C++ 为work函数中的每个输出指定noutput_项

我想修改OOT块，使其具有两个输出，如下所示：

    int
    block_impl::general_work (int noutput_items,
                       gr_vector_int &ninput_items,
                       gr_vector_const_void_star &input_items,
                       gr_vector_void_star &output_items)
    {
        const int OUT = 0;
        const int OUT_ALL = 1;

        const gr_complex *in = (const gr_complex *) input_items[0];
        gr_complex *out = (gr_complex *) output_items[OUT];
        gr_complex *out_all = (gr_complex *) output_items[OUT_ALL];
        
        // signal processing part 

        switch (state) {
          case SEND: {
            // Send one complex vector to "out" and "out_all"
            produce(OUT,1);
            produce(OUT_ALL,1);
          }
          case NOK:  {
            // Send complex vector to "out_all"
            produce(OUT,0);
            produce(OUT_ALL,1);
          }
        }
        return WORK_CALLED_PRODUCE;
     }

当前状态：

    int
    block_impl::general_work (int noutput_items,
                       gr_vector_int &ninput_items,
                       gr_vector_const_void_star &input_items,
                       gr_vector_void_star &output_items)
    {
        const gr_complex *in = (const gr_complex *) input_items[0];
        gr_complex *out = (gr_complex *) output_items[0];        
        
        // signal processing part 

        switch (state) {
          case SEND: {
            // Send one complex vector to "out"
            noutput_items = 1;
          }
          case NOK:  {
            // Do nothing
            noutput_items = 0;
          }
        }
        return noutput_items;
     }

我试着：

    int
    block_impl::general_work (int noutput_items,
                       gr_vector_int &ninput_items,
                       gr_vector_const_void_star &input_items,
                       gr_vector_void_star &output_items)
    {
        const gr_complex *in = (const gr_complex *) input_items[0];
        gr_complex *out = (gr_complex *) output_items[0];
        gr_complex *out_all = (gr_complex *) output_items[1];
        
        // signal processing part 

        switch (state) {
          case SEND: {
            // Send one complex vector to "out" and "out_all"
            noutput_items = 2;
          }
          case NOK:  {
            // Send complex vector to "out_all"
            noutput_items = 1;
          }
        }
        return noutput_items;
     }

但是，此解决方案不起作用，因为连接到“out_all”的块没有接收任何内容，并且连接到“out”的块不再正常工作

我想我对在工作函数结束时返回的“noutput_items”值的理解并不全面，有人能解释一下我缺少了什么吗？

您可以使用如下方法：

    int
    block_impl::general_work (int noutput_items,
                       gr_vector_int &ninput_items,
                       gr_vector_const_void_star &input_items,
                       gr_vector_void_star &output_items)
    {
        const int OUT = 0;
        const int OUT_ALL = 1;

        const gr_complex *in = (const gr_complex *) input_items[0];
        gr_complex *out = (gr_complex *) output_items[OUT];
        gr_complex *out_all = (gr_complex *) output_items[OUT_ALL];
        
        // signal processing part 

        switch (state) {
          case SEND: {
            // Send one complex vector to "out" and "out_all"
            produce(OUT,1);
            produce(OUT_ALL,1);
          }
          case NOK:  {
            // Send complex vector to "out_all"
            produce(OUT,0);
            produce(OUT_ALL,1);
          }
        }
        return WORK_CALLED_PRODUCE;
     }