C# 计算器问题:我只输入了第二个值
我创建了一个基本的计算器,但每次输入第二个值并按下“相等”按钮时,都没有返回结果。只有我输入的值是2。 我的+-*/方法在一个单独的类中。解决这个问题的最好办法是什么?这可能是个简单的错误,但我找不到。你能给我解释一下我做错了什么吗。提前谢谢C# 计算器问题:我只输入了第二个值,c#,calculator,C#,Calculator,我创建了一个基本的计算器,但每次输入第二个值并按下“相等”按钮时,都没有返回结果。只有我输入的值是2。 我的+-*/方法在一个单独的类中。解决这个问题的最好办法是什么?这可能是个简单的错误,但我找不到。你能给我解释一下我做错了什么吗。提前谢谢 public sealed partial class Calculator : Page { public double num01, num02; int operater; public Calculator() {
public sealed partial class Calculator : Page
{
public double num01, num02;
int operater;
public Calculator()
{
this.InitializeComponent();
}
private void btn1_Click(object sender, RoutedEventArgs e)
{
txtcalcdisplay.Text =txtcalcdisplay.Text+ "1";
}
private void btn2_Click(object sender, RoutedEventArgs e)
{
txtcalcdisplay.Text = txtcalcdisplay.Text + "2";
}
private void btn3_Click(object sender, RoutedEventArgs e)
{
txtcalcdisplay.Text = txtcalcdisplay.Text + "3";
}
private void btn4_Click(object sender, RoutedEventArgs e)
{
txtcalcdisplay.Text = txtcalcdisplay.Text + "4";
}
private void btn5_Click(object sender, RoutedEventArgs e)
{
txtcalcdisplay.Text = txtcalcdisplay.Text + "5";
}
private void btn6_Click(object sender, RoutedEventArgs e)
{
txtcalcdisplay.Text = txtcalcdisplay.Text + "6";
}
private void btn7_Click(object sender, RoutedEventArgs e)
{
txtcalcdisplay.Text = txtcalcdisplay.Text + "7";
}
private void btn8_Click(object sender, RoutedEventArgs e)
{
txtcalcdisplay.Text = txtcalcdisplay.Text + "8";
}
private void btn9_Click(object sender, RoutedEventArgs e)
{
txtcalcdisplay.Text = txtcalcdisplay.Text + "9";
}
private void Clear_Click(object sender, RoutedEventArgs e)
{
txtcalcdisplay.Text = string.Empty;
}
private void btnsubtract_Click(object sender, RoutedEventArgs e)
{
num01 = Convert.ToDouble(txtcalcdisplay.Text);
txtcalcdisplay.Text = "";
operater = '1';
}
private void btnadd_Click(object sender, RoutedEventArgs e)
{
num01 = Convert.ToDouble(txtcalcdisplay.Text);
txtcalcdisplay.Text = "";
operater = '2';
}
private void btnmultiply_Click(object sender, RoutedEventArgs e)
{
num01 = Convert.ToDouble(txtcalcdisplay.Text);
txtcalcdisplay.Text = "";
operater = '3';
}
private void btndivide_Click(object sender, RoutedEventArgs e)
{
num01 = Convert.ToDouble(txtcalcdisplay.Text);
txtcalcdisplay.Text = "";
operater = '4';
}
private void btnequals_Click(object sender, RoutedEventArgs e)
{
switch (operater)
{
case 1:
num02 = Convert.ToDouble(txtcalcdisplay.Text);
CalculationClass sub = new CalculationClass();
double answer= sub.Subtract(num01, num02);
txtcalcdisplay.Text = answer.ToString();
break;
case 2:
num02 = Convert.ToDouble(txtcalcdisplay.Text);
CalculationClass add = new CalculationClass();
answer= add.Addition(num01, num02);
