C++ 通过重载+添加分数;运算符使用具有私有数据成员的类
首先,这是一个家庭作业。我只是需要一些帮助 解决与分数运算符+()函数相关的问题。在函数BinaryMathTest中,应该将数组中的两个分数相加,但是分数::运算符+()函数只返回分母C++ 通过重载+添加分数;运算符使用具有私有数据成员的类,c++,class,operator-overloading,private-members,fractions,C++,Class,Operator Overloading,Private Members,Fractions,首先,这是一个家庭作业。我只是需要一些帮助 解决与分数运算符+()函数相关的问题。在函数BinaryMathTest中,应该将数组中的两个分数相加,但是分数::运算符+()函数只返回分母 #include <iostream> #include <string> using namespace std; class Fraction { private: int num,denom; public: Fraction operat
#include <iostream>
#include <string>
using namespace std;
class Fraction
{
private:
int num,denom;
public:
Fraction operator + (const Fraction &right)const;
friend ostream&operator<<(ostream&stream,Fraction obj);
Fraction(int a=0,int b=1){num=a; denom=b;}
};
ostream&operator<<(ostream&stream,Fraction obj)
{
stream<<obj.num<<'/';
stream<<obj.denom;
return stream;
}
Fraction Fraction::operator+(const Fraction &right)const
{
Fraction temp;
Fraction tempo;
Fraction full;
temp.num = ((num*right.denom) + (right.num*denom));
tempo.denom =(denom*right.denom);
full = (temp,tempo);
return full;
}
void BinaryMathTest();
int main()
{
BinaryMathTest();
return 0;
}
void BinaryMathTest()
{
cout << "\n----- Testing binary arithmetic between Fractions\n";
const Fraction fr[] = {Fraction(1, 6), Fraction(1,3),
Fraction(-2,3), Fraction(5), Fraction(-4,3)};
for (int i = 0; i < 4; i++) {
cout << fr[i] << " + " << fr[i+1] << " = " << fr[i] + fr[i+1]
<<endl;}}
/* OUTPUT
----- Testing binary arithmetic between Fractions
1/6 + 1/3 = 0/18
1/3 + -2/3 = 0/9
-2/3 + 5/1 = 0/3
5/1 + -4/3 = 0/3
*/
#包括
#包括
使用名称空间std;
类分数
{
私人:
int num,denom;
公众:
分数运算符+(常数分数&右)常数;
friend ostream&运营商
分数::运算符+()函数只返回分母
#include <iostream>
#include <string>
using namespace std;
class Fraction
{
private:
int num,denom;
public:
Fraction operator + (const Fraction &right)const;
friend ostream&operator<<(ostream&stream,Fraction obj);
Fraction(int a=0,int b=1){num=a; denom=b;}
};
ostream&operator<<(ostream&stream,Fraction obj)
{
stream<<obj.num<<'/';
stream<<obj.denom;
return stream;
}
Fraction Fraction::operator+(const Fraction &right)const
{
Fraction temp;
Fraction tempo;
Fraction full;
temp.num = ((num*right.denom) + (right.num*denom));
tempo.denom =(denom*right.denom);
full = (temp,tempo);
return full;
}
void BinaryMathTest();
int main()
{
BinaryMathTest();
return 0;
}
void BinaryMathTest()
{
cout << "\n----- Testing binary arithmetic between Fractions\n";
const Fraction fr[] = {Fraction(1, 6), Fraction(1,3),
Fraction(-2,3), Fraction(5), Fraction(-4,3)};
for (int i = 0; i < 4; i++) {
cout << fr[i] << " + " << fr[i+1] << " = " << fr[i] + fr[i+1]
<<endl;}}
/* OUTPUT
----- Testing binary arithmetic between Fractions
1/6 + 1/3 = 0/18
1/3 + -2/3 = 0/9
-2/3 + 5/1 = 0/3
5/1 + -4/3 = 0/3
*/
让我们按照该函数中的代码行进行操作,看看会发生什么
Fraction temp; // Creates an object with num = 0, denom = 1
Fraction tempo; // ditto
Fraction full; // ditoo
temp.num = ((num*right.denom) + (right.num*denom)); // Sets the num of temp
tempo.denom =(denom*right.denom); // Sets the denom of tempo
我觉得你不知道下一行会发生什么
full = (temp,tempo);
行的RHS是使用的表达式
它计算temp
并丢弃该值。它计算tempo
并将其分配给full
。在该行之后,full
只有分母,因为tempo
的分子从未从0
更改
// Returns an object whose numerator is zero.
