C# 绘制具有多个孔的多边形?
我想画一个有多个洞的多边形。我尝试了以下代码,但无法正常工作。请告知C# 绘制具有多个孔的多边形?,c#,c++,gdi+,gdi,C#,C++,Gdi+,Gdi,我想画一个有多个洞的多边形。我尝试了以下代码,但无法正常工作。请告知 PointF[] mypoly = new PointF[6 + 5 + 5]; mypoly[0] = new PointF(0, 0); mypoly[1] = new PointF(100, 0); mypoly[2] = new PointF(100, 100); mypoly[3] = new PointF(0, 100); mypoly[4] = new Point
PointF[] mypoly = new PointF[6 + 5 + 5];
mypoly[0] = new PointF(0, 0);
mypoly[1] = new PointF(100, 0);
mypoly[2] = new PointF(100, 100);
mypoly[3] = new PointF(0, 100);
mypoly[4] = new PointF(10, 80);
mypoly[5] = new PointF(0, 0);
mypoly[6] = new PointF(10, 10);
mypoly[7] = new PointF(10, 20);
mypoly[8] = new PointF(20, 20);
mypoly[9] = new PointF(20, 10);
mypoly[10] = new PointF(10, 10);
mypoly[11] = new PointF(40, 10);
mypoly[12] = new PointF(40, 20);
mypoly[13] = new PointF(60, 20);
mypoly[14] = new PointF(60, 10);
mypoly[15] = new PointF(40, 10);
g.FillPolygon(new SolidBrush(Color.Red), mypoly, FillMode.Winding);
第一部分是外多边形。第二部分和第三部分是多边形内的两个孔。使用
图形SPATH
。您可以使用Graphics.FillPath
绘制它,如下所示:
using System.Drawing.Drawing2D;
...
using (var gp = new GraphicsPath()) {
PointF[] outer = new PointF[] { new PointF(0, 0), new PointF(100, 0),
new PointF(100, 100), new PointF(0, 100), new PointF(10, 80),new PointF(0, 0) };
gp.AddPolygon(outer);
PointF[] inner1 = new PointF[] { new PointF(10, 10), new PointF(10, 20),
new PointF(20, 20), new PointF(20, 10), new PointF(10, 10) };
gp.AddPolygon(inner1);
PointF[] inner2 = new PointF[] { new PointF(40, 10), new PointF(40, 20),
new PointF(60, 20), new PointF(60, 10), new PointF(40, 10) };
gp.AddPolygon(inner2);
e.Graphics.FillPath(Brushes.Black, gp);
}
你得到了什么?有什么原因不能是3个单独的多边形吗?你尝试了什么填充模式?这控制了交集的渲染方式。为什么不用一种颜色绘制外部多边形,用“背景”颜色绘制内部多边形呢?在阅读您的答案之前,我已经找到了一个解决方案。它就在Microsoft网站的FillPath参考页上。他们的答案和你的一样。