txtcalcdisplay.Text = answer.ToString();
break;
case 3:
num02 = Convert.ToDouble(txtcalcdisplay.Text);
CalculationClass mult = new CalculationClass();
answer = mult.Multiply(num01, num02);
txtcalcdisplay.Text = answer.ToString();
break;
case 4:
num02 = Convert.ToDouble(txtcalcdisplay.Text);
CalculationClass div = new CalculationClass();
answer = div.Div(num01, num02);
txtcalcdisplay.Text = Convert.ToString(answer);
break;
}
}
private void btnback_Click(object sender, RoutedEventArgs e)
{
}
private void btnplusdivideminus_Click(object sender, RoutedEventArgs e)
{
}
private void btncomma_Click(object sender, RoutedEventArgs e)
{
}
private void btngallery_Click(object sender, RoutedEventArgs e)
{
}
private void btncontact_Click(object sender, RoutedEventArgs e)
{
}
private void num0_Click(object sender, RoutedEventArgs e)
{
txtcalcdisplay.Text += "0";
num01 = Convert.ToDouble(txtcalcdisplay.Text);
}
}
class CalculationClass
{
double answer;
public double Addition(double x, double y)
{
answer = x + y;
return answer;
}
public double Subtract(double x, double y)
{
answer = x - y;
return answer;
}
public double Multiply(double x, double y)
{
answer = x * y;
return answer;
}
public double Div(double x, double y)
{
answer = x / y;
return answer;
}
}
我不是100%确定,但我相当肯定这与变量
运算符是int
这一事实有关,但您正在为它分配一个字符(这很有效-可以将字符分配给int),然后将其与整数进行比较(例如执行1='1'
)
因此,要解决此问题,请使用交换机中的字符:
switch(operater){
case '1': ...
}
或者指定整数1,2,3,4,而不是字符“1”、“2”、“3”和“4”
private void btnadd_Click(object sender, RoutedEventArgs e)
{
num01 = Convert.ToDouble(txtcalcdisplay.Text);
txtcalcdisplay.Text = "";
operater = 2; // here
}
因此,在运算符单击处理程序(用于+、-、*、/等的处理程序)中,您正在将运算符变量设置为字符'1'
,'2'
,等等。嗯,运算符变量是一个int。但是,等等,您不应该能够将字符分配给int
?!编译器在这里进行隐式转换()
因此,当您执行operater='1'
时,结果是operater
被分配了49('1'
的ASCII值)。然后,当您到达equals按钮单击处理程序时,它会点击那个switch语句。你猜怎么着?你没有49岁的理由。所以什么也没发生,你一直在屏幕上看到你的第二个数字
因此,要修复它,请删除运算符处理程序中分配给operater
的数字周围的单引号。即:
private void btnsubtract_Click(object sender, RoutedEventArgs e)
{
num01 = Convert.ToDouble(txtcalcdisplay.Text);
txtcalcdisplay.Text = "";
operater = 1; // <-- change this line to be like this, removed the single quotes
}
private void btnsubtract\u单击(对象发送方,路由目标)
{
num01=Convert.ToDouble(txtcdalcdisplay.Text);
txtcdcdisplay.Text=“”;
operater=1;//最好的办法是弹出调试器,在事件处理程序上为equals按钮设置一个断点,然后逐步执行操作。是的,如果不使用XAML,很难看到可能出现错误的地方。是否所有运算符都会发生此错误(即,加法、减法、乘法和除法),还是只有一个?如果是,哪一个?请尝试提供一个。这可能表明了您的错误,并使我们更容易查看您的问题(如果问题仍然存在)。顺便说一句,谢谢,您拼写的“operator”错误。这不是问题的根源,但这足以困扰我提及它。是的,所有的operator都会出现这种情况。
private void btnsubtract_Click(object sender, RoutedEventArgs e)
{
num01 = Convert.ToDouble(txtcalcdisplay.Text);
txtcalcdisplay.Text = "";
operater = 1; // <-- change this line to be like this, removed the single quotes
}