C# 类似Linq或其他结构

我的解决方案中有DB oracle。 我想在这个查询中得到一些结果。 查询示例：

select * from doctor where doctor.name like '%IVANOV_A%';

但如果我在林克这样做，我就不会有任何结果

from p in repository.Doctor.Where(x => x.Name.ToLower().Contains(name))
select p;

其中“name”是字符串参数的变量

Web布局请求下一个字符串：“Ivanov a”或“a Ivanov”

但我建议用户选择您的模式进行查询

如果姓名由“名字”和“姓氏”组成，但用户不知道您的医生的全名，如何获取“患者姓名”

PS：我被迫使用下一个sql：

select * 
from doctor
where doctor.name like '%Ivano%' and doctor.name like '%Serg%';

试试这个，它可能会工作（没有测试）：

你可以这么做

repository.Doctor.Where(x => x.Name.Contains(name))

在LINQtoSQL和LINQtoEntities中，这都被转换为类似%…%%的

。您甚至可能不需要
ToLower
，因为比较完全是数据库端的，所以使用数据库的排序规则。您必须尝试一下，但通常数据库在默认情况下是不区分大小写的。但是如果需要，您可以使用
ToLower
，它将转换为SQL

至于名称顺序问题。无论得到什么搜索字符串，都可以使用尾随空格和前导空格来查找匹配项。假设搜索字符串是“ab”。匹配项应该是（（像“%A%”和“%B%”）或（像“%A%”和“%B%”）。（请输入空格字符！）。可以通过在空格处拆分字符串来解决此问题

[System.Data.Objects.DataClasses.EdmFunction("WebDataModel", "String_Like")]
public static bool Like(this string input, string pattern)
{
    /* Turn "off" all regular expression related syntax in
     * the pattern string. */
    pattern = Regex.Escape(pattern);

    /* Replace the SQL LIKE wildcard metacharacters with the
     * equivalent regular expression metacharacters. */
    pattern = pattern.Replace("%", ".*?").Replace("_", ".");

    /* The previous call to Regex.Escape actually turned off
     * too many metacharacters, i.e. those which are recognized by
     * both the regular expression engine and the SQL LIKE
     * statement ([...] and [^...]). Those metacharacters have
     * to be manually unescaped here. */
    pattern = pattern.Replace(@"\[", "[").Replace(@"\]", "]").Replace(@"\^", "^");

    return Regex.IsMatch(input, pattern, RegexOptions.IgnoreCase);
}

如果这样更改，会有结果吗<代码>来自repository.Doctor.Where（x=>x.Name.ToLower（）.Contains（Name.ToLower（））中的p）选择p[System.Data.Objects.DataClasses.EdmFunction("WebDataModel", "String_Like")]
public static bool Like(this string input, string pattern)
{
    /* Turn "off" all regular expression related syntax in
     * the pattern string. */
    pattern = Regex.Escape(pattern);

    /* Replace the SQL LIKE wildcard metacharacters with the
     * equivalent regular expression metacharacters. */
    pattern = pattern.Replace("%", ".*?").Replace("_", ".");

    /* The previous call to Regex.Escape actually turned off
     * too many metacharacters, i.e. those which are recognized by
     * both the regular expression engine and the SQL LIKE
     * statement ([...] and [^...]). Those metacharacters have
     * to be manually unescaped here. */
    pattern = pattern.Replace(@"\[", "[").Replace(@"\]", "]").Replace(@"\^", "^");

    return Regex.IsMatch(input, pattern, RegexOptions.IgnoreCase);
}