C# 如何将json字符串转换为键\值对？

我想在“instanceData”下的\“标记\”之后获取所有键值对，并在“属性”下生成键值对

我有这个

{
  "id": "/subscriptions/1234abcd-ab12-12ab-12ab-abcdfghi1234/Daily_BRSDT_20161214_0000",
  "name": "Daily_BRSDT_20161214_0000",
  "type": "Microsoft.Commerce/UsageAggregate",
  "properties": {
    "subscriptionId": "1234abcd-ab12-12ab-12ab-abcdfghi1234",
    "usageStartTime": "2017-03-08T00:00:00+00:00",
    "usageEndTime": "2017-03-09T00:00:00+00:00",
    "meterName": "Standard IO - File Read Operation Units (in 10,000s)",
    "meterCategory": "Data Management",
    "unit": "10,000s",
    "instanceData": "{\"Microsoft.Resources\":{\"resourceUri\":\"/subscriptions/1234abcd-ab12-12ab-12ab-abcdfghi1234/resourceGroups/default-resource-group67/providers/Microsoft.Storage/storageAccounts/defaultstorage67\",\"location\":\"ussouthcentral\",\"tags\":{\"ProjectName\":\"default Portal\",\"billTo\":\"Technology\",\"component\":\"Persistant Storage\",\"department\":\"Technology\",\"displayName\":\"default Portal Storage Account\",\"enviornment\":\"default\",\"function\":\"Reporting\",\"matterNumber\":\"999999\",\"primaryowner\":\"john@internet.com\",\"productLine\":\"Information Components\",\"secondaryowner\":\"mary@internet.com\",\"version\":\"1.0.0.0\"}}}",
    "meterId": "12345ab-259d-4206-a6ae-12345678abcd",
    "infoFields": {},
    "quantity": 0.0004
  }
}

我想要这个

{
  "id": "/subscriptions/1234abcd-ab12-12ab-12ab-abcdfghi1234/Daily_BRSDT_20161214_0000",
  "name": "Daily_BRSDT_20161214_0000",
  "type": "Microsoft.Commerce/UsageAggregate",
  "properties": {
    "subscriptionId": "1234abcd-ab12-12ab-12ab-abcdfghi1234",
    "usageStartTime": "2017-03-08T00:00:00+00:00",
    "usageEndTime": "2017-03-09T00:00:00+00:00",
    "meterName": "Standard IO - File Read Operation Units (in 10,000s)",
    "meterCategory": "Data Management",
    "unit": "10,000s",
    "instanceData": "{\"Microsoft.Resources\":{\"resourceUri\":\"/subscriptions/1234abcd-ab12-12ab-12ab-abcdfghi1234/resourceGroups/default-resource-group67/providers/Microsoft.Storage/storageAccounts/defaultstorage67\",\"location\":\"ussouthcentral\"}}",
    "ProjectName":"default Portal",
    "billTo":"Technology",
    "component":"Persistant Storage",
    "department":"Technology",
    "displayName":"default Portal Storage Account",
    "enviornment":"default",
    "function":"Reporting",
    "matterNumber":"999999",
    "primaryowner":"john@internet.com",
    "productLine":"Information Components",
    "secondaryowner":"mary@internet.com",
    "version":"1.0.0.0",
    "meterId": "12345ab-259d-4206-a6ae-12345678abcd",
    "infoFields": {},
    "quantity": 0.0004
  }
}

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有没有一个简单的方法来转换这个？我正试图用正则表达式来做这件事，但运气不好。

我建议您看看这样的东西：

实际上，您需要去掉要解析的一个键，并将其重新添加到JSON对象中

NET-Newtonsoft的工具非常适合使用Json。

最简单的方法：

将整个JSON字符串转换为字典或

列表。

获取要拆分的instanceData位，然后将其解析为另一个C#对象

使用某种逻辑将两个对象合并在一起，以确保没有重复的键

将对象序列化回JSON

---

这是一种简单的方法，但不是最有效的方法

用正则表达式？听起来像是噩梦。不要那样做。什么语言？bash、php、java？一定有比regexI更多的东西，我正在用C#编写库，使用Azure资源使用API。。。您需要将json反序列化为它的对象表示形式，或

动态

。然后在“标记”下获取值，并将它们添加到“属性”下的父项中。使用Json.NET，它将使这变得更容易。