C++ arm64的上下文？

我正在尝试为iOS（armv7、armv7s、arm64）编译

boost:：context

：

错误

jump_arm_aapcs_macho_gas.S:52:18: error: ',' expected
    stmia a1, {v1-v8,sp-lr} @ save V1-V8,SP-LR
                 ^
jump_arm_aapcs_macho_gas.S:53:14: error: register expected
    str lr, [a1,#40] @ save LR as PC
             ^
jump_arm_aapcs_macho_gas.S:69:18: error: invalid variant 'use'
    mov a1, a3 @ use third arg as return value after jump
                 ^
jump_arm_aapcs_macho_gas.S:70:39: error: unexpected token at start of statement
                                    @ and as first arg in context function
                                      ^
jump_arm_aapcs_macho_gas.S:71:18: error: ',' expected
    ldmia a2, {v1-v8,sp-pc} @ restore v1-V8,SP-PC
                 ^

跳臂跳气

.text
.globl _jump_fcontext
.align 2
_jump_fcontext:
    stmia   a1, {v1-v8,sp-lr}       @ save V1-V8,SP-LR
    str     lr, [a1,#40]            @ save LR as PC

#if (defined(__VFP_FP__) && !defined(__SOFTFP__))
    cmp     a4, #0                  @ test if fpu env should be preserved
    beq     1f

    mov     a4, a1
    add     a4, #52
    vstmia  a4, {d8-d15}            @ save S16-S31

    mov     a4, a2
    add     a4, #52
    vldmia  a4, {d8-d15}            @ restore S16-S31
1:
#endif

    mov     a1, a3                  @ use third arg as return value after jump
                                    @ and as first arg in context function
    ldmia   a2, {v1-v8,sp-pc}       @ restore v1-V8,SP-PC

如果我删除了arm64，并将架构设置为仅armv7，那么它会编译，因此代码应该很好

---

有没有办法让它为arm64编译？arm64（AArch64）与ARM32（A32）在指令和寄存器集上都有很大的不同。调用约定（ABI）也不同。您需要重写汇编程序片段。我建议您与开发人员联系，因为您似乎不熟悉自己动手的底层细节。

谢谢！我习惯于看到asm只使用32位和64位的“e”或“r”前缀寄存器。。我有点希望事情会这么简单。我想我会去boost论坛。