C++ 无法打印缓冲区地址
我想测试以下代码,但是我得到了一个编译错误。让我困惑的是,pd1和pd2的创建和打印方式与pd3和pd4相同,但编译器在我打印时会抱怨pd3和pd4C++ 无法打印缓冲区地址,c++,C++,我想测试以下代码,但是我得到了一个编译错误。让我困惑的是,pd1和pd2的创建和打印方式与pd3和pd4相同,但编译器在我打印时会抱怨pd3和pd4 const int BUF = 512; const int N = 5; char buffer[BUF]; // chunk of memory int main(){ using namespace std; double *pd1, *pd2; int i; cout << "Cal
const int BUF = 512;
const int N = 5;
char buffer[BUF]; // chunk of memory
int main(){
using namespace std;
double *pd1, *pd2;
int i;
cout << "Calling new and placement new:\n";
pd1 = new double[N]; // use heap
pd2 = new (buffer) double[N]; // use buffer array
for (i = 0; i < N; i++)
pd2[i] = pd1[i] = 1000 + 20.0*i;
cout << "Buffer addresses:\n" << " heap: " << pd1 << " static: " << (void *)buffer << endl;
cout << "Buffer contents:\n";
for(i = 0; i < N; i++) {
cout << pd1[i] << " at " << &pd1[i] << "; ";
cout << pd2[i] << " at " << &pd2[i] << endl;
}
cout << "\nCalling new and placement new a second time:\n";
double *pd3, *pd4;
pd3 = new double[N];
pd4 = new (buffer) double[N];
for(i = 0; i < N; i++)
pd4[i] = pd3[i] = 1000 + 20.0 * i;
cout << "Buffer contents:\n";
for (i = 0; i < N; i++) {
cout << pd3[i] < " at " << &pd3[i] << "; ";
cout << pd4[i] < " at " << &pd4[i] << endl;
}
return 0;
}
const int BUF=512;
常数int N=5;
字符缓冲区[BUF];//内存块
int main(){
使用名称空间std;
双倍*pd1,*pd2;
int i;
你能不能少一个符号
cout << pd3[i] < " at " << &pd3[i] << "; ";
cout << pd4[i] < " at " << &pd4[i] << endl;
cout这里缺少一个
cout << pd3[i] < " at " << &pd3[i] << "; ";
cout << pd4[i] < " at " << &pd4[i] << endl;
cout这里缺少一个
cout << pd3[i] < " at " << &pd3[i] << "; ";
cout << pd4[i] < " at " << &pd4[i] << endl;
cout这里缺少一个
cout << pd3[i] < " at " << &pd3[i] << "; ";
cout << pd4[i] < " at " << &pd4[i] << endl;
cout你只放一个你只放一个你只放一个你只放一个Replace'Replace'Replace'Replace'
cout << pd3[i] << " at " << &pd3[i] << "; ";
cout << pd4[i] << " at " << &pd4[i] << endl;