C++ 类-C++;

C++ 类-C++;,c++,class,struct,undefined,member,C++,Class,Struct,Undefined,Member,我会尽力解释的 基本上,我是为GBA游戏编写这个程序的,我试图在类中更改struct实例的成员变量。这是代码,省略了不必要的部分: player.cpp #include "player.h" // Line 1 #include "BgLayerSettings.h" player::player(){ x = 16; y = 16; health = 5; direction = LEFT; dead = false; }

我会尽力解释的

基本上,我是为GBA游戏编写这个程序的,我试图在类中更改struct实例的成员变量。这是代码,省略了不必要的部分:

player.cpp

#include "player.h"                // Line 1
#include "BgLayerSettings.h"
player::player(){
    x = 16;
    y = 16;
    health = 5;
    direction = LEFT;
    dead = false;
}

player::~player(){
}

// Omitted unrelated code

void player::ScrollScreen(){       // Line 99
    if(x>((240/2)-8)){
        BACKGROUND_2.h_offset += x-((240/2)-8);
    }
}
player.h

#include <stdint.h>                // Line 1
#include <stdlib.h>
#include <string.h>
#include "gba.h"
#include "font.h"
#pragma once

class player {
public:
    player();
    ~player();

    unsigned int x;
    unsigned int y;

    void ScrollScreen();
};
}

BgLayerSettings.h

#include <stdint.h>                // Line 1
#include <stdlib.h>
#include <string.h>
#include "gbs.h"
#include "font.h"
#pragma once

enum BACKGROUND {bg0=0, bg1, bg2, bg3, bg4, bg5, bg6, bg7,
                bg8, bg9, bg10, bg11, bg12, bg13, bg14, bg15,
                bg16, bg17, bg18, bg19, bg20, bg21, bg22, bg23,
                bg24, bg25, bg26, bg27, bg28, DUNGEON_1, DUNGEON_FLOOR, BLANK,
};

struct BgLayerSettings {
    public:
        BgLayerSettings();
        ~BgLayerSettings();

        unsigned int charblock;
        BACKGROUND screenblock;
        int v_offset;
        int h_offset;
};
本质上,我试图从
player
类中更改对象
BACKGROUND\u 2
的变量
h\u offset

当我尝试编译此文件时,收到以下错误:

player.cpp: In member function 'void player::ScrollScreen()':
player.cpp:101:3: error: 'BACKGROUND_2' was not declared in this scope
make: *** [player.o] Error 1
不管我怎么努力,我都无法克服这个错误。有人能帮我解释一下吗


提前感谢。

它看起来不像Player.cpp,特别是这一行

BACKGROUND_2.h_offset += x-((240/2)-8);
可以看到BACKGROUND_2的实例。如果您在main.cpp中实例化它,那么在构建过程中Player.cpp将无法看到它。您应该将想要更改的任何背景作为引用传递到函数中,并从main.cpp更改它。像这样的东西

void player::ScrollScreen( BgLayerSettings &bg ){       // Line 99
    if(x>((240/2)-8)){
        bg.h_offset += x-((240/2)-8);
    }
}
你的main.cpp应该是这样的

player1.ScrollScreen( BACKGROUND_2 );

那么
player.h
中的原型如何查找
void screen()在这种情况下?类似于void ScrollScreen(BgLayerSettings&b),如果您不想添加BgLayerSettings的include,您可以通过放置类BgLayerSettings向前声明它;超过你的玩家定义。已经为此辛劳了几个小时,终于修好了!非常感谢:)我自己也去过那里。
void player::ScrollScreen( BgLayerSettings &bg ){       // Line 99
    if(x>((240/2)-8)){
        bg.h_offset += x-((240/2)-8);
    }
}
player1.ScrollScreen( BACKGROUND_2 );