n" );
for( i = 0; i < 3; i++ )
{
printf( " Test %d ", i + 1 );
sha1_starts( &ctx );
if( i < 2 )
{
sha1_update( &ctx, (uint8 *) msg[i],
strlen( msg[i] ) );
}
else
{
memset( buf, 'a', 1000 );
for( j = 0; j < 1000; j++ )
{
sha1_update( &ctx, (uint8 *) buf, 1000 );
}
}
sha1_finish( &ctx, sha1sum );
for( j = 0; j < 20; j++ )
{
sprintf( output + j * 2, "%02x", sha1sum[j] );
}
if( memcmp( output, val[i], 40 ) )
{
printf( "failed!\n" );
return( 1 );
}
printf( "passed.\n" );
}
printf( "\n" );
}
else
{
if( ! ( f = fopen( argv[1], "rb" ) ) )
{
perror( "fopen" );
return( 1 );
}
sha1_starts( &ctx );
while( ( i = fread( buf, 1, sizeof( buf ), f ) ) > 0 )
{
sha1_update( &ctx, buf, i );
}
sha1_finish( &ctx, sha1sum );
for( j = 0; j < 20; j++ )
{
printf( "%02x", sha1sum[j] );
}
printf( " %s\n", argv[1] );
}
return( 0 );
}
#endif
谢谢听起来您的实际需求是找到一种在硬件上计算8字节输入的廉价MAC/PRF 由于您的数据具有固定长度,因此可以使用安全分组密码(具有128位块)作为密码。由于您的数据短于一个数据块,CBC-MAC简化为使用原始分组密码/ECB模式加密数据 如果128位分组密码的每字节成本与SHA-1相似,则与HMAC-SHA-1相比,这将导致8倍的加速(SHA-1有512位块,需要为HMAC散列两个块)。如果您选择一种特别适合您的CPU的密码,则加速比可能会更大 由于AES非常流行,为8位CPU优化的实现应该不会太难 如果我是正确的,
S(x,n)
期望x
成为uint32
。考虑到输入量非常小,是否可以通过减小x
来减少移位数,例如uint8
否。SHA1函数的状态由五个32位值组成,每个迭代都会更改,这些值是S(x,n)
正在操作的值。将这些值转换为8位值将得到一个完全不同的(可能是非常糟糕的)散列函数
MD5/SHA系列散列函数都严重依赖于32位整数运算。在8位处理器(如8051)上易于实现并不是这些功能的设计目标,在这些部件上的实现不会表现得特别好。很抱歉您需要适应缓慢的速度,使用另一个微处理器(或具有SHA1硬件加速的微处理器!),或者使用不同的哈希算法。是的,对于8位MCU,您建议使用字节处理将产生更好的性能。我的想法是,32位处理(在当前代码中)用于捕获32位处理器(寄存器大小为32位)算法的优化性能。(x&0xFFFFFFFF)在这里,并且在宏中不需要操作(因为x仅为32位)。简单的x可以直接使用。对。你的意思是如果x是uint8,那么AND操作就没有必要了吗?为什么?32位case->(x&0xFFFFFFFF),其中x是32位数据,8位case->(x&0xFF),其中x是8位数据,在所有情况下,都是用所有1完成的,所以结果是原始数字x本身,所以AND运算无关紧要。是的,在另一种情况下,比如,x是32位,并且是从这个32位数据中屏蔽8位/16位,那么,它是有意义的。例如,在发布的代码中,是否有可能使用x作为64位数据调用S(x,n)?我不完全确定
S(x,n)
中的x
应该表示什么,因为x
可能是a
,B
,C
,等等,这取决于W
的索引。如果保证输入为8字节或更少,则可以A
,B
,C
<代码>W[]全部是8位长的吗?我确实研究了CBC-MAC,但我找不到8位处理器的实现-这就是为什么我开始研究SHA-1。你知道8位CBC-MAC的实现吗?@Kar如果你有AES实现,在其上实现CBC-MAC很简单。只需对块进行一位异或运算,调用AES,最后进行恒定时间比较。
#define S(x,n) ((x << n) | ((x & 0xFF) >> (8 - n)))
void sha1_process( sha1_context *ctx, uint8 data[64] )
{
uint32 temp, W[16], A, B, C, D, E;
// ...
void sha1_process( sha1_context *ctx, uint8 data[64] )
{
uint8 temp, W[16], A, B, C, D, E;
// ...
