C# 使用MVC中实体的列表变量打印表格
我已经很长时间没有在MVC工作了;我是这方面的新手。因此,我有两个实体:C# 使用MVC中实体的列表变量打印表格,c#,asp.net-mvc,entity-framework,asp.net-mvc-4,model-view-controller,C#,Asp.net Mvc,Entity Framework,Asp.net Mvc 4,Model View Controller,我已经很长时间没有在MVC工作了;我是这方面的新手。因此,我有两个实体: // Entity Worker [Display(Name = "ID")] public Int32 Id { get; set; } [Display(Name = "Número")] public Int32 Numero { get; set; } [Display(Name = "Nome")] // Entity Lottery public Int32 Id { get; set; } [Di
// Entity Worker
[Display(Name = "ID")]
public Int32 Id { get; set; }
[Display(Name = "Número")]
public Int32 Numero { get; set; }
[Display(Name = "Nome")]
// Entity Lottery
public Int32 Id { get; set; }
[Display(Name = "Tipo")]
public String Tipo { get; set; }
[Display(Name = "Data")]
public DateTime Data { get; set; }
[Display(Name = "Observações")]
public List<Worker> FuncionariosSorteados { get; set; }
其中服务是我的数据库连接存储库,在本例中,他通过ID在数据库上进行搜索以获得正确的彩票
这里我的疑问开始了,如果我想为彩票做一张桌子,我可以用彩票模型来做
@foreach (var item in Model)
{
<tr>
<td>
@Html.DisplayFor(modelItem => item.Tipo)
</td>
<td>
@Html.DisplayFor(modelItem => item.Data)
</td>
<td>
@Html.DisplayFor(modelItem => item.Observacoes)
</tr>
}
但是我怎么能对公共列表函数做同样的事情呢?我只想在GridMvc表中打印public List functioniossorteados,但是通过模型我无法访问它 我认为您需要在已经创建的foreach循环中遍历列表。大概是这样的:
@foreach (var item in Model)
{
<table>
<tr>
<td>
@Html.DisplayFor(modelItem => item.Tipo)
</td>
<td>
@Html.DisplayFor(modelItem => item.Data)
</td>
<td>
@Html.DisplayFor(modelItem => item.Observacoes)
</td>
</tr>
</table>
<table>
@foreach(var w in Model.FuncionariosSorteados )
{
<tr>
<td>@Html.DisplayFor(w => w.Id)</td>
<td>@Html.DisplayFor(w => w.Numero)</td>
</tr>
}
</table>
}
我很困惑,因为在你的行为中,你拉一张彩票记录并将其传递给你的视图,但在你的视图中,你在迭代一个看起来像IEnumerable的东西 由于从类型为彩票的模型访问FunctionariosSorteAdos没有问题,因此我假设该视图实际上使用的是IEnumerable。对于可枚举项,必须遍历列表并访问单个项的属性。例如:
@model IEnumerable<Lottery>
@Model.FuncionariosSorteados <!-- fail -->
@foreach (var lottery in Model)
{
@lottery.FuncionariosSorteados <!-- success -->
}
对于第二个实体,您可以这样创建它:
Entitie Lottery
public Lottery( )
{
FuncionariosSorteados = new List <Worker>();
}
public Int32 Id { get; set; }
[Display(Name = "Tipo")]
public String Tipo { get; set; }
[Display(Name = "Data")]
public DateTime Data { get; set; }
[Display(Name = "Observações")]
public virtual List<Worker> FuncionariosSorteados { get; set; }
然后在您的视图中,您可以使用foreach loup在列表中进行迭代将模型类型定义为彩票并使用Include。这正是我要找的!谢谢
Entitie Lottery
public Lottery( )
{
FuncionariosSorteados = new List <Worker>();
}
public Int32 Id { get; set; }
[Display(Name = "Tipo")]
public String Tipo { get; set; }
[Display(Name = "Data")]
public DateTime Data { get; set; }
[Display(Name = "Observações")]
public virtual List<Worker> FuncionariosSorteados { get; set; }