Collections MongoDB一次查询多个集合
这是我的mongodb的一个示例。我想得到所有具有“via”属性等于“facebook”并由管理员发布的帖子(“admin”:1)。我不知道如何获取此查询。因为mongodb不是关系数据库,所以我无法执行连接操作。解决方案是什么?执行多个查询或使用嵌入式文档或查看“数据库引用”。尝试加入MongoDB将无法达到使用MongoDB的目的。但是,您可以使用和编写应用程序级代码(或库),以便它自动为您获取这些引用 或者您可以更改模式并使用Collections MongoDB一次查询多个集合,collections,join,mongodb,Collections,Join,Mongodb,这是我的mongodb的一个示例。我想得到所有具有“via”属性等于“facebook”并由管理员发布的帖子(“admin”:1)。我不知道如何获取此查询。因为mongodb不是关系数据库,所以我无法执行连接操作。解决方案是什么?执行多个查询或使用嵌入式文档或查看“数据库引用”。尝试加入MongoDB将无法达到使用MongoDB的目的。但是,您可以使用和编写应用程序级代码(或库),以便它自动为您获取这些引用 或者您可以更改模式并使用 最后一个选择是让事情保持原样,并执行两个查询。一个解决方案:将
最后一个选择是让事情保持原样,并执行两个查询。一个解决方案:将isAdmin:0/1标志添加到收集后文档中
其他解决方案:如前所述,在MongoDB中使用DBrefs,您不能在集合之间加入 例如,解决方案可以是:
users
{
"_id":"12345",
"admin":1
},
{
"_id":"123456789",
"admin":0
}
posts
{
"content":"Some content",
"owner_id":"12345",
"via":"facebook"
},
{
"content":"Some other content",
"owner_id":"123456789",
"via":"facebook"
}
请参阅参考手册-光标部分:
另一个解决方案是在posts集合中嵌入用户,但我认为对于大多数web应用程序来说,出于安全原因,用户集合需要是独立的。用户集合可能具有角色、权限等
var myCursor = db.users.find({admin:1});
var user_id = myCursor.hasNext() ? myCursor.next() : null;
db.posts.find({owner_id : user_id._id});
然后:
posts
{
"content":"Some content",
"user":{"_id":"12345", "admin":1},
"via":"facebook"
},
{
"content":"Some other content",
"user":{"_id":"123456789", "admin":0},
"via":"facebook"
}
这是你问题的答案
db.posts.find({user.admin: 1 });
或者您可以选择mongodb group选项
db.getCollection('users').aggregate([
{$match : {admin : 1}},
{$lookup: {from: "posts",localField: "_id",foreignField: "owner_id",as: "posts"}},
{$project : {
posts : { $filter : {input : "$posts" , as : "post", cond : { $eq : ['$$post.via' , 'facebook'] } } },
admin : 1
}}
])
您可以使用
$lookup
(多个)从多个集合中获取记录:
{
"_id" : ObjectId("5901b0f6d318b072ceea44fb"),
"userId" : ObjectId("5901a4c63541b7d5d3293766"),
"fbURLs" : "http://www.facebook.com",
"twitterURLs" : "http://www.twitter.com"
}
db.doc1.aggregate([
{ $match: { _id: ObjectId("5901a4c63541b7d5d3293766") } },
{
$lookup:
{
from: "doc2",
localField: "_id",
foreignField: "userId",
as: "address"
}
},
{
$unwind: "$address"
},
{
$project: {
__v: 0,
"address.__v": 0,
"address._id": 0,
"address.userId": 0,
"address.mob": 0
}
},
{
$lookup:
{
from: "doc3",
localField: "_id",
foreignField: "userId",
as: "social"
}
},
{
$unwind: "$social"
},
{
$project: {
__v: 0,
"social.__v": 0,
"social._id": 0,
"social.userId": 0
}
}
]).pretty();
{
"_id" : ObjectId("5901a4c63541b7d5d3293766"),
"firstName" : "shubham",
"lastName" : "verma",
"address" : {
"address" : "Gurgaon"
},
"social" : {
"fbURLs" : "http://www.facebook.com",
"twitterURLs" : "http://www.twitter.com"
}
}
{
$project: {
__v: 0,
"address.__v": 0,
"address._id": 0,
"address.userId": 0,
"address.mob": 0
}
}
{
$project: {
"social.__v": 0,
"social._id": 0,
"social.userId": 0
}
}
例如:
如果您有更多的集合(我这里有3个用于演示的集合,您可以有3个以上)。我想从单个对象中的3个集合中获取数据:
集合如下所示:
{
"_id" : ObjectId("5901b0f6d318b072ceea44fb"),
"userId" : ObjectId("5901a4c63541b7d5d3293766"),
"fbURLs" : "http://www.facebook.com",
"twitterURLs" : "http://www.twitter.com"
}
db.doc1.aggregate([
{ $match: { _id: ObjectId("5901a4c63541b7d5d3293766") } },
{
$lookup:
{
from: "doc2",
localField: "_id",
foreignField: "userId",
as: "address"
}
},
{
$unwind: "$address"
},
{
$project: {
__v: 0,
"address.__v": 0,
"address._id": 0,
"address.userId": 0,
"address.mob": 0
}
},
{
$lookup:
{
from: "doc3",
localField: "_id",
foreignField: "userId",
as: "social"
}
},
{
$unwind: "$social"
