C# 如何在没有未知密钥的情况下访问Json数据?
下面是我运行该代码时的结果。我的问题是如何在不使用C# 如何在没有未知密钥的情况下访问Json数据?,c#,json,unity3d,scripting,C#,Json,Unity3d,Scripting,下面是我运行该代码时的结果。我的问题是如何在不使用“M4qRmfIqhKdy643Ujye”键(自动生成)的情况下访问/获取所有数据 如果使用JavaScript,我可以使用object.values,但由于我使用的是C#,我不知道如何获取数据 public static string RESTToJsonConverter(string incoming_data){ string data = "["; int i = 0; Debug.Log(&
“M4qRmfIqhKdy643Ujye”
键(自动生成)的情况下访问/获取所有数据
如果使用JavaScript,我可以使用object.values
,但由于我使用的是C#,我不知道如何获取数据
public static string RESTToJsonConverter(string incoming_data){
string data = "[";
int i = 0;
Debug.Log("incoming_data"+incoming_data);
data += "]";
string JSONToParse = "{\"values\":" + data + "}";
return JSONToParse;
}
更新
这是我的Downloader类中的函数之一
{
"-M4qRmfIqhKdy643Ujye": {
"assetName": "avatar",
"id": "-M4qRmfnFya7bC43Ujye",
"imageName": "icon_avatar",
"name": "Bob",
"objName": "Bobby",
"point": "-M4vZRY9vhKs65n5L_Gk",
"versionNumber": "3"
},
"-M4qRmfIqhKdy643Ujye": {
"assetName": "avatar",
"id": "-M4qRmfnFya7bC43Ujye",
"imageName": "icon_avatar",
"name": "Bobfds",
"objName": "Bobbydsf",
"point": "-M4vZRY9vhKs65n5L_Gk",
"versionNumber": "3"
},
"-M4qRmfIqhKdy643Ujye": {
"assetName": "avatar",
"id": "-M4qRmfnFya7bC43Ujye",
"imageName": "icon_avatar",
"name": "Bobfdsa",
"objName": "Bobbyfc",
"point": "-M4vZRY9vhKs65n5L_Gk",
"versionNumber": "3"
}
}
IEnumerator下载数据(字符串数据路径,动作回调){
Log(“dataPath=>”+dataPath);
var token=LocalData.getAuth();
Auth data=JsonUtility.FromJson对于您的具体情况,我将采用另一种方式:
根字段名通常并不重要,因此如果删除尾随的}
并从第二个{
开始字符串,则
public static string FirebaseToJsonConverter(DataSnapshot snapshot){
string data = "[";
int i = 0;
foreach(DataSnapshot s in snapshot.Children){
data += s.GetRawJsonValue();
i++;
if(i != snapshot.ChildrenCount)
data += ",";
}
data += "]";
string JSONToParse = "{\"values\":" + data + "}";
return JSONToParse;
}
public static string RESTToJsonConverter(string incoming_data)
{
Debug.Log($"incoming_data:/n{incoming_data}");
// remove everything before the SECOND occurrence of '{'
// remove last occurrence of '}'
var startIndex = incoming_data.IndexOf('{', incoming_data.IndexOf('{') + 1);
var endIndex = incoming_data.LastIndexOf('}') - 1;
var json = incoming_data.Substring(startIndex, endIndex - startIndex);
// then remove leading or trailing whitespace
json = json.Trim();
Debug.Log($"json:/n{json}");
var data = JsonUtility.FromJson<string>(json);
return data;
}
您只需为其创建一个c#类即可
{
"assetName": "avatar",
"id": "-M4qRmfnFya7bC43Ujye",
"imageName": "icon_avatar",
"name": "Bob",
"objName": "Bobby",
"point": "-M4vZRY9vhKs65n5L_Gk",
"versionNumber": "3"
}
然后可以使用JsonUtility
[Serializable]
public class Data
{
public string assetName;
public string id;
public string imageName;
public string name;
public string objName;
public string point;
public string versionNumber;
}
然后做一些类似的事情
[Serializable]
public class Data
{
public string assetName;
public string id;
public string imageName;
public string name;
public string objName;
public string point;
public string versionNumber;
}
我想,您的问题是关于使用非唯一键反序列化JSON。
如果是,请看这里:
在您的情况下,解决方案应包含以下内容:
声明您的合同:
var datas = RESTToJsonConverter(receivedRawData);
foreach(var data in data.Values)
{
Debug.Log(data.id);
}
您的“自定义反序列化程序”:
获取字典作为结果类型的一些代码
public static JToken DeserializeAndCombineDuplicates(JsonTextReader reader)
{
if (reader.TokenType == JsonToken.None)
{
reader.Read();
}
if (reader.TokenType == JsonToken.StartObject)
{
reader.Read();
JObject obj = new JObject();
while (reader.TokenType != JsonToken.EndObject)
{
string propName = (string)reader.Value;
reader.Read();
JToken newValue = DeserializeAndCombineDuplicates(reader);
JToken existingValue = obj[propName];
if (existingValue == null)
{
