c#使用linq反转和序列化词典
想知道是否可以在一个LINQ语句中反转字典 结构如下:c#使用linq反转和序列化词典,c#,linq,C#,Linq,想知道是否可以在一个LINQ语句中反转字典 结构如下: Dictionary<string, List<string>> original = new Dictionary<string, List<string>>() { {"s", new List<string>() { "1", "2", "3" }}, {"m", new List<string>() { "4", "5"
Dictionary<string, List<string>> original = new Dictionary<string, List<string>>()
{
{"s", new List<string>() { "1", "2", "3" }},
{"m", new List<string>() { "4", "5", "6" }},
{"l", new List<string>() { "7", "8", "9" }},
{"xl", new List<string>() { "10", "11", "12" }},
};
Dictionary original=new Dictionary()
{
{“s”,新列表(){“1”,“2”,“3”},
{“m”,新列表(){“4”、“5”、“6”},
{“l”,新列表(){“7”,“8”,“9”},
{“xl”,新列表(){“10”、“11”、“12”},
};
我想把它转换成一本类型的字典
Dictionary<string, string> Reverse = new Dictionary<string, string>()
{
{"1", "s"},
{"2", "s"}, //and so on
};
Dictionary Reverse=new Dictionary()
{
{“1”,“s”},
{“2”、“s”}、//等等
};
如果您这样做:
var reversed = original.SelectMany(x => x.Value.Select(y => new KeyValuePair<string, string>(y, x.Key)));
var reversed=original.SelectMany(x=>x.Value.Select(y=>newkeyvaluepair(y,x.Key));
然后你会得到:
1-s
2-s
3-s
4米
5米
等等。类似于:
var result = (from kvp in original
from value in kvp.Value
select new {Key = value, Value = kvp.Key}).ToDictionary(a => a.Key, a => a.Value);
或者,如果您更喜欢方法语法:
var result = original.SelectMany(kvp => kvp.Value.Select(v => new {Key = v, Value = kvp.Key}))
.ToDictionary(a => a.Key, a => a.Value);
为此,您可以使用
SelectMany
LINQ扩展方法:
var original = new Dictionary<string, List<string>>
{
{ "s", new List<string> { "1", "2", "3" } },
{ "m", new List<string> { "4", "5", "6" } },
{ "l", new List<string> { "7", "8", "9" } },
{ "xl", new List<string> { "10", "11", "12" } },
};
var keyValuePairs = original.SelectMany(o => o.Value.Select(v => new KeyValuePair<string, string>(v, o.Key)));
var original=新字典
{
{“s”,新列表{“1”、“2”、“3”},
{“m”,新列表{“4”、“5”、“6”},
{“l”,新列表{“7”、“8”、“9”},
{“xl”,新名单{“10”、“11”、“12”},
};
var keyValuePairs=original.SelectMany(o=>o.Value.Select(v=>newkeyvaluepair(v,o.Key));
您可以使用SelectMany
拆分值子列表,然后使用ToDictionary将键和值反转到新词典中
var result = original
.SelectMany(k=> k.Value.Select(v => new { Key = v, Value = k.Key } ))
.ToDictionary( t=> t.Key, t=> t.Value);