},
{
$project: {
__v: 0,
"social.__v": 0,
"social._id": 0,
"social.userId": 0
}
}
]).pretty();
{
"_id" : ObjectId("5901a4c63541b7d5d3293766"),
"firstName" : "shubham",
"lastName" : "verma",
"address" : {
"address" : "Gurgaon"
},
"social" : {
"fbURLs" : "http://www.facebook.com",
"twitterURLs" : "http://www.twitter.com"
}
}
{
$project: {
__v: 0,
"address.__v": 0,
"address._id": 0,
"address.userId": 0,
"address.mob": 0
}
}
{
$project: {
"social.__v": 0,
"social._id": 0,
"social.userId": 0
}
}
db.doc1.find().pretty()强>
db.getCollection('users').aggregate([
{$match : {admin : 1}},
{$lookup: {from: "posts",localField: "_id",foreignField: "owner_id",as: "posts"}},
{$unwind : "$posts"},
{$match : {"posts.via":"facebook"}},
{ $group : {
_id : "$_id",
posts : {$push : "$posts"}
}}
])
{
"_id" : ObjectId("5901a4c63541b7d5d3293766"),
"firstName" : "shubham",
"lastName" : "verma"
}
{
"_id" : ObjectId("5901a5f83541b7d5d3293768"),
"userId" : ObjectId("5901a4c63541b7d5d3293766"),
"address" : "Gurgaon",
"mob" : "9876543211"
}
db.doc2.find().pretty()强>
db.getCollection('users').aggregate([
{$match : {admin : 1}},
{$lookup: {from: "posts",localField: "_id",foreignField: "owner_id",as: "posts"}},
{$unwind : "$posts"},
{$match : {"posts.via":"facebook"}},
{ $group : {
_id : "$_id",
posts : {$push : "$posts"}
}}
])
{
"_id" : ObjectId("5901a4c63541b7d5d3293766"),
"firstName" : "shubham",
"lastName" : "verma"
}
{
"_id" : ObjectId("5901a5f83541b7d5d3293768"),
"userId" : ObjectId("5901a4c63541b7d5d3293766"),
"address" : "Gurgaon",
"mob" : "9876543211"
}
db.doc3.find().pretty()强>
db.getCollection('users').aggregate([
{$match : {admin : 1}},
{$lookup: {from: "posts",localField: "_id",foreignField: "owner_id",as: "posts"}},
{$unwind : "$posts"},
{$match : {"posts.via":"facebook"}},
{ $group : {
_id : "$_id",
posts : {$push : "$posts"}
}}
])
{
"_id" : ObjectId("5901a4c63541b7d5d3293766"),
"firstName" : "shubham",
"lastName" : "verma"
}
{
"_id" : ObjectId("5901a5f83541b7d5d3293768"),
"userId" : ObjectId("5901a4c63541b7d5d3293766"),
"address" : "Gurgaon",
"mob" : "9876543211"
}
现在您的查询如下:
{
"_id" : ObjectId("5901b0f6d318b072ceea44fb"),
"userId" : ObjectId("5901a4c63541b7d5d3293766"),
"fbURLs" : "http://www.facebook.com",
"twitterURLs" : "http://www.twitter.com"
}
db.doc1.aggregate([
{ $match: { _id: ObjectId("5901a4c63541b7d5d3293766") } },
{
$lookup:
{
from: "doc2",
localField: "_id",
foreignField: "userId",
as: "address"
}
},
{
$unwind: "$address"
},
{
$project: {
__v: 0,
"address.__v": 0,
"address._id": 0,
"address.userId": 0,
"address.mob": 0
}
},
{
$lookup:
{
from: "doc3",
localField: "_id",
foreignField: "userId",
as: "social"
}
},
{
$unwind: "$social"
},
{
$project: {
__v: 0,
"social.__v": 0,
"social._id": 0,
"social.userId": 0
}
}
]).pretty();
{
"_id" : ObjectId("5901a4c63541b7d5d3293766"),
"firstName" : "shubham",
"lastName" : "verma",
"address" : {
"address" : "Gurgaon"
},
"social" : {
"fbURLs" : "http://www.facebook.com",
"twitterURLs" : "http://www.twitter.com"
}
}
{
$project: {
__v: 0,
"address.__v": 0,
"address._id": 0,
"address.userId": 0,
"address.mob": 0
}
}
{
$project: {
"social.__v": 0,
"social._id": 0,
"social.userId": 0
}
}
那么您的结果将是:
{
"_id" : ObjectId("5901b0f6d318b072ceea44fb"),
"userId" : ObjectId("5901a4c63541b7d5d3293766"),
"fbURLs" : "http://www.facebook.com",
"twitterURLs" : "http://www.twitter.com"
}
db.doc1.aggregate([
{ $match: { _id: ObjectId("5901a4c63541b7d5d3293766") } },
