C 我收到信号灯的警告
所以我在这个项目上工作了一整天,我检查了我的错误,当我修复它们的时候,我来到了最后一部分,那就是警告 我得到的警告是相同的:从兼容指针类型[默认情况下已启用]传递“”的参数1 注意:应为“union sem_t*”,但参数的类型为“void*()(void)” 请帮帮我。我已经在这个问题上纠缠了好几个小时了。提前谢谢 我在顾客和理发店都从sem_init上取下了&但它不起作用C 我收到信号灯的警告,c,linux,operating-system,pthreads,C,Linux,Operating System,Pthreads,所以我在这个项目上工作了一整天,我检查了我的错误,当我修复它们的时候,我来到了最后一部分,那就是警告 我得到的警告是相同的:从兼容指针类型[默认情况下已启用]传递“”的参数1 注意:应为“union sem_t*”,但参数的类型为“void*()(void)” 请帮帮我。我已经在这个问题上纠缠了好几个小时了。提前谢谢 我在顾客和理发店都从sem_init上取下了&但它不起作用 #include <unistd.h> //Provides API for POSIX(or UN
#include <unistd.h> //Provides API for POSIX(or UNIX) OS for system calls
#include <stdio.h> //Standard I/O Routines
#include <stdlib.h> //For exit() and rand()
#include <pthread.h> //Threading APIs
#include <semaphore.h> //Semaphore APIs
#define MAX 30 //Maximum no. of customers for simulation
#define MAX_BARBERS 1000
sem_t customer; //Semaphore
sem_t barber; //Semaphore
sem_t mutex; //Semaphore for providing mutially exclusive access
void *barbers(void *param); //Thread Function
void *customers(void *param); //Thread Function
int num_chairs;
int barbers_total;
int customers_total;
int serveMeNext; //Index to choose a candidate for cutting hair
void wait(); //Randomized delay function
int main(int argc, char *argv[]){
pthread_t barberid[MAX_BARBERS];
pthread_t customerid[MAX]; //Thread declaration
int i = 0;
if(argc != 4){
printf("Enter 3 arguments (Number of chairs, barbers, customers)\n");
exit(0);
}
num_chairs = atoi(argv[1]);
barbers_total = atoi(argv[2]);
customers_total = atoi(argv[3]);
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/*Semaphore initialization*/
sem_init(&mutex,0,1);
sem_init(customers,0,0);
sem_init(barbers,0,0);
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/*Barber thread initialization*/
printf("!!Barber Shop Opens!!\n");
for(i = 0; i <= barbers_total; i++){ //Creation of barbers
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pthread_create(&barberid[i], NULL, barbers, (void*)&i);
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sleep(1);
}
/*Customer thread initialization*/
for(i = 0; i <= customers_total; i++){ //Creation of Customer Threads
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pthread_create(&customerid[i],NULL,customers,(void*)&i);
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wait(); //Create customers in random interval
}
for(i = 0; i <= MAX; i++) //Waiting till all customers are dealt with
pthread_join(customerid[i],NULL);
printf("!!Barber Shop Closes!!\n");
exit(EXIT_SUCCESS); //Exit abandoning infinite loop of barber thread
}
void *customers(void *param){ /*Customer Process*/
int mySeat, B;
static int count = 0; //Counter of No. of customers
int numberOfFreeSeats = num_chairs; //Counter for Vacant seats in waiting room
int seatPocket[num_chairs]; //To exchange pid between customer and barber
int sitHereNext = 0; //Index for next legitimate seat
serveMeNext = 0;
sem_wait(&mutex); //Lock mutex to protect seat changes
count++; //Arrival of customer
printf("Customer-%d entered shop. ",count);
if(numberOfFreeSeats > 0){
--numberOfFreeSeats; //Sit on chairs on waiting room
printf("Customer-%d Sits In Waiting Room.\n",count);
sitHereNext = (++sitHereNext) % num_chairs; //Choose a vacant chair to sit
mySeat = sitHereNext;
seatPocket[mySeat] = count;
sem_post(&mutex); //Release the seat change mutex
sem_post(barbers); //Wake up one barber
sem_wait(customers); //Join queue of sleeping customers
sem_wait(&mutex); //Lock mutex to protect seat changes
B = seatPocket[mySeat]; //Barber replaces customer PID with his own PID
numberOfFreeSeats++; //Stand Up and Go to Barber Room
sem_post(&mutex); //Release the seat change mutex
/*Customer is having hair cut by barber 'B'*/
}else{
sem_post(&mutex); //Release the mutex and customer leaves without haircut
printf("Customer-%d Finds No Seat & Leaves.\n",count);
}
pthread_exit(0);
}
void *barbers(void *param){ /*Barber Process*/
int index = *(int *)(param);
int myNext, C;
int worktime;
int seatPocket[num_chairs]; //To exchange pid between customer and barber
printf("Barber-%d joins shop. ",index);
while(1){ /*Infinite loop*/
printf("Barber-%d Gone To Sleep.\n",index);
sem_wait(barbers); //Join queue of sleeping barbers
sem_wait(&mutex); //Lock mutex to protect seat changes
serveMeNext = (++serveMeNext) % MAX; //Select next customermyNext = serveMeNext;
C = seatPocket[myNext]; //Get selected customer's PID
seatPocket[myNext] = pthread_self(); //Leave own PID for customer
sem_post(&mutex);
sem_post(customers); //Call selected customer
/*Barber is cutting hair of customer 'C'*/
printf("Barber-%d Wakes Up & Is Cutting Hair Of Customer-%d.\n",index,C);
worktime = (rand() % 3) + 1;
printf("Barber-%d Finished.\n",index);
sleep(worktime);
}
}
void wait(){ /*Generates random number between 50000 to 250000*/
int x = rand() % (250000 - 50000 + 1) + 50000;
srand(time(NULL));
usleep(x); //usleep halts execution in specified miliseconds
}
#include//为POSIX(或UNIX)操作系统提供用于系统调用的API
#包括//标准I/O例程
#包含//用于exit()和rand()的值
#包括//线程API
#include//信号量api
#定义最多30//模拟的最大客户数
#定义最大理发师1000人
扫描客户//信号量
理发师//信号量
sem_t互斥体//提供多排他访问的信号量
void*理发师(void*param)//线程函数
作废*客户(作废*参数)//线程函数
int num_椅子;
国际理发师总人数;
国际客户总数;
int servementext//选择剪发候选对象的索引
无效等待()//随机延迟函数
int main(int argc,char*argv[]){
pthread_t barberid[MAX_BARBERS];
pthread_t customerid[MAX];//线程声明
int i=0;
如果(argc!=4){
printf(“输入3个参数(椅子、理发师、客户的数量)\n”);
出口(0);
}
num_chairs=atoi(argv[1]);
barbers_total=atoi(argv[2]);
客户总数=atoi(argv[3]);
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/*信号量初始化*/
sem_init(&mutex,0,1);
sem_init(客户,0,0);
sem_init(barbers,0,0);
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/*理发线程初始化*/
printf(“理发店开门!!\n”);
对于警告中的(i=0;i),很明显您传递的是指向函数的指针,而不是它所期望的sem\t
类型
您似乎对customer
和barber
有输入错误
sem_init
必须
sem_init(&customer,0,0);
sem_init(&barber,0,0);
sem_post(&customer);
sem_post(&barber);
您的sem_post
必须
sem_init(&customer,0,0);
sem_init(&barber,0,0);
sem_post(&customer);
sem_post(&barber);
另外,不要忘记使用-lpthread
或-pthread
编译此文件。从警告中可以看出,您传递的是指向函数的指针,而不是它所期望的sem\t
类型
您似乎对customer
和barber
有输入错误
sem_init
必须
sem_init(&customer,0,0);
sem_init(&barber,0,0);
sem_post(&customer);
sem_post(&barber);
您的sem_post
必须
sem_init(&customer,0,0);
sem_init(&barber,0,0);
sem_post(&customer);
sem_post(&barber);
另外,不要忘了用-lpthread
或-pthreadcustomer
vscustomers
barber
vsbarbers
扫描互斥体;
现在,考虑到互斥体是一种实际的对象类型,这很容易混淆…等等(2)
恰好是系统调用的名称。可能您有一些与此事实相关的未定义行为。我不打算投票结束此问题,但您需要尝试在您的C项目中不使用标准库函数名,主要是在它们与线程相关的情况下。您需要发布一个完整、最小且可验证的程序am,不是代码片段。请阅读并编辑您的问题,或重新发帖。另外,exit(2)
是另一个系统调用,它会结束您的整个程序,而不仅仅是您正在运行的线程。因此,请使用pthread\u exit()
和/或pthread\u join()
来同步线程终止。不要使用exit(2)customer
vscustomers
barber
vsbarbers
扫描互斥体;
鉴于互斥体是一种实际的对象类型,现在这很令人困惑…wait(2)
恰好是系统调用的名称。可能您有一些与此事实相关的未定义行为。我不打算投票结束此问题,但您需要尝试在您的C项目中不使用标准库函数名,主要是在它们与线程相关的情况下。您需要发布一个完整、最小且可验证的程序am,不是代码片段。请阅读并编辑您的问题,或重新发帖。另外,exit(2)
是另一个系统调用,它会结束您的整个程序,而不仅仅是您正在运行的线程。因此,请使用pthread\u exit()
和/或pthread\u join()
来同步线程终止。不要使用exit(2)
在线程中终止它。