C++ boost::计时可读持续时间
我一直在使用boost chrono开发一个探查器,它可以在微秒内对函数进行计时,对于小函数效果很好,但对于较大的函数,我倾向于获得非常高的数值 想象一下下面的场景C++ boost::计时可读持续时间,c++,boost,C++,Boost,我一直在使用boost chrono开发一个探查器,它可以在微秒内对函数进行计时,对于小函数效果很好,但对于较大的函数,我倾向于获得非常高的数值 想象一下下面的场景 boost::chrono::duration<long long, boost::micro> us1(300); boost::chrono::duration<long long, boost::micro> us2(200000); std::cout << boost::chrono:
boost::chrono::duration<long long, boost::micro> us1(300);
boost::chrono::duration<long long, boost::micro> us2(200000);
std::cout << boost::chrono::duration_short << "us1: " << us1 << ", us2: " << us2;
boost::chrono::duration us1(300);
boost::chrono::duration us2(200000);
std::cout多亏了大家,我这样解决了这个问题:
const std::string readableDuration(const boost::chrono::duration<long long, boost::micro>& duration)
{
std::stringstream stream;
int digits = calcNumDigits(duration.count());
stream << boost::chrono::duration_short;
if (digits <= 3) {
stream << duration;
} else if ((digits > 3) && (digits <= 6)) {
stream << boost::chrono::duration_cast<boost::chrono::milliseconds>(duration);
} else if ((digits > 6) && (digits <= 9)) {
stream << boost::chrono::duration_cast<boost::chrono::seconds>(duration);
} else if (digits > 9)
{
stream << boost::chrono::duration_cast<boost::chrono::minutes>(duration);
}
return stream.str();
}
const std::string readableDuration(const boost::chrono::duration&duration)
{
std::stringstream;
int digits=calcNumDigits(duration.count());
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