C# PathGeometry.FillContainsWithDetail（）始终返回IntersectionDetail.Empty

下面的代码始终可以访问IntersectionDetail.Empty，但也可以访问FullyContains或FullyInside。为什么?

Path p1; // filled with a polygon
Path p2; // filled with another polygon

PathGeometry pg1 = p1.RenderedGeometry.GetFlattenedPathGeometry().GetWidenedPathGeometry(new Pen(new SolidColorBrush(), 1)).GetOutlinedPathGeometry(1, ToleranceType.Absolute);
pg1.FillRule = FillRule.EvenOdd;

PathGeometry pg2 = p2.RenderedGeometry.GetFlattenedPathGeometry().GetWidenedPathGeometry(new Pen(new SolidColorBrush(), 1)).GetOutlinedPathGeometry(1, ToleranceType.Absolute);
pg2.FillRule = FillRule.EvenOdd;

IntersectionDetail id = pg1.FillContainsWithDetail(pg2);
if (id == IntersectionDetail.FullyContains) // never reached but should
if (id == IntersectionDetail.FullyInside) //never reached but should
if (id == IntersectionDetail.Intersect) // always reached (edit: found a bug no more the error case)
if (id == IntersectionDetail.Empty) // edit: after bug fix now always reached

多边形被绘制到屏幕上，所以我可以说这应该真正达到案例FullyContains/FullyInside。 有什么办法让它工作吗

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编辑：由我自己解决，请参见下面的答案。

看来GetWideedPathGeometry和GetOutlinedPathGeometry以某种方式操纵PathGeometry，使交叉点变为空。删除这些后，只需调用GetFlattedPathGeometry，我的代码就能按预期运行良好

以下是固定代码：

Path p1; // filled with a polygon
Path p2; // filled with another polygon

PathGeometry pg1 = p1.RenderedGeometry.GetFlattenedPathGeometry();
pg1.FillRule = FillRule.EvenOdd;

PathGeometry pg2 = p2.RenderedGeometry.GetFlattenedPathGeometry();
pg2.FillRule = FillRule.EvenOdd;

IntersectionDetail id = pg1.FillContainsWithDetail(pg2);
if (id == IntersectionDetail.FullyContains) // now reached as expected
if (id == IntersectionDetail.FullyInside) // now reached as expected
if (id == IntersectionDetail.Intersect)
if (id == IntersectionDetail.Empty)

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您是否已将

pg1

和

pg2

放入另外两个路径控件中，并对它们进行了目视检查？谢谢，这帮助我找到了一个bug。我忘记设置

路径图的
起始点
，
IsClosed=true
和
IsFilled=true
。但是现在我得到了
IntersectionDetail.Empty
并且没有FullyInside/FullyContains。我正在用画布中绘制的两个椭圆对象尝试同样的方法。我总是有交叉点。有什么想法吗？