C# CreateStreamedFileFromUriAsync:如何传递IRandomAccessStreamReference?
我试图使用C# CreateStreamedFileFromUriAsync:如何传递IRandomAccessStreamReference?,c#,uri,storagefile,C#,Uri,Storagefile,我试图使用StorageFile方法createstreamdfilefromuriasync下载一个文件,但我对irandomaccesstreamreference参数感到困惑。如何传递IRandomAccessStreamReference?这是一个接口。我该怎么办 public static IAsyncOperation<StorageFile> CreateStreamedFileFromUriAsync( string displayNameWithExtens
StorageFile
方法createstreamdfilefromuriasync
下载一个文件,但我对irandomaccesstreamreference
参数感到困惑。如何传递IRandomAccessStreamReference?这是一个接口。我该怎么办
public static IAsyncOperation<StorageFile> CreateStreamedFileFromUriAsync(
string displayNameWithExtension,
Uri uri,
IRandomAccessStreamReference thumbnail
)
公共静态IAsyncOperation CreatedStreamedFileFromuriAsync(
字符串displayNameWithExtension,
乌里,
irandomaccesstreamreference缩略图
)
我找到了答案:
IRandomAccessStreamReference thumbnail =
RandomAccessStreamReference.CreateFromUri(new Uri(remoteUri));
IAsyncOperation<StorageFile> file1 =
StorageFile.CreateStreamedFileFromUriAsync("duyuru.pdf", new Uri(remoteUri), thumbnail);
irandomaccesstreamreference缩略图=
RandomAccessStreamReference.CreateFromUri(新Uri(remoteUri));
IAsyncOperation文件1=
CreateStreamedFileFromUriAsync(“duyuru.pdf”,新Uri(remoteUri),缩略图);
这看起来不是很有意义,我想知道是否有一个全面的CreateStreamedFileFromUriAsync指南