C# Winforms控件赢得';t显示
我正在从另一个Winforms对象(应该是一个简单的加载窗口)中调用Winforms窗口,但是当调用window.Show()时,我看到的是: 顶部空间应该是带有“等待”文本的标签,底部应该是动画GIF。我已逐步验证是否为此对象调用了InitializeComponent()。下面是调用它的代码:C# Winforms控件赢得';t显示,c#,winforms,C#,Winforms,我正在从另一个Winforms对象(应该是一个简单的加载窗口)中调用Winforms窗口,但是当调用window.Show()时,我看到的是: 顶部空间应该是带有“等待”文本的标签,底部应该是动画GIF。我已逐步验证是否为此对象调用了InitializeComponent()。下面是调用它的代码: LoadWindow loading = new LoadWindow(); loading.Show(); loading.BringToFront
LoadWindow loading = new LoadWindow();
loading.Show();
loading.BringToFront();
//Perform loading function in background worker
//BackgroundWorker worker = new BackgroundWorker();
//worker.DoWork += new DoWorkEventHandler(worker_DoWork);
//worker.RunWorkerAsync();
// Close the loading window
System.Threading.Thread.Sleep(10000);
loading.Close();
暂停是为了调试目的,正如您所看到的,在我试图弄清楚这一点的时候,后台工作程序暂时没有运行。有人对如何正确显示此窗口有什么建议吗?您可以通过调用
Thread.Sleep()
冻结UI线程。因此控件不能使其布局无效。
我猜,load.Close()
的调用必须在BackgroundWorker.RunWorkerCompleted
事件中
private void Show()
{
LoadWindow loading = new LoadWindow();
loading.Show();
loading.BringToFront();
BackgroundWorker worker = new BackgroundWorker();
worker.DoWork += new DoWorkEventHandler(
(s, e) =>
{
// your logic
Thread.Sleep(10000);
});
worker.RunWorkerCompleted += new RunWorkerCompletedEventHandler(
(s, e) =>
{
loading.Close();
});
worker.RunWorkerAsync();
}
通过调用
Thread.Sleep()
冻结UI线程。因此控件不能使其布局无效。
我猜,load.Close()
的调用必须在BackgroundWorker.RunWorkerCompleted
事件中
private void Show()
{
LoadWindow loading = new LoadWindow();
loading.Show();
loading.BringToFront();
BackgroundWorker worker = new BackgroundWorker();
worker.DoWork += new DoWorkEventHandler(
(s, e) =>
{
// your logic
Thread.Sleep(10000);
});
worker.RunWorkerCompleted += new RunWorkerCompletedEventHandler(
(s, e) =>
{
loading.Close();
});
worker.RunWorkerAsync();
}
我猜你的问题是在UI线程中调用
Thread.Sleep(10000)
一个可能的解决办法是:
public void LoadSomething()
{
LoadWindow loading = new LoadWindow();
loading.Show();
loading.BringToFront();
BackgroundWorker worker = new BackgroundWorker();
worker.DoWork += new DoWorkEventHandler(worker_DoWork);
worker.RunWorkerCompleted += WorkerOnRunWorkerCompleted;
worker.RunWorkerAsync(loading)
}
private void worker_DoWork(object sender, DoWorkEventArgs e)
{
// Do your background-work here
Thread.Sleep(10000);
e.Result = e.Argument;
}
private void WorkerOnRunWorkerCompleted(object sender, RunWorkerCompletedEventArgs e)
{
LoadWindow loading= (LoadWindow)e.Result;
loading.Close();
}
我猜你的问题是在UI线程中调用
Thread.Sleep(10000)
一个可能的解决办法是:
public void LoadSomething()
{
LoadWindow loading = new LoadWindow();
loading.Show();
loading.BringToFront();
BackgroundWorker worker = new BackgroundWorker();
worker.DoWork += new DoWorkEventHandler(worker_DoWork);
worker.RunWorkerCompleted += WorkerOnRunWorkerCompleted;
worker.RunWorkerAsync(loading)
}
private void worker_DoWork(object sender, DoWorkEventArgs e)
{
// Do your background-work here
Thread.Sleep(10000);
e.Result = e.Argument;
}
private void WorkerOnRunWorkerCompleted(object sender, RunWorkerCompletedEventArgs e)
{
LoadWindow loading= (LoadWindow)e.Result;
loading.Close();
}
如果你删除了Sleep(),你能不能把你的代码发布到那个
BackgroundWorker
上。同时发布worker\u DoWork
-方法尝试删除Sleep()
并通过loading
的BeginInvoke()
添加loading.Update()从worker\u DoWork
调用Close()
;是一个解决这个问题的黑客。不要将UI线程置于睡眠状态。加载.Show()
在线程中运行?如果删除睡眠(),会怎么样?请发布您的代码与BackgroundWorker
的外观。同时发布worker\u DoWork
-方法尝试删除Sleep()
并通过loading
的BeginInvoke()
添加loading.Update()从worker\u DoWork
调用Close()
;是一个解决这个问题的黑客。不要将UI线程置于睡眠状态。加载.Show()
在线程中运行?谢谢Tomtom!我无法让(LoadWindow)e.Result工作,所以我唯一的选择就是加载一个全局变量(bleah),或者使用al amanat的建议并使用lambda。谢谢Tom!我无法让(LoadWindow)e.Result工作,所以我唯一的选择是让加载一个全局变量(bleah)或使用al-amanat的建议并使用lambda。