C++ 试图获取用户输入并发送一条消息，当我输入一个有效的名称时，它会发送所有的信息 #包括 #包括 #包括 使用名称空间std； int main（）{ 弦枪=”； 如果条件不能以这种方式工作，则不能

。 如果你想要这个，你必须这样写：

#include <iostream>
#include <string>
#include <sstream>

using namespace std;

int main() {

    string gun = "";
    cout << "Enter The Gun You Would Like To Know The Type Of Ammo For: \n";
    getline(cin, gun);
    if (gun == "b95" || "B95" || "windchester" || "wind chester" || "Windchester" || "Wind Chester" || "longhorn" || "Long Horn" || "fal" || "FAL")
    {
        cout << "The Type Of Ammo For The " << gun << " Is 308 Windchester";
    }   
    if (gun == "izh rifle" || "IZH Rifle" || "izhrifle" || "izh rifle" || "sks" || "SKS" || "akm" || "AKM")
    {
        cout << "The Type Of Ammo For The " << gun << " 7.62x39mm";
    }
    if (gun == "Mangnum" || "mangnum" || "Repetor" || "repetor")
    {
        cout << "The Type Of Ammo For The " << gun << ".357";
    }
    return 0;
}

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基本上比较需要两个值进行比较，而不是一个值。

< P>不能在C++中写这样的布尔表达式。布尔表达式的每一个都是布尔值，所以在你的情况下，所有三个都是真的，因为在布尔表达式中非空字符串是真的。 请阅读有关布尔表达式的内容并编写类似的内容

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如果（输入＝“STR1”，输入=“STR2”等）

如果你的条件不做你想让他们做的事，请从C++中学习C++，而不是猜测。

 if (gun == "izh rifle" || gun ==  "IZH Rifle" || gun == "izhrifle" || gun ==  "izh rifle" || 
   gun ==  "sks" ||gun ==  "SKS" ||gun ==  "akm" ||gun ==  "AKM")