#include <string.h>
#include "sha1.h"
#define GET_UINT32(n,b,i) \
{ \
(n) = ( (uint32) (b)[(i) ] << 24 ) \
| ( (uint32) (b)[(i) + 1] << 16 ) \
| ( (uint32) (b)[(i) + 2] << 8 ) \
| ( (uint32) (b)[(i) + 3] ); \
}
#define PUT_UINT32(n,b,i) \
{ \
(b)[(i) ] = (uint8) ( (n) >> 24 ); \
(b)[(i) + 1] = (uint8) ( (n) >> 16 ); \
(b)[(i) + 2] = (uint8) ( (n) >> 8 ); \
(b)[(i) + 3] = (uint8) ( (n) ); \
}
void sha1_starts( sha1_context *ctx )
{
ctx->total[0] = 0;
ctx->total[1] = 0;
ctx->state[0] = 0x67452301;
ctx->state[1] = 0xEFCDAB89;
ctx->state[2] = 0x98BADCFE;
ctx->state[3] = 0x10325476;
ctx->state[4] = 0xC3D2E1F0;
}
void sha1_process( sha1_context *ctx, uint8 data[64] )
{
uint32 temp, W[16], A, B, C, D, E;
GET_UINT32( W[0], data, 0 );
GET_UINT32( W[1], data, 4 );
GET_UINT32( W[2], data, 8 );
GET_UINT32( W[3], data, 12 );
GET_UINT32( W[4], data, 16 );
GET_UINT32( W[5], data, 20 );
GET_UINT32( W[6], data, 24 );
GET_UINT32( W[7], data, 28 );
GET_UINT32( W[8], data, 32 );
GET_UINT32( W[9], data, 36 );
GET_UINT32( W[10], data, 40 );
GET_UINT32( W[11], data, 44 );
GET_UINT32( W[12], data, 48 );
GET_UINT32( W[13], data, 52 );
GET_UINT32( W[14], data, 56 );
GET_UINT32( W[15], data, 60 );
#define S(x,n) ((x << n) | ((x & 0xFFFFFFFF) >> (32 - n)))
#define R(t) \
( \
temp = W[(t - 3) & 0x0F] ^ W[(t - 8) & 0x0F] ^ \
W[(t - 14) & 0x0F] ^ W[ t & 0x0F], \
( W[t & 0x0F] = S(temp,1) ) \
)
#define P(a,b,c,d,e,x) \
{ \
e += S(a,5) + F(b,c,d) + K + x; b = S(b,30); \
}
A = ctx->state[0];
B = ctx->state[1];
C = ctx->state[2];
D = ctx->state[3];
E = ctx->state[4];
#define F(x,y,z) (z ^ (x & (y ^ z)))
#define K 0x5A827999
P( A, B, C, D, E, W[0] );
P( E, A, B, C, D, W[1] );
P( D, E, A, B, C, W[2] );
P( C, D, E, A, B, W[3] );
P( B, C, D, E, A, W[4] );
P( A, B, C, D, E, W[5] );
P( E, A, B, C, D, W[6] );
P( D, E, A, B, C, W[7] );
P( C, D, E, A, B, W[8] );
P( B, C, D, E, A, W[9] );
P( A, B, C, D, E, W[10] );
P( E, A, B, C, D, W[11] );
P( D, E, A, B, C, W[12] );
P( C, D, E, A, B, W[13] );
P( B, C, D, E, A, W[14] );
P( A, B, C, D, E, W[15] );
P( E, A, B, C, D, R(16) );
P( D, E, A, B, C, R(17) );
P( C, D, E, A, B, R(18) );
P( B, C, D, E, A, R(19) );
#undef K
#undef F
#define F(x,y,z) (x ^ y ^ z)
#define K 0x6ED9EBA1
P( A, B, C, D, E, R(20) );
P( E, A, B, C, D, R(21) );
P( D, E, A, B, C, R(22) );
P( C, D, E, A, B, R(23) );
P( B, C, D, E, A, R(24) );
P( A, B, C, D, E, R(25) );
P( E, A, B, C, D, R(26) );
P( D, E, A, B, C, R(27) );
P( C, D, E, A, B, R(28) );
