C++ 使用boost::chrono计算执行时间
我试图计算循环中函数执行时间的总和,但出现了一些问题:C++ 使用boost::chrono计算执行时间,c++,boost,type-conversion,global-variables,C++,Boost,Type Conversion,Global Variables,我试图计算循环中函数执行时间的总和,但出现了一些问题: #include <boost/chrono.hpp> #include <iostream> boost::chrono::milliseconds sumGlobal; int main() { boost::chrono::high_resolution_clock::time_point t1 ; boost::chrono::high_resolution_clock::time_poi
#include <boost/chrono.hpp>
#include <iostream>
boost::chrono::milliseconds sumGlobal;
int main() {
boost::chrono::high_resolution_clock::time_point t1 ;
boost::chrono::high_resolution_clock::time_point t2 ;
for (i=0;i<10;i++)
{
t1 = boost::chrono::high_resolution_clock::now();
f(); //to waste time
t2 = boost::chrono::high_resolution_clock::now();
sumGlobal += (boost::chrono::duration_cast<boost::chrono::milliseconds>(t2-t1)).sumGlobal;
}
std::cout << sumGlobal << "\n";
}
#包括
#包括
boost::chrono::global;
int main(){
boost::chrono::高分辨率时钟::时间点t1;
boost::chrono::高分辨率时钟::时间点t2;
for(i=0;iboost::chrono::millides
不会返回带有sumGlobal
数据成员的内容。只需将其丢弃即可
sumGlobal += (boost::chrono::duration_cast<boost::chrono::milliseconds>(t2-t1));
sumGlobal+=(boost::chrono::duration_cast(t2-t1));
boost::chrono::millizes
不会返回带有sumGlobal
数据成员的内容。只需将其丢弃即可
sumGlobal += (boost::chrono::duration_cast<boost::chrono::milliseconds>(t2-t1));
sumGlobal+=(boost::chrono::duration_cast(t2-t1));