如何在clojure中获得'doc'函数的输出?
我试图保存如何在clojure中获得'doc'函数的输出?,clojure,Clojure,我试图保存doc函数的输出,例如: user> (def doc-str-split (doc str/split)) ------------------------- clojure.string/split ([s re] [s re limit]) Splits string on a regular expression. Optional argument limit is the maximum number of splits. Not lazy. Returns
doc
函数的输出,例如:
user> (def doc-str-split (doc str/split))
-------------------------
clojure.string/split
([s re] [s re limit])
Splits string on a regular expression. Optional argument limit is
the maximum number of splits. Not lazy. Returns vector of the splits.
#'user/doc-str-split
user> doc-str-split
nil
user>
但是,对于docstr拆分
,我得到了nil
。我试图获取文档
输出的类型
:
user> (type (doc str/split))
-------------------------
clojure.string/split
([s re] [s re limit])
Splits string on a regular expression. Optional argument limit is
the maximum number of splits. Not lazy. Returns vector of the splits.
nil
仍然得到一个nil
。如何保存doc
函数的输出?您可以使用来捕获输出,如下所示:
user> (def doc-str-split (with-out-str (doc str/split)))
#'user/doc-str-split
user> (println doc-str-split)
-------------------------
clojure.string/split
([s re] [s re limit])
Splits string on a regular expression. Optional argument limit is
the maximum number of splits. Not lazy. Returns vector of the splits.
nil
user> (type (with-out-str (doc str/split)))
java.lang.String
您可以只获取文档字符串,如下所示:
user.core=> (def doc (prn (:doc (meta #'clojure.string/split))))
"Splits string on a regular expression. Optional argument limit is
the maximum number of splits. Not lazy. Returns vector of the splits."
啊,我不知道这个功能。谢谢
Clojure
充满了令人惊讶但有用的功能。非常感谢。