Cakephp 3.0 使用ORM在辅助键上连接CakePHP 3

CakePHP3.5.13-使用遗留数据库。我有一个名为

substances

的表，其中主键是

id

。此表中还有另一列名为

app\u id

应用程序中的大多数表都有外键，这意味着它们可以连接到

substances.id

。有一个名为

article_95

的表，它有一个字段

article_95.app_id

，因此必须连接到

物质.app_id

（不是

物质.id

-在

article_95

表中根本没有对该字段的引用）

应用程序基于多达11个输入执行搜索。我正在使用ORM在执行查询对象之前动态构建它

我的问题是这样开始的：

$query = $Substances->find()->select(['id' => 'Substances.id'])->distinct();

// Search by CAS Number
if ($this->request->getData('cas_number')) {
    $cas_number = $this->request->getData('cas_number');
    $query = $query->matching('Cas', function ($q) use ($cas_number) {
        return $q->where([
            'Cas.value LIKE' => '%'.$cas_number.'%'
        ]);
    });
}

'SELECT DISTINCT Substances.id AS `id` FROM substances Substances INNER JOIN cas_substances CasSubstances ON Substances.id = (CasSubstances.substance_id) INNER JOIN cas Cas ON (Cas.value like :c0 AND Cas.id = (CasSubstances.cas_id))'

'SELECT DISTINCT Substances.id AS `id` FROM substances Substances INNER JOIN cas_substances CasSubstances ON Substances.id = (CasSubstances.substance_id) INNER JOIN cas Cas ON (Cas.value like :c0 AND Cas.id = (CasSubstances.cas_id)) INNER JOIN article_95 Article95s ON (Article95s.entity_name like :c1 AND Substances.id = (Article95s.app_id))'

然后，如果我想在join映射到

substances.id

的地方做一些事情，我会这样做：

$query = $Substances->find()->select(['id' => 'Substances.id'])->distinct();

// Search by CAS Number
if ($this->request->getData('cas_number')) {
    $cas_number = $this->request->getData('cas_number');
    $query = $query->matching('Cas', function ($q) use ($cas_number) {
        return $q->where([
            'Cas.value LIKE' => '%'.$cas_number.'%'
        ]);
    });
}

'SELECT DISTINCT Substances.id AS `id` FROM substances Substances INNER JOIN cas_substances CasSubstances ON Substances.id = (CasSubstances.substance_id) INNER JOIN cas Cas ON (Cas.value like :c0 AND Cas.id = (CasSubstances.cas_id))'

'SELECT DISTINCT Substances.id AS `id` FROM substances Substances INNER JOIN cas_substances CasSubstances ON Substances.id = (CasSubstances.substance_id) INNER JOIN cas Cas ON (Cas.value like :c0 AND Cas.id = (CasSubstances.cas_id)) INNER JOIN article_95 Article95s ON (Article95s.entity_name like :c1 AND Substances.id = (Article95s.app_id))'

到目前为止还不错。如果我输出SQL字符串，它如下所示：

$query = $Substances->find()->select(['id' => 'Substances.id'])->distinct();

// Search by CAS Number
if ($this->request->getData('cas_number')) {
    $cas_number = $this->request->getData('cas_number');
    $query = $query->matching('Cas', function ($q) use ($cas_number) {
        return $q->where([
            'Cas.value LIKE' => '%'.$cas_number.'%'
        ]);
    });
}

'SELECT DISTINCT Substances.id AS `id` FROM substances Substances INNER JOIN cas_substances CasSubstances ON Substances.id = (CasSubstances.substance_id) INNER JOIN cas Cas ON (Cas.value like :c0 AND Cas.id = (CasSubstances.cas_id))'

'SELECT DISTINCT Substances.id AS `id` FROM substances Substances INNER JOIN cas_substances CasSubstances ON Substances.id = (CasSubstances.substance_id) INNER JOIN cas Cas ON (Cas.value like :c0 AND Cas.id = (CasSubstances.cas_id)) INNER JOIN article_95 Article95s ON (Article95s.entity_name like :c1 AND Substances.id = (Article95s.app_id))'

我的问题是，当查询对象进入我的

article_95

表时，如何操作它，因为当我需要它加入

substances.app_id

时，它正试图加入

substances.id

我的

表中有以下内容

类。请注意行

$this->setPrimaryKey（'tbl_id'）-这是因为我使用的是一个遗留/旧数据库，
article\u 95
表的主键实际上是
tbl\u id
而不是
id
。但是，这相对来说并不重要，因为联接应该基于两个表中都存在的
app\u id

// src/Model/Table/SubstancesTable.php
public function initialize(array $config)
{
    $this->setTable('substances');
    $this->setPrimaryKey('id');
    $this->hasMany('Article95s', [
        'foreignKey' => 'app_id'
    ]);
    // ...
}


// src/Model/Table/Article95sTable.php
public function initialize(array $config)
{
    $this->setTable('article_95');
    $this->setPrimaryKey('tbl_id');

    $this->belongsTo('Substances', [
        'foreignKey' => 'app_id',
        'joinType' => 'INNER'
    ]);
}

如果我尝试执行包含Article 95值的搜索，则SQL字符串如下所示：

$query = $Substances->find()->select(['id' => 'Substances.id'])->distinct();

// Search by CAS Number
if ($this->request->getData('cas_number')) {
    $cas_number = $this->request->getData('cas_number');
    $query = $query->matching('Cas', function ($q) use ($cas_number) {
        return $q->where([
            'Cas.value LIKE' => '%'.$cas_number.'%'
        ]);
    });
}

'SELECT DISTINCT Substances.id AS `id` FROM substances Substances INNER JOIN cas_substances CasSubstances ON Substances.id = (CasSubstances.substance_id) INNER JOIN cas Cas ON (Cas.value like :c0 AND Cas.id = (CasSubstances.cas_id))'

'SELECT DISTINCT Substances.id AS `id` FROM substances Substances INNER JOIN cas_substances CasSubstances ON Substances.id = (CasSubstances.substance_id) INNER JOIN cas Cas ON (Cas.value like :c0 AND Cas.id = (CasSubstances.cas_id)) INNER JOIN article_95 Article95s ON (Article95s.entity_name like :c1 AND Substances.id = (Article95s.app_id))'

这个问题是SQL字符串的一部分，它读取
Substances.id=（Article95s.app_id））
。我需要它是
Substances.app_id=（Article95s.app_id））
，但我不知道如何用ORM语法编写它

在
substances.id
上保持其余连接（如前面显示的CAS编号）的连接也很重要

有人能帮忙吗？
老师解释一下

属于
bindingKey：其他表中用于匹配外键的列的名称。如果未指定，将使用主键（例如用户表的id列）

有许多
bindingKey：当前表中用于匹配foreignKey的列的名称。如果未指定，将使用主键（例如Articles表的id列）

老师解释了这一切

属于
bindingKey：其他表中用于匹配外键的列的名称。如果未指定，将使用主键（例如用户表的id列）

有许多
bindingKey：当前表中用于匹配foreignKey的列的名称。如果未指定，将使用主键（例如Articles表的id列）