Cakephp 使用';和'';或';条款
我的疑问是:Cakephp 使用';和'';或';条款,cakephp,cakephp-2.0,Cakephp,Cakephp 2.0,我的疑问是: //here $u_id is id of the users table retrieved using session variable $this->User->Request->find("all",array("conditions" =>array("request.status" => "friends" , "OR" => array("request.friend_id" => "$u_id","request.use
//here $u_id is id of the users table retrieved using session variable
$this->User->Request->find("all",array("conditions" =>array("request.status" => "friends" ,
"OR" => array("request.friend_id" => "$u_id","request.user_id" => "$u_id"))));
等效的SQL查询是:-
SELECT `Request`.`id`, `Request`.`user_id`, `Request`.`friend_id`, `Request`.`status`, `User`.`id`, `User`.`name`, `User`.`email`, `User`.`password`,
FROM
`myblog`.`requests` AS `Request` JOIN `myblog`.`users` AS `User`
ON
(`Request`.`friend_id` = `User`.`id`)
WHERE
((`request`.`friend_id` = 3) OR (`request`.`user_id` = 3)) AND `request`.`status` = 'friends'
然而,我希望在上面的SQL查询中,在“ON”之后有一行,以获得所需的结果:
`Request`.`user_id` = `User`.`id` OR `Request`.`friend_id` = `User`.`id`
我应该在find()
方法中进行哪些更改,
或者我应该改变我的模式
我的桌子是:
用户(id、姓名、密码、电子邮件)请求(id、用户id(用户表的id),
friend_id(用户表的id),状态)
可以在模型中指定条件
public $belongsTo = array('User' => array('className' => 'Request',
'foreignKey' => 'user_id',
'conditions' => array('OR' => array('Request.user_id' => 'User.id', 'Request.friend_id' => 'User.id')
))
);
我完全按照你告诉我的那样做了,但这次我在sql查询中“开”之后得到了以下信息:-(
请求
朋友id
=用户
id
和(请求
用户id用户id请求
朋友id
=/User.id'))我正在向我的机器说明这一点。同时,您可以参考以下链接: