C++ 从不同的c类访问阵列++;
我正在为学校做一个名为LCR的骰子游戏。我最终得到了要编译的程序,并且我已经完成了游戏例程。我现在被困在从我的玩家类访问主阵列上。特别是播放器::设置芯片。我可能应该使用指针,但我在这方面非常粗糙,任何输入都可能很棒。函数调用很好,输出正常,但是我注释掉的行显然不正常,但是给出了我想要做的事情的想法。谢谢 以下是我在LCR Game.cpp中的代码:C++ 从不同的c类访问阵列++;,c++,C++,我正在为学校做一个名为LCR的骰子游戏。我最终得到了要编译的程序,并且我已经完成了游戏例程。我现在被困在从我的玩家类访问主阵列上。特别是播放器::设置芯片。我可能应该使用指针,但我在这方面非常粗糙,任何输入都可能很棒。函数调用很好,输出正常,但是我注释掉的行显然不正常,但是给出了我想要做的事情的想法。谢谢 以下是我在LCR Game.cpp中的代码: int main() { // Display Game Rules Player::directions();
int main()
{
// Display Game Rules
Player::directions();
// Get # of Players
int currentPlayer = 0;
srand((unsigned)time(NULL));
const int numPlayers = setPlayers(); //set number of players
static Player* players = new Player[numPlayers]; //set up array
for (int i = 0; i < numPlayers; i++) //set names and chips for each player
{
cout << endl << "Enter player number " << (i + 1) << "'s name: " << endl;
players[i].setName();
players[i].chips = 3;
}
// start game
cout << endl << "OK Let's play!" << endl;
while (winner == false) {
for (int i = 0; i < numPlayers; i++) {
// check if player has chips. if not ++i and skip turn
if (players[i].chips == 0) {
cout << endl << "Sorry " << players[i].name << " you have no chips, you must skip this turn" << endl;
++i;
}
cout << endl << players[i].name << " You have " << players[i].chips << " chips " << " press enter to roll the dice" << endl;
std::cin.ignore(); //wait for keypress
for (int j = 0; j < players[i].chips || j < 3; j++) { // player rolls dice up to 3 times or max chips
Player::setChips(); // call setChips. roll dice & move chips
cout << players[i].chips;
// check for winner after each diceroll
totalChips = 0; // reset chip counter
for (int k = 0; k < numPlayers; k++) { //add all chips on table
totalChips = totalChips + players[i].chips;
}
// check for winner
if (totalChips - players[i].chips == 0) {
cout << endl << "Congratulations " << players[i].name << " you win " << players[i].chips << " chips!";
winner = true;
return 0;
}
}
}
}
return 0;
}
intmain()
{
//显示游戏规则
播放器::方向();
//获得#名球员
int currentPlayer=0;
srand((无符号)时间(NULL));
const int numPlayers=setPlayers();//设置玩家数量
静态玩家*players=新玩家[numPlayers];//设置数组
for(int i=0;i 您的setChips
功能是静态的吗
非静态成员引用必须相对于特定对象
您的错误是因为函数setChips
是静态的,而chips
不是静态的
如果你想让你的函数是静态的,你需要让芯片也成为静态的。另外,在.cpp的顶部,你需要定义未签名的播放器::芯片;
,然后你可以在播放器
类函数中使用++chips
如果你不需要你的函数是静态的,只需要从你的函数中删除静态的,你仍然可以在你的类函数中使用++chips
。在“Player”对象中你不需要players数组。只需要使用++chips;所以players[3]给你一个播放器,players[3]。set_chips()调用set_chips(),可以访问所有播放器[3]数据。我只尝试了++芯片,它说“非静态成员引用必须相对于特定对象。如果我尝试++播放器[1]我知道我缺少一些简单的东西,但是我对C++很陌生。谢谢。我用芯片做了静态的,使用了芯片+。像一个魅力。再一次我在想它。谢谢大家!
void Player::setChips()
{
switch (Dice::rollDice()) // roll the dice
{
case 1:
cout << endl << "You rolled <L> "; // subtract 1 chip from player and add one to left
//--players[i].chips;
//if (i = numPlayers) {
// ++players[1].chips;
// }
break;
case 2:
cout << endl << "You rolled <C> "; // subtract 1 chip from player
//--players[i].chips;
break;
case 3:
cout << endl << "You rolled <R> "; //subrtact 1 chip from player and give to right
//--players[i].chips;
//if (i = 1) {
// ++players[numPlayers].chips;
break;
case 4:
cout << endl << "You rolled <*> ";
break; //do nothing
case 5:
cout << endl << "You rolled <*> ";
break; // do nothing
case 6:
cout << endl << "You rolled <*> ";
break; //do nothing
}
}