C# WCF REST：我的XML在请求中应该是什么样子？

我的WCF服务中有以下方法：

[OperationContract]
[WebInvoke(Method = "POST", BodyStyle = WebMessageBodyStyle.Bare, ResponseFormat = WebMessageFormat.Xml, RequestFormat = WebMessageFormat.Xml)]
public int GetOne(string param1, string param2)
{
    return 1;
}

我从Flex应用程序发送xml，它接受如下对象：

{param1:“test”，param2:“test2”}

，并将其转换为以下请求：

POST http://localhost:8012/MyService.svc/GetOne HTTP/1.1
Accept: application/xml
Accept-Language: en-US
x-flash-version: 10,1,53,64
Content-Type: application/xml
Content-Length: 52
Accept-Encoding: gzip, deflate
User-Agent: Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.1; WOW64; Trident/5.0)
Host: localhost:8012
Connection: Keep-Alive
Pragma: no-cache
Cookie: ASP.NET_SessionId=drsynacw0ignepk4ya4pou23

<param1>something</param1><param2>something</param2>

---

有效的XML必须有一个根元素。WCF REST中也没有将XML元素映射到字符串参数的神奇之处。可以将XElement作为操作参数

[OperationContract]
[WebInvoke(Method = "POST", BodyStyle = WebMessageBodyStyle.Bare, ResponseFormat = WebMessageFormat.Xml, RequestFormat = WebMessageFormat.Xml)]
public int GetOne(XElement content)
{
    string param1 = content.Elements().First(element => element.Name == "param1").Value;
    string param2 = content.Elements().First(element => element.Name == "param2").Value;

    return 1;
}

您发送的数据类似于：

<parameters>
    <param1>something</param1>
    <param2>something</param2>
</parameters>

某物
某物

我不认为可以通过

POST

操作为框架传递两个参数来自动反序列化它。您已经尝试了以下几种方法：

将您的WCF方法定义如下：

[OperationContract]
[WebInvoke(Method = "POST", 
    BodyStyle = WebMessageBodyStyle.Bare, 
    ResponseFormat = WebMessageFormat.Xml, 
    RequestFormat = WebMessageFormat.Xml, 
    URITemplate="/GetOne/{param1}")]
public int GetOne(string param1, string param2)
{
    return 1;
}

POST http://localhost/SampleService/RestService/ValidateUser/myparam1 HTTP/1.1
User-Agent: Fiddler
Content-Type: application/xml
Host: localhost
Content-Length: 86

<string xmlns="http://schemas.microsoft.com/2003/10/Serialization/">my param2</string>

[OperationContract]
[WebInvoke(Method = "POST", 
    BodyStyle = WebMessageBodyStyle.WrappedRequest, 
    ResponseFormat = WebMessageFormat.Json, 
    RequestFormat = WebMessageFormat.Json)]
public int GetOne(string param1, string param2)
{
    return 1;
}

[OperationContract]
[WebInvoke(Method="POST", 
    BodyStyle=WebMessageBodyStyle.WrappedRequest, 
    ResponseFormat=WebMessageFormat.Xml, 
    RequestFormat= WebMessageFormat.Xml)]
public int GetOne(string param1, string param2)
{
   return 1;
}

您的原始POST请求如下所示：

[OperationContract]
[WebInvoke(Method = "POST", 
    BodyStyle = WebMessageBodyStyle.Bare, 
    ResponseFormat = WebMessageFormat.Xml, 
    RequestFormat = WebMessageFormat.Xml, 
    URITemplate="/GetOne/{param1}")]
public int GetOne(string param1, string param2)
{
    return 1;
}

POST http://localhost/SampleService/RestService/ValidateUser/myparam1 HTTP/1.1
User-Agent: Fiddler
Content-Type: application/xml
Host: localhost
Content-Length: 86

<string xmlns="http://schemas.microsoft.com/2003/10/Serialization/">my param2</string>

[OperationContract]
[WebInvoke(Method = "POST", 
    BodyStyle = WebMessageBodyStyle.WrappedRequest, 
    ResponseFormat = WebMessageFormat.Json, 
    RequestFormat = WebMessageFormat.Json)]
public int GetOne(string param1, string param2)
{
    return 1;
}

[OperationContract]
[WebInvoke(Method="POST", 
    BodyStyle=WebMessageBodyStyle.WrappedRequest, 
    ResponseFormat=WebMessageFormat.Xml, 
    RequestFormat= WebMessageFormat.Xml)]
public int GetOne(string param1, string param2)
{
   return 1;
}

现在，您的原始请求应该如下所示：

POST http://localhost/SampleService/RestService/ValidateUser HTTP/1.1
User-Agent: Fiddler
Content-Type: application/json
Host: localhost
Content-Length: 86

{"param1":"my param1","param2":"my param 2"}

将您的WCF REST方法更改为如下所示：

[OperationContract]
[WebInvoke(Method = "POST", 
    BodyStyle = WebMessageBodyStyle.Bare, 
    ResponseFormat = WebMessageFormat.Xml, 
    RequestFormat = WebMessageFormat.Xml, 
    URITemplate="/GetOne/{param1}")]
public int GetOne(string param1, string param2)
{
    return 1;
}

POST http://localhost/SampleService/RestService/ValidateUser/myparam1 HTTP/1.1
User-Agent: Fiddler
Content-Type: application/xml
Host: localhost
Content-Length: 86

<string xmlns="http://schemas.microsoft.com/2003/10/Serialization/">my param2</string>

[OperationContract]
[WebInvoke(Method = "POST", 
    BodyStyle = WebMessageBodyStyle.WrappedRequest, 
    ResponseFormat = WebMessageFormat.Json, 
    RequestFormat = WebMessageFormat.Json)]
public int GetOne(string param1, string param2)
{
    return 1;
}

[OperationContract]
[WebInvoke(Method="POST", 
    BodyStyle=WebMessageBodyStyle.WrappedRequest, 
    ResponseFormat=WebMessageFormat.Xml, 
    RequestFormat= WebMessageFormat.Xml)]
public int GetOne(string param1, string param2)
{
   return 1;
}

现在，您的原始请求如下所示：

POST http://localhost/SampleService/RestService/ValidateUser HTTP/1.1
User-Agent: Fiddler
Content-Type: application/xml
Host: localhost
Content-Length: 116

<ValidateUser xmlns="http://tempuri.org/"><Username>my param1</Username><Password>myparam2</Password></ValidateUser>

POSThttp://localhost/SampleService/RestService/ValidateUser HTTP/1.1
用户代理：Fiddler
内容类型：application/xml
主机：本地主机
内容长度：116
我的心上人

---

将响应格式设置为xml，并将JSON格式的输入作为

{param1:test]，param2:test2}

？这个oKI也要指出，{param1:“test”，param2:“test2”'不是您声称要发送数据的XML格式。提供用于调用服务的Flex代码可能会有所帮助。@WaqarJanjua:这是Flex对象表示法。它被序列化为您在我发布的请求中看到的XML。好的，1个问题，方法GetOne返回一个整数，但您设置了method=“POST”在webinvoke属性中？它不应该是Get？@www.Flextras.com:发布了服务调用，但即使在Fiddler中处理了请求，我也无法让它识别为XML。您最后的建议就是我所做的。我只需要在Flex端写一些东西，以便在之前总是用方法名包装参数正在做最后的请求。谢谢！