C++ 需要帮助获得无效代码工作，并支付总工资吗

我需要以下代码帮助更正错误。它的主要功能是接收用户工作小时数，然后根据工作小时数背后的逻辑，应用适当的小时费率

#include <iostream>
#include <iomanip>
using namespace std;

//function prototype
void getGrossPay(int regular,
                 int &timeAndHalf,
                 int &doubleTime);

int main()
{   //variables
    const int REG_RATE = 10;
    const int TIME_HALF = 15;
    const int DOUB_TIME = 20;
    int hoursWorked = 0;

    cout << "Please enter your hours worked(press -1 to quit): ";
    cin >> hoursWorked;
    getGrossPay(regular, timeAndHalf, doubleTime);

    while (hoursWorked != -1);
    {
        if(hoursWorked >=1 && hoursWorked <=37)
        {
        getGrossPay(regular);
        cout << "Your gross pay is: $ (press -1 to exit)" << regular << endl;
        cout << "Please enter your hours worked(press -1 to quit): ";
        cin >> hoursWorked;
        }
        else
            if (hoursWorked >=38 && hoursWorked <=50)
        {
            getGrossPay(timeAndHalf);
            cout << "your gross pay is: $(press -1 to exit)" << timeAndHalf << endl;
            cout << "Please enter your hours worked(press -1 to quit): ";
            cin >> hoursWorked;
        }
            else
            if (hoursWorked >=50)
            {
            getGrossPay(doubleTime);
            cout << "your gross pay is: $(press -1 to exit)" << doubleTime << endl;
            cout << "Please enter your hours worked(press -1 to quit): ";
            cin >> hoursWorked;
            }//end if
    }//end while


}// end of main function


    //****function definitions*****
    void getGrossPay(int regular,
                 int &timeAndHalf,int &doubleTime)
    {
        regular = hoursWorked * REG_RATE;
        timeAndHalf = hoursWorked * TIME_HALF;
        doubleTime = hoursWorked * DOUB_TIME;

    } // end getGrossPay function

int main（） {//变量

cout << "Please enter your hours worked(press -1 to quit): " << endl;
cin >> hoursWorked;

while (hoursWorked != -1);
{

    if(hoursWorked >=1 && hoursWorked <=37)
    {
    getGrossPay(regular, timeAndHalf, doubleTime);

    cout << "Your gross pay is: $ (press -1 to exit)" << regular << endl;
    cout << "Please enter your hours worked(press -1 to quit): " << endl;

    cin >> hoursWorked;
    }
    else
        if (hoursWorked >=38 && hoursWorked <=50)
    {
        getGrossPay(regular, timeAndHalf, doubleTime);
        cout << "your gross pay is: $(press -1 to exit)" << timeAndHalf << endl;
        cout << "Please enter your hours worked(press -1 to quit): " << endl;
        cin >> hoursWorked;
    }
        else
        if (hoursWorked >=50)
        {
        getGrossPay(regular, timeAndHalf, doubleTime);
        cout << "your gross pay is: $(press -1 to exit)" << doubleTime << endl;
        cout << "Please enter your hours worked(press -1 to quit): " << endl;
        cin >> hoursWorked;
        }//end if
}//end while

getGrossPay（）

根据定义用3个参数声明。但是，在

main（）

函数中有3个实例，例如：

getGrossPay(regular);

只有一个参数被传递给函数。您需要重新处理函数，因为代码中有许多关于

getGrossPay（）

的逻辑错误

此外，您没有在

main（）

中声明

regular

，而是将其传递给

getGrossPay（）

函数

---

同样，您在

main（）

函数中声明了

DOUB\u TIME

、

REG\u RATE

和

TIME\u HALF

；因此，它在

getGrossPay（）中是不可访问的

函数。

如果GetGrossPay是一个带有三个参数的原型函数，那么如果不给它三个参数，它将无法工作。我建议修改您的函数。

REG\u RATE

，

DOUB\u TIME

，

TIME\u HALF

仅在

main（）中声明

函数；它们对于

getGrossPay（）

是不可访问的。有关代码中的其他错误，请参阅下面的答案。

//****function definitions*****
void getGrossPay(int regular,
             int &timeAndHalf,int &doubleTime)
{
    regular = hoursWorked * REG_RATE;
    timeAndHalf = hoursWorked * TIME_HALF;
    doubleTime = hoursWorked * DOUB_TIME;

} // end getGrossPay function

getGrossPay(regular);