C++ g++；std:：与共享\u ptr绑定错误

我很难理解为什么下面的代码不能编译

#include <memory>
#include <functional>

class Foo 
{
public:
  void Bar(int i) {}
};

void X(std::function<void(std::shared_ptr<Foo>)> f)
{

}

int main()
{
  std::shared_ptr<Foo> f(new Foo);
  auto f1(std::bind(&Foo::Bar, std::placeholders::_1, 1));
  X(f1);
  return 0;
}

#包括
#包括
福班
{
公众：
空条（int i）{}
};
void X（标准：：函数f）
{
}
int main（）
{
std：：共享的ptr f（新的Foo）；
自动f1（std:：bind（&Foo:：Bar，std:：占位符：：_1，1））；
X（f1）；
返回0；
}

g++（4.6.3）输出

n file included from /usr/include/c++/4.6/memory:80:0,
                 from test.cpp:1:
/usr/include/c++/4.6/functional: In static member function ‘static void std::_Function_handler<void(_ArgTypes ...), _Functor>::_M_invoke(const std::_Any_data&, _ArgTypes ...) [with _Functor = std::_Bind<std::_Mem_fn<void (Foo::*)(int)>(std::_Placeholder<1>, int)>, _ArgTypes = {std::shared_ptr<Foo>}]’:
/usr/include/c++/4.6/functional:2148:6:   instantiated from ‘std::function<_Res(_ArgTypes ...)>::function(_Functor, typename std::enable_if<(! std::is_integral<_Functor>::value), std::function<_Res(_ArgTypes ...)>::_Useless>::type) [with _Functor = std::_Bind<std::_Mem_fn<void (Foo::*)(int)>(std::_Placeholder<1>, int)>, _Res = void, _ArgTypes = {std::shared_ptr<Foo>}, typename std::enable_if<(! std::is_integral<_Functor>::value), std::function<_Res(_ArgTypes ...)>::_Useless>::type = std::function<void(std::shared_ptr<Foo>)>::_Useless]’
test.cpp:19:7:   instantiated from here
/usr/include/c++/4.6/functional:1778:2: error: no match for call to ‘(std::_Bind<std::_Mem_fn<void (Foo::*)(int)>(std::_Placeholder<1>, int)>) (std::shared_ptr<Foo>)’
/usr/include/c++/4.6/functional:1130:11: note: candidates are:
/usr/include/c++/4.6/functional:1201:2: note: template<class ... _Args, class _Result> _Result std::_Bind<_Functor(_Bound_args ...)>::operator()(_Args&& ...) [with _Args = {_Args ...}, _Result = _Result, _Functor = std::_Mem_fn<void (Foo::*)(int)>, _Bound_args = {std::_Placeholder<1>, int}]
/usr/include/c++/4.6/functional:1215:2: note: template<class ... _Args, class _Result> _Result std::_Bind<_Functor(_Bound_args ...)>::operator()(_Args&& ...) const [with _Args = {_Args ...}, _Result = _Result, _Functor = std::_Mem_fn<void (Foo::*)(int)>, _Bound_args = {std::_Placeholder<1>, int}]
/usr/include/c++/4.6/functional:1229:2: note: template<class ... _Args, class _Result> _Result std::_Bind<_Functor(_Bound_args ...)>::operator()(_Args&& ...) volatile [with _Args = {_Args ...}, _Result = _Result, _Functor = std::_Mem_fn<void (Foo::*)(int)>, _Bound_args = {std::_Placeholder<1>, int}]
/usr/include/c++/4.6/functional:1243:2: note: template<class ... _Args, class _Result> _Result std::_Bind<_Functor(_Bound_args ...)>::operator()(_Args&& ...) const volatile [with _Args = {_Args ...}, _Result = _Result, _Functor = std::_Mem_fn<void (Foo::*)(int)>, _Bound_args = {std::_Placeholder<1>, int}]

n文件包含在/usr/include/c++/4.6/memory:80:0中，
来自测试。cpp:1：
/usr/include/c++/4.6/functional:在静态成员函数“static void std:：_function_handler:：_M_invoke（const std:：_Any_data&，_ArgTypes…[带_Functor=std:：_Bind，_ArgTypes={std:：shared ptr}]：
/usr/include/c++/4.6/functional:2148:6：从“std:：function”（\u Functor，typename std:：enable\u if:：type）[with _Functor=std:：\u Bind，\u Res=void，\u ArgTypes={std:：shared\u ptr}，typename std:：enable\u if:：type=std:：function:\u无用]”实例化
test.cpp:19:7:从此处实例化
/usr/include/c++/4.6/functional:1778:2:错误：调用“（std:：_Bind）（std:：shared_ptr）”时不匹配
/usr/include/c++/4.6/functional:1130:11：注：候选项包括：
/usr/include/c++/4.6/functional:1201:2：注意：模板(结果std:):(绑定&&…[带(Args={Args…}，)结果=(结果)，(Functor=std:):(内存(fn，)绑定(Args={std:)占位符，int}]
/usr/include/c++/4.6/functional:1215:2：注意：模板(结果std:):(绑定&&…)操作符（）（)参数&…)常量[带(参数={(参数…}，)结果=(结果，)函数=std:(内存)fn，(绑定)参数={std:(占位符，int}]
/usr/include/c++/4.6/functional:1229:2:注意：模板(结果std:):(绑定&&…)操作符（）（(参数&&…)volatile[带有(参数={(参数…}，)结果=(结果，)函子=std:(内存)fn，(绑定)参数={std:(占位符，int}]
/usr/include/c++/4.6/functional:1243:2:注：模板(结果std:):(绑定&&…)运算符（）（)参数&…)常量volatile[带(参数={Args…}，(结果=)结果，(Functor=std:)Mem fn，(绑定)参数={std:(占位符，int}]

这是一个GCC错误，我在4.7中修复了它，但我不记得到底是哪个错误。我会设法弄明白的

Edit:Aha，4.7中没有固定，它只固定在GCC主干上（将是4.8）

---

错误在于

mem_fn

返回的调用包装器不接受右值，并且您的

std:：functionTry
std:：bind（&Foo:：Bar，f.get（），1）
我认为这应该计算为Bar（1）@user814628，这如何帮助将
f1
传递到
X
？
void X(std::function<void(const std::shared_ptr<Foo>&)> f)