{
$lookup:
{
from: "doc2",
localField: "_id",
foreignField: "userId",
as: "address"
}
},
{
$unwind: "$address"
},
{
$project: {
__v: 0,
"address.__v": 0,
"address._id": 0,
"address.userId": 0,
"address.mob": 0
}
},
{
$lookup:
{
from: "doc3",
localField: "_id",
foreignField: "userId",
as: "social"
}
},
{
$unwind: "$social"
},
{
$project: {
__v: 0,
"social.__v": 0,
"social._id": 0,
"social.userId": 0
}
}
]).pretty();
{
"_id" : ObjectId("5901a4c63541b7d5d3293766"),
"firstName" : "shubham",
"lastName" : "verma",
"address" : {
"address" : "Gurgaon"
},
"social" : {
"fbURLs" : "http://www.facebook.com",
"twitterURLs" : "http://www.twitter.com"
}
}
{
$project: {
__v: 0,
"address.__v": 0,
"address._id": 0,
"address.userId": 0,
"address.mob": 0
}
}
{
$project: {
"social.__v": 0,
"social._id": 0,
"social.userId": 0
}
}
如果您想要每个集合中的所有记录,则应从查询中删除以下行:
{
"_id" : ObjectId("5901b0f6d318b072ceea44fb"),
"userId" : ObjectId("5901a4c63541b7d5d3293766"),
"fbURLs" : "http://www.facebook.com",
"twitterURLs" : "http://www.twitter.com"
}
db.doc1.aggregate([
{ $match: { _id: ObjectId("5901a4c63541b7d5d3293766") } },
{
$lookup:
{
from: "doc2",
localField: "_id",
foreignField: "userId",
as: "address"
}
},
{
$unwind: "$address"
},
{
$project: {
__v: 0,
"address.__v": 0,
"address._id": 0,
"address.userId": 0,
"address.mob": 0
}
},
{
$lookup:
{
from: "doc3",
localField: "_id",
foreignField: "userId",
as: "social"
}
},
{
$unwind: "$social"
},
{
$project: {
__v: 0,
"social.__v": 0,
"social._id": 0,
"social.userId": 0
}
}
]).pretty();
{
"_id" : ObjectId("5901a4c63541b7d5d3293766"),
"firstName" : "shubham",
"lastName" : "verma",
"address" : {
"address" : "Gurgaon"
},
"social" : {
"fbURLs" : "http://www.facebook.com",
"twitterURLs" : "http://www.twitter.com"
}
}
{
$project: {
__v: 0,
"address.__v": 0,
"address._id": 0,
"address.userId": 0,
"address.mob": 0
}
}
{
$project: {
"social.__v": 0,
"social._id": 0,
"social.userId": 0
}
}
删除上述代码后,您将获得如下总记录:
{
"_id" : ObjectId("5901b0f6d318b072ceea44fb"),
"userId" : ObjectId("5901a4c63541b7d5d3293766"),
"fbURLs" : "http://www.facebook.com",
"twitterURLs" : "http://www.twitter.com"
}
db.doc1.aggregate([
{ $match: { _id: ObjectId("5901a4c63541b7d5d3293766") } },
{
$lookup:
{
from: "doc2",
localField: "_id",
foreignField: "userId",
as: "address"
}
},
{
$unwind: "$address"
},
{
$project: {
__v: 0,
"address.__v": 0,
"address._id": 0,
"address.userId": 0,
"address.mob": 0
}
},
{
$lookup:
{
from: "doc3",
localField: "_id",
foreignField: "userId",
as: "social"
}
},
{
$unwind: "$social"
},
{
$project: {
__v: 0,
"social.__v": 0,
"social._id": 0,
"social.userId": 0
}
}
]).pretty();
{
"_id" : ObjectId("5901a4c63541b7d5d3293766"),
"firstName" : "shubham",
"lastName" : "verma",
"address" : {
"address" : "Gurgaon"
},
"social" : {
"fbURLs" : "http://www.facebook.com",
"twitterURLs" : "http://www.twitter.com"
}
}
{
$project: {
__v: 0,
"address.__v": 0,
"address._id": 0,
"address.userId": 0,
"address.mob": 0
}
}
{
$project: {
"social.__v": 0,
"social._id": 0,
"social.userId": 0
}
}
如何编写两个查询呢?Doctrine MongoDB ODM是处理这类事情的一个不错的库。但是,它只允许通过一层引用进行连接;您不能以任何程度的语法轻松地在引用中的引用中填充引用。如何在MongoJS中使用普通的旧查询实现这一点?您现在可以使用
$lookup
加入抱歉,但我必须说,“尝试在没有联接概念的情况下使用DB会完全违背数据库的目的。完全”Mongo添加了$lookup,原因是错误地假设情况并非如此。嵌入文档不是最好的解决方案,因为它们与它们应该等价的记录不同步,最终导致数据重复。这是怎么回事?这是一个查询还是将元数据添加到集合中?$lookup运算符是自3.2版以来的新运算符,类似于左外联接。请参见@Shubham Verma,如何从“社交”或“地址”集合中获取多个记录。在同一个查询中。就像我有多个记录在社会收集为单一用户