C# Web scrape项目写入过多信息

我正试图修改下面的代码，以便从www.itoworld.com/careers上抓取工作。作业采用表格格式，并返回所有，您只需创建一个“名称节点”并将其用于解析方法

我用这段代码进行了测试，它对我有效

            var parentnode = node.ParentNode.ParentNode.ParentNode.FirstChild.NextSibling;
            var nameNode = parentnode.FirstChild;

            Links l = new Links();
            l.Name = ParseHtmlContainingText(nameNode.InnerText);
            l.Link = node.GetAttributeValue("href", "");

---

那太完美了。非常感谢你。我将努力更好地理解遗产。

<a  class="std-btn" href="http://www.itoworld.com/office-manager/">Office Manager</a> 

<a href='http://www.itoworld.com/office-manager/' target='_blank'>Office ManagerOffice & AdminCambridgeFind out more</a>

public string ExtractIto()
    {
        string sUrl = "http://www.itoworld.com/careers/";
        GlobusHttpHelper ghh = new GlobusHttpHelper();
        List<Links> link = new List<Links>();

        bool Next = true;
        int count = 1;

        string html = ghh.getHtmlfromUrl(new Uri(string.Format(sUrl)));
        HtmlAgilityPack.HtmlDocument hd = new HtmlAgilityPack.HtmlDocument();
        hd.LoadHtml(html);
        var hn = hd.DocumentNode.SelectSingleNode("//*[@class='btn-wrapper']");

        var hnc = hn.SelectNodes(".//a");

        foreach (var node in hnc)
        {

            try
            {
                var parentnode = node.ParentNode.ParentNode.ParentNode.FirstChild.NextSibling; 
                Links l = new Links();
                l.Name = ParseHtmlContainingText(parentnode.InnerText);     
                l.Link = node.GetAttributeValue("href", "");


                link.Add(l);


            }

        }


        string Xml = getXml(link);

        return WriteXml(Xml);

 public string ParseHtmlContainingText(string htmlString)
    {
        return Regex.Replace(Regex.Replace(WebUtility.HtmlDecode(htmlString), @"<[^>]+>|&nbsp;", ""), @"\s{2,}", " ").Trim(); 
    }

            var parentnode = node.ParentNode.ParentNode.ParentNode.FirstChild.NextSibling;
            var nameNode = parentnode.FirstChild;

            Links l = new Links();
            l.Name = ParseHtmlContainingText(nameNode.InnerText);
            l.Link = node.GetAttributeValue("href", "");