P( B, C, D, E, A, R(29) );
P( A, B, C, D, E, R(30) );
P( E, A, B, C, D, R(31) );
P( D, E, A, B, C, R(32) );
P( C, D, E, A, B, R(33) );
P( B, C, D, E, A, R(34) );
P( A, B, C, D, E, R(35) );
P( E, A, B, C, D, R(36) );
P( D, E, A, B, C, R(37) );
P( C, D, E, A, B, R(38) );
P( B, C, D, E, A, R(39) );
#undef K
#undef F
#define F(x,y,z) ((x & y) | (z & (x | y)))
#define K 0x8F1BBCDC
P( A, B, C, D, E, R(40) );
P( E, A, B, C, D, R(41) );
P( D, E, A, B, C, R(42) );
P( C, D, E, A, B, R(43) );
P( B, C, D, E, A, R(44) );
P( A, B, C, D, E, R(45) );
P( E, A, B, C, D, R(46) );
P( D, E, A, B, C, R(47) );
P( C, D, E, A, B, R(48) );
P( B, C, D, E, A, R(49) );
P( A, B, C, D, E, R(50) );
P( E, A, B, C, D, R(51) );
P( D, E, A, B, C, R(52) );
P( C, D, E, A, B, R(53) );
P( B, C, D, E, A, R(54) );
P( A, B, C, D, E, R(55) );
P( E, A, B, C, D, R(56) );
P( D, E, A, B, C, R(57) );
P( C, D, E, A, B, R(58) );
P( B, C, D, E, A, R(59) );
#undef K
#undef F
#define F(x,y,z) (x ^ y ^ z)
#define K 0xCA62C1D6
P( A, B, C, D, E, R(60) );
P( E, A, B, C, D, R(61) );
P( D, E, A, B, C, R(62) );
P( C, D, E, A, B, R(63) );
P( B, C, D, E, A, R(64) );
P( A, B, C, D, E, R(65) );
P( E, A, B, C, D, R(66) );
P( D, E, A, B, C, R(67) );
P( C, D, E, A, B, R(68) );
P( B, C, D, E, A, R(69) );
P( A, B, C, D, E, R(70) );
P( E, A, B, C, D, R(71) );
P( D, E, A, B, C, R(72) );
P( C, D, E, A, B, R(73) );
P( B, C, D, E, A, R(74) );
P( A, B, C, D, E, R(75) );
P( E, A, B, C, D, R(76) );
P( D, E, A, B, C, R(77) );
P( C, D, E, A, B, R(78) );
P( B, C, D, E, A, R(79) );
#undef K
#undef F
ctx->state[0] += A;
ctx->state[1] += B;
ctx->state[2] += C;
ctx->state[3] += D;
ctx->state[4] += E;
}
void sha1_update( sha1_context *ctx, uint8 *input, uint32 length )
{
uint32 left, fill;
if( ! length ) return;
left = ctx->total[0] & 0x3F;
fill = 64 - left;
ctx->total[0] += length;
ctx->total[0] &= 0xFFFFFFFF;
if( ctx->total[0] < length )
ctx->total[1]++;
if( left && length >= fill )
{
memcpy( (void *) (ctx->buffer + left),
(void *) input, fill );
sha1_process( ctx, ctx->buffer );
length -= fill;
input += fill;
left = 0;
}
while( length >= 64 )
{
sha1_process( ctx, input );
length -= 64;
input += 64;
}
if( length )
{
memcpy( (void *) (ctx->buffer + left),
(void *) input, length );
}
}
static uint8 sha1_padding[64] =
{
0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
};
void sha1_finish( sha1_context *ctx, uint8 digest[20] )
{
uint32 last, padn;
uint32 high, low;
uint8 msglen[8];
high = ( ctx->total[0] >> 29 )
