C# 使用和不使用空格C进行解析#

例如，我有一个程序，它计算1+1，中间有一个空格，但是我如何在我的代码中使它也计算1+1，而不计算空格？我在考虑一个正则表达式或分割字符串，但我不能成功

有人能帮我吗

这是我的代码：

private char[] SPACE = new char[] { ' ' };
private void GetAnswer(string clipboardText)
{
    //Loop through all questions and answers//
    foreach (question q in questionList)
    {
        //If we have found an answer that is exactly the same show an Notification//

        //Startwith zoekt naar alle vragen die matchen vanaf het begin van de zin en Endwith alle vragen die matchen vanaf het eind van de zin//
        if (q._question.StartsWith(clipboardText) || q._question.EndsWith(clipboardText))
        {
            ShowNotification(q._question, q._answer);
            break;
        }
    }
    var parts = clipboardText.Split(SPACE);
    var isValid = true;
    Double a, b;

    // Make sure it's format A # B
    if (parts.Length != 3)
        return;

    // Parse first number
    isValid = Double.TryParse(parts[0], out a);
    if (!isValid)
        return;

    var validOperators = new char[] { '+', '-', ':', 'x', '%' };

    // Parse operator
    if (parts[1].Length != 1)
        return;
    var op = parts[1][0];
    if (!validOperators.Contains(op))
        return;

    // Parse 2nd number
    isValid = Double.TryParse(parts[2], out b);
    if (!isValid)
        return;

    // Now calculate the answer
    string answer = null;
    switch (op)
    {
        case '+':
            answer = (a + b).ToString();
            break;
        case '-':
            answer = (a - b).ToString();
            break;
        case ':':
            if (b == 0)
                answer = "NaN";
            else
                answer = (a / b).ToString();
            break;
        case 'x':
            answer = (a * b).ToString();
            break;
        // rekent percentage van een bedrag 
        case '%':
            answer = (a / b * 100).ToString();
            break;
        default:
            throw new InvalidOperationException();
    }

    // Show the answer
    ShowNotification(clipboardText, answer);
}

---

提前谢谢

您可以尝试

var parts=clipboardText.Replace（“，”）这将使您的输出始终没有空格

private static void GetAnswer(string clipboardText)
{
    //Loop through all questions and answers//
    foreach (question q in questionList)
    {
        //If we have found an answer that is exactly the same show an Notification//

        //Startwith zoekt naar alle vragen die matchen vanaf het begin van de zin en Endwith alle vragen die matchen vanaf het eind van de zin//
        if (q._question.StartsWith(clipboardText) || q._question.EndsWith(clipboardText))
        {
            ShowNotification(q._question, q._answer);
            break;
        }
    }

    var parts = clipboardText.Replace(" ", "");
    var isValid = true;
    Double a, b;

    // Make sure it's format A # B

    char? op = null;
    int end;
    var validOperators = new char[] { '+', '-', ':', 'x', '%' };
    // find operator 
    foreach (char oper in validOperators)
    {
        if (parts.Contains(oper))
        {
            end = parts.IndexOf(oper);
            op = oper;
        }
    }
    if (!op.HasValue)
        return;
    // split to argument with op
    var arguments = parts.Split(op.Value);


    // Parse first number
    isValid = Double.TryParse(arguments[0], out a);
    if (!isValid)
        return;




    // Parse 2nd number
    isValid = Double.TryParse(arguments[1], out b);
    if (!isValid)
        return;

    // Now calculate the answer
    string answer = null;
    switch (op)
    {
        case '+':
            answer = (a + b).ToString();
            break;
        case '-':
            answer = (a - b).ToString();
            break;
        case ':':
            if (b == 0)
                answer = "NaN";
            else
                answer = (a / b).ToString();
            break;
        case 'x':
            answer = (a * b).ToString();
            break;
        // rekent percentage van een bedrag 
        case '%':
            answer = (a / b * 100).ToString();
            break;
        default:
            throw new InvalidOperationException();
    }

    // Show the answer
    ShowNotification(clipboardText,answer);
}

实际上，我建议首先尝试从
剪贴簿文本中提取操作符。如果有效，则按其拆分，并在拆分时删除空条目（空格）：

var validOperators = new char[] { '+', '-', ':', 'x', '%' };

char op = validOperators.FirstOrDefault(o => clipboardText.Contains(o));
if (op == default(char))
    return;

var parts = clipboardText.Split(new char[] { op}, StringSplitOptions.RemoveEmptyEntries);

最后一件事是现在你的格式将只是数字！零件将只有2个元素（希望）：

这也意味着取第一个和最后一个数字：

// Parse first number
isValid = Double.TryParse(parts.First(), out a);
if (!isValid)
    return;

// Parse last number
isValid = Double.TryParse(parts.Last(), out b);
if (!isValid)
    return;

不，此时您可以取消运算符转换和检查：

// Parse operator
if (parts[1].Length != 1)
    return;
var op = parts[1][0];
if (!validOperators.Contains(op))
    return;

假设你只有两个数字，这就是解决方案

// this code will work for all of the text mentioned in comments 
//string text = "1 + 1";
//string text = "1+1";
//string text = "100.998+ 2000.7";
//string text = "10       +   2000.7";

        string text = "100+ 2000";
        text = Regex.Replace(text, @"\s+", "");
        double num1 = 0;
        double num2 = 0;
        char operand  ;
        int startIndex = 0;



        for (int i = 0; i < text.Length; i++)
        {
            // look for first operator
            if (isOperator(text[i]) || (i+1) == text.Length) {
                if (startIndex == 0) {
                    double.TryParse(text.Substring(startIndex, i), out num1);
                    operand = text[i];
                    startIndex = i + 1;
                }
                else
                {
                    double.TryParse(text.Substring(startIndex), out num2);
                    break;
                }
            }

        }
        // calculate(num1,operand,num2) // Implement this method with a simple switch case and this will calculate the final answer for you 

OP正在空间上拆分字符串。删除空格将强制对代码进行另一次更改。@Kazkans我在执行
var parts=clipboardText.Replace（“，”）时遇到了一系列错误
因为我的代码没有将字符转换成字符串，你能帮我吗？@rrwe编辑了答案，它现在可以在任意数量的空格上工作
// this code will work for all of the text mentioned in comments 
//string text = "1 + 1";
//string text = "1+1";
//string text = "100.998+ 2000.7";
//string text = "10       +   2000.7";

        string text = "100+ 2000";
        text = Regex.Replace(text, @"\s+", "");
        double num1 = 0;
        double num2 = 0;
        char operand  ;
        int startIndex = 0;



        for (int i = 0; i < text.Length; i++)
        {
            // look for first operator
            if (isOperator(text[i]) || (i+1) == text.Length) {
                if (startIndex == 0) {
                    double.TryParse(text.Substring(startIndex, i), out num1);
                    operand = text[i];
                    startIndex = i + 1;
                }
                else
                {
                    double.TryParse(text.Substring(startIndex), out num2);
                    break;
                }
            }

        }
        // calculate(num1,operand,num2) // Implement this method with a simple switch case and this will calculate the final answer for you 

 public static bool isOperator(char opt) {
            switch (opt)
            {
                case '+':
                    return true;
                case '-':
                    return true;
                case '*':
                    return true;
                case '/':
                    return true;
                default:
                    return false;
            }
        }