C# 单击按钮，打开xml文件，将数据显示到文本框

我在windows窗体应用程序中单击一个按钮，它会打开一个文件打开框。我单击要打开的xml文件，并希望数据填充windows窗体中的文本字段，但我得到System.ArgumentException:“路径中的非法字符。”代码的FileStream行出现错误

private void button2_Click(object sender, EventArgs e)
{
    // On click Open the file
    if (openFileDialog1.ShowDialog() == DialogResult.OK)
    {
        StreamReader sr = new StreamReader(openFileDialog1.FileName);
        XmlSerializer serializer = new XmlSerializer(typeof(ContactLead));

        // Save file contents to variable
        var fileResult = sr.ReadToEnd();
        FileStream myFileStream = new FileStream(fileResult, FileMode.Open, FileAccess.Read, FileShare.Read);

        ContactLead contactLead = (ContactLead)serializer.Deserialize(myFileStream);

        this.textboxFirstName.Text = contactLead.firstname;
        this.textboxLastName.Text = contactLead.lastname;
        this.textboxEmail.Text = contactLead.email;
    }
}

这就是你的问题：

var fileResult = sr.ReadToEnd();
FileStream myFileStream = new FileStream(fileResult, FileMode.Open, FileAccess.Read, FileShare.Read);

您正在读取一个文件的内容，然后将该文件的内容用作文件流的文件名。当然，该文件的XML内容在Windows或任何操作系统上都不是有效的文件名

我怀疑你真的只是想这么做：

private void button2_Click(object sender, EventArgs e)
{
    // On click Open the file
    if (openFileDialog1.ShowDialog() == DialogResult.OK)
    {
        // open the file for reading
        using (FileStream myFileStream = new FileStream(openFileDialog1.FileName, FileMode.Open, FileAccess.Read, FileShare.Read))
        {
            XmlSerializer serializer = new XmlSerializer(typeof(ContactLead));
            // deserialize the contact from the open file stream
            ContactLead contactLead = (ContactLead)serializer.Deserialize(myFileStream);

            this.textboxFirstName.Text = contactLead.firstname;
            this.textboxLastName.Text = contactLead.lastname;
            this.textboxEmail.Text = contactLead.email;
        }
    }
}

我已经在文件流中添加了一个using，这样在您读取完文件流后，它就会被正确地处理掉，否则C将保持文件的打开状态