| ( ctx->total[1] << 3 );
low = ( ctx->total[0] << 3 );
PUT_UINT32( high, msglen, 0 );
PUT_UINT32( low, msglen, 4 );
last = ctx->total[0] & 0x3F;
padn = ( last < 56 ) ? ( 56 - last ) : ( 120 - last );
sha1_update( ctx, sha1_padding, padn );
sha1_update( ctx, msglen, 8 );
PUT_UINT32( ctx->state[0], digest, 0 );
PUT_UINT32( ctx->state[1], digest, 4 );
PUT_UINT32( ctx->state[2], digest, 8 );
PUT_UINT32( ctx->state[3], digest, 12 );
PUT_UINT32( ctx->state[4], digest, 16 );
}
#ifdef TEST
#include <stdlib.h>
#include <stdio.h>
/*
* those are the standard FIPS-180-1 test vectors
*/
static char *msg[] =
{
"abc",
"abcdbcdecdefdefgefghfghighijhijkijkljklmklmnlmnomnopnopq",
NULL
};
static char *val[] =
{
"a9993e364706816aba3e25717850c26c9cd0d89d",
"84983e441c3bd26ebaae4aa1f95129e5e54670f1",
"34aa973cd4c4daa4f61eeb2bdbad27316534016f"
};
int main( int argc, char *argv[] )
{
FILE *f;
int i, j;
char output[41];
sha1_context ctx;
unsigned char buf[1000];
unsigned char sha1sum[20];
if( argc < 2 )
{
printf( "\n SHA-1 Validation Tests:\n\n" );
for( i = 0; i < 3; i++ )
{
printf( " Test %d ", i + 1 );
sha1_starts( &ctx );
if( i < 2 )
{
sha1_update( &ctx, (uint8 *) msg[i],
strlen( msg[i] ) );
}
else
{
memset( buf, 'a', 1000 );
for( j = 0; j < 1000; j++ )
{
sha1_update( &ctx, (uint8 *) buf, 1000 );
}
}
sha1_finish( &ctx, sha1sum );
for( j = 0; j < 20; j++ )
{
sprintf( output + j * 2, "%02x", sha1sum[j] );
}
if( memcmp( output, val[i], 40 ) )
{
printf( "failed!\n" );
return( 1 );
}
printf( "passed.\n" );
}
printf( "\n" );
}
else
{
if( ! ( f = fopen( argv[1], "rb" ) ) )
{
perror( "fopen" );
return( 1 );
}
sha1_starts( &ctx );
while( ( i = fread( buf, 1, sizeof( buf ), f ) ) > 0 )
{
sha1_update( &ctx, buf, i );
}
sha1_finish( &ctx, sha1sum );
for( j = 0; j < 20; j++ )
{
printf( "%02x", sha1sum[j] );
}
printf( " %s\n", argv[1] );
}
return( 0 );
}
#endif
0031D0 85 18 82 MOV DPL,XSP(L)
0031D3 85 19 83 MOV DPH,XSP(H)
0031D6 78 08 MOV R0,#0x08
0031D8 12 17 85 LCALL ?L_MOV_X
0031DB 74 1E MOV A,#0x1E
0031DD 78 08 MOV R0,#0x08
0031DF 12 16 80 LCALL ?L_SHL
0031E2 85 18 82 MOV DPL,XSP(L)
0031E5 85 19 83 MOV DPH,XSP(H)
0031E8 78 10 MOV R0,#0x10
0031EA 12 17 85 LCALL ?L_MOV_X
0031ED 74 02 MOV A,#0x02
0031EF 78 10 MOV R0,#0x10
0031F1 12 16 67 LCALL ?UL_SHR
0031F4 78 08 MOV R0,#0x08
0031F6 79 10 MOV R1,#0x10
0031F8 12 17 39 LCALL ?L_IOR
0031FB 85 18 82 MOV DPL,XSP(L)
0031FE 85 19 83 MOV DPH,XSP(H)
003201 78 08 MOV R0,#0x08
003203 12 17 94 LCALL ?L_MOV_TO_X