C# 如何从另一个线程（即与GUI线程同步）访问WinForms控件？

我正在开发C#winforms应用程序，我需要知道如何通过更改复选框值将代码制作成线程

 new Thread(() =>
        {
            Thread.CurrentThread.IsBackground = true;

            TcpListener server = null;
            while (true)
            {
                if(){}else{}// here I need to check my checkbox
}}).Start();

您可以使用以下选项：

new Thread(() =>
{
  Thread.CurrentThread.IsBackground = true;

  TcpListener server = null;

  while (true)
  {
    ...
    this.SynUI(()=>
    {
      if ( checkbox.Checked )
      {
      }
    });
    ...
  }
}).Start();

或：

具有：

static public class SyncUIHelper
{
  static public Thread MainThread { get; private set; }

  // Must be called from the Program.Main or the Main Form constructor for example
  static public void Initialize()
  {
    MainThread = Thread.CurrentThread;
  }

  static public void SyncUI(this Control control, Action action, bool wait = true)
  {
    if ( !Thread.CurrentThread.IsAlive ) throw new ThreadStateException();
    Exception exception = null;
    Semaphore semaphore = null;
    Action processAction = () =>
    {
      try { action(); }
      catch ( Exception except ) { exception = except; }
    };
    Action processActionWait = () =>
    {
      processAction();
      if ( semaphore != null ) semaphore.Release();
    };
    if ( control != null
      && control.InvokeRequired
      && Thread.CurrentThread != MainThread )
    {
      if ( wait ) semaphore = new Semaphore(0, 1);
      control.BeginInvoke(wait ? processActionWait : processAction);
      if ( semaphore != null ) semaphore.WaitOne();
    }
    else
      processAction();
    if ( exception != null ) throw exception;
  }

}

在应用程序之前添加Program.Main。运行：

SyncUIHelper.Initialize();

您可以在堆栈溢出上找到各种方法来将线程与UI线程同步，如：

也有BackgroundWorker。

请阅读以了解堆栈溢出的工作原理，并阅读如何提高问题的质量。然后，你的问题包括你的完整源代码，你有作为一个，它可以被编译和测试的其他人。

SyncUIHelper.Initialize();