C# 将void(对象、DataReceivedEventArgs)传递给函数
我正在编写一个函数来创建一个进程并运行它 以下是原始函数:C# 将void(对象、DataReceivedEventArgs)传递给函数,c#,function,process,delegates,output-redirect,C#,Function,Process,Delegates,Output Redirect,我正在编写一个函数来创建一个进程并运行它 以下是原始函数: public static void LaunchApplication(string runCommand, string commandArguments, string workingDir, string informMessage) { try { Process applicationProcess = new Process(); applicationProcess.Sta
public static void LaunchApplication(string runCommand, string commandArguments, string workingDir, string informMessage)
{
try
{
Process applicationProcess = new Process();
applicationProcess.StartInfo.FileName = runCommand;
applicationProcess.StartInfo.WorkingDirectory = workingDir;
applicationProcess.StartInfo.Arguments = commandArguments;
applicationProcess.StartInfo.UseShellExecute = false;
WriteHeadlineToConsole(informMessage);
applicationProcess.Start();
while (Process.GetProcesses().Any(runningProcess => runningProcess.Id == applicationProcess.Id)) { }
WriteHeadlineToConsole("Finished " + informMessage);
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
return;
}
}
我想将函数的签名更改为:
public static void LaunchApplication(string runCommand, string commandArguments, string workingDir, string informMessage, Func<object, DataReceivedEventArgs> myMethodName)
applicationProcess.OutputDataReceived += new DataReceivedEventHandler(myMethodName);
可以这样做吗?试试这个:
public static void LaunchApplication(string runCommand, string commandArguments, string workingDir, string informMessage, Action<string> redirectOutput, Action<string> redirectError)
{
try
{
Process applicationProcess = new Process();
applicationProcess.StartInfo.FileName = runCommand;
applicationProcess.StartInfo.WorkingDirectory = workingDir;
applicationProcess.StartInfo.Arguments = commandArguments;
applicationProcess.StartInfo.UseShellExecute = false;
applicationProcess.EnableRaisingEvents = true;
applicationProcess.StartInfo.CreateNoWindow = true;
if (redirectOutput != null)
applicationProcess.OutputDataReceived += (s, data) => redirectOutput(data.Data);
if (redirectError != null)
applicationProcess.ErrorDataReceived += (sErr, errData) => redirectError(errData.Data);
GeneralUtils.WriteHeadlineToConsole(informMessage);
applicationProcess.Start();
if (redirectOutput != null)
applicationProcess.BeginOutputReadLine();
if (redirectError != null)
applicationProcess.BeginErrorReadLine();
applicationProcess.WaitForExit();
GeneralUtils.WriteHeadlineToConsole("Finished " + informMessage);
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
return;
}
}
PS:
下面的代码太糟糕了AccessDeniedException
可能被抛出,CPU快疯了
while (Process.GetProcesses().Any(runningProcess => runningProcess.Id == applicationProcess.Id)) { }
使用
applicationProcess.WaitForExit()代码>取而代之 在实现所有更改后,我测试了代码,但现在我得到了:StandardOut尚未重定向或进程尚未启动。
尝试调用applicationProcess.BeginOutputReadLine()时出现异常代码>。我用更改更新了您的代码。有什么想法吗?我看不到下面这行applicationProcess.StartInfo.RedirectStandardOutput=true代码>。我想这是需要的。我的错,忘了。再次非常感谢!!
while (Process.GetProcesses().Any(runningProcess => runningProcess.Id == applicationProcess.Id)) { }