return full;
您可以将该函数简化为:
Fraction Fraction::operator+(const Fraction &right)const
{
int num = ((num*right.denom) + (right.num*denom));
int denom = (denom*right.denom);
return Fraction(num, denom);
}
在上述实现中需要注意的一点是,如果继续添加Fraction
对象,它将快速增加num
和denom
的值。您可以延迟/防止整数溢出,您必须将num
和denom
的值除以它们的值,以减小它们
分数::运算符+()函数只返回分母
#include <iostream>
#include <string>
using namespace std;
class Fraction
{
private:
int num,denom;
public:
Fraction operator + (const Fraction &right)const;
friend ostream&operator<<(ostream&stream,Fraction obj);
Fraction(int a=0,int b=1){num=a; denom=b;}
};
ostream&operator<<(ostream&stream,Fraction obj)
{
stream<<obj.num<<'/';
stream<<obj.denom;
return stream;
}
Fraction Fraction::operator+(const Fraction &right)const
{
Fraction temp;
Fraction tempo;
Fraction full;
temp.num = ((num*right.denom) + (right.num*denom));
tempo.denom =(denom*right.denom);
full = (temp,tempo);
return full;
}
void BinaryMathTest();
int main()
{
BinaryMathTest();
return 0;
}
void BinaryMathTest()
{
cout << "\n----- Testing binary arithmetic between Fractions\n";
const Fraction fr[] = {Fraction(1, 6), Fraction(1,3),
Fraction(-2,3), Fraction(5), Fraction(-4,3)};
for (int i = 0; i < 4; i++) {
cout << fr[i] << " + " << fr[i+1] << " = " << fr[i] + fr[i+1]
<<endl;}}
/* OUTPUT
----- Testing binary arithmetic between Fractions
1/6 + 1/3 = 0/18
1/3 + -2/3 = 0/9
-2/3 + 5/1 = 0/3
5/1 + -4/3 = 0/3
*/
让我们按照该函数中的代码行进行操作,看看会发生什么
Fraction temp; // Creates an object with num = 0, denom = 1
Fraction tempo; // ditto
Fraction full; // ditoo
temp.num = ((num*right.denom) + (right.num*denom)); // Sets the num of temp
tempo.denom =(denom*right.denom); // Sets the denom of tempo
我觉得你不知道下一行会发生什么
full = (temp,tempo);
行的RHS是使用的表达式
它计算temp
并丢弃该值。它计算tempo
并将其分配给full
。在该行之后,full
只有分母,因为tempo
的分子从未从0
更改
// Returns an object whose numerator is zero.
return full;
您可以将该函数简化为:
Fraction Fraction::operator+(const Fraction &right)const
{
int num = ((num*right.denom) + (right.num*denom));
int denom = (denom*right.denom);
return Fraction(num, denom);
}
在上述实现中需要注意的一点是,如果继续添加Fraction
对象,它将快速增加num
和denom
的值。您可以延迟/防止整数溢出,您必须将num
和denom
的值除以它们的值,以减小它们
#包括
#包括
使用名称空间std;
类分数
{
私人:
int num,denom;
满浮;
公众:
分数运算符+(常数分数&右)常数;
friend ostream&operator#包括
#包括
使用名称空间std;
类分数
{
私人:
int num,denom;
满浮;
公众:
分数运算符+(常数分数&右)常数;
friend ostream&运营商