obj.Add(new JProperty(propName, newValue));
}
else if (existingValue.Type == JTokenType.Array)
{
CombineWithArray((JArray)existingValue, newValue);
}
else // Convert existing non-array property value to an array
{
JProperty prop = (JProperty)existingValue.Parent;
JArray array = new JArray();
prop.Value = array;
array.Add(existingValue);
CombineWithArray(array, newValue);
}
reader.Read();
}
return obj;
}
if (reader.TokenType == JsonToken.StartArray)
{
reader.Read();
JArray array = new JArray();
while (reader.TokenType != JsonToken.EndArray)
{
array.Add(DeserializeAndCombineDuplicates(reader));
reader.Read();
}
return array;
}
return new JValue(reader.Value);
}
private static void CombineWithArray(JArray array, JToken value)
{
if (value.Type == JTokenType.Array)
{
foreach (JToken child in value.Children())
array.Add(child);
}
else
{
array.Add(value);
}
}
使用(StringReader sr=new StringReader(json))
使用(JsonTextReader reader=newjsontextreader(sr))
{
var parsed=反序列化和组合复制(reader).ToObject();
if(已解析!=null)
{
解析
托利斯先生()
.ForEach(x=>Console.WriteLine(“\r\nkey={0}\r\n值:\r\n{1}”
,x.键
,string.Join(“\r\n”,x.Value
.Select(z=>string.Join(“\t\t”,z.name,z.id,z.objName))
.ToArray());
}还有一个控制台。WriteLine(“不行,老兄!”);
}
完整的解决方案放在这里:当您研究“反序列化json C#”时,您遇到了什么问题?@MichaelRandall我认为这个问题与您可以反序列化到nameValue对或字典有关
public static Dictionary<string, Data> RESTToJsonConverter(string incoming_data)
{
Debug.Log($"incoming_data:/n{incoming_data}");
var data = JsonConvert.DeserializeObject<Dictionary<string, Data>(json);
return data;
}
var datas = RESTToJsonConverter(receivedRawData);
foreach(var data in data.Values)
{
Debug.Log(data.id);
}
public class Data
{
public string assetName{get;set;}
public string id{get;set;}
public string imageName{get;set;}
public string name{get;set;}
public string objName{get;set;}
public string point{get;set;}
public string versionNumber{get;set;}
}
public static JToken DeserializeAndCombineDuplicates(JsonTextReader reader)
{
if (reader.TokenType == JsonToken.None)
{
reader.Read();
}
if (reader.TokenType == JsonToken.StartObject)
{
reader.Read();
JObject obj = new JObject();
while (reader.TokenType != JsonToken.EndObject)
{
string propName = (string)reader.Value;
reader.Read();
JToken newValue = DeserializeAndCombineDuplicates(reader);
JToken existingValue = obj[propName];
if (existingValue == null)
{
obj.Add(new JProperty(propName, newValue));
}
else if (existingValue.Type == JTokenType.Array)
{
CombineWithArray((JArray)existingValue, newValue);
}
else // Convert existing non-array property value to an array
{
JProperty prop = (JProperty)existingValue.Parent;
JArray array = new JArray();
prop.Value = array;
array.Add(existingValue);
CombineWithArray(array, newValue);
}
reader.Read();
}
return obj;
}
if (reader.TokenType == JsonToken.StartArray)
{
reader.Read();
JArray array = new JArray();
while (reader.TokenType != JsonToken.EndArray)
{
array.Add(DeserializeAndCombineDuplicates(reader));
reader.Read();
}
return array;
}
return new JValue(reader.Value);
}
private static void CombineWithArray(JArray array, JToken value)
{
if (value.Type == JTokenType.Array)
{
foreach (JToken child in value.Children())
array.Add(child);
}
else
{
array.Add(value);
}
}
using (StringReader sr = new StringReader(json))
using (JsonTextReader reader = new JsonTextReader(sr))
{
var parsed = DeserializeAndCombineDuplicates(reader).ToObject<Dictionary<string, Data[]>>();
if(parsed!=null)
{
parsed
.ToList()
.ForEach(x=>Console.WriteLine("\r\nkey={0}\r\nvalues:\r\n{1}"
, x.Key
, string.Join("\r\n", x.Value
.Select(z=>string.Join("\t\t", z.name, z.id, z.objName))
.ToArray())));
} else Console.WriteLine("No way, dude!");
}