用C#发出警报，在一天中按特定的固定时间鸣响

我试图在特定的时间发出警报（例如，从上午9:30到下午4点，每隔五分钟）。所以，我想写一段9:30和9:35响起的代码，然后。但每种方法最终都会出错。在我的代码中，我有一个包含时间的字符串，但我不能在if（…）中使用该字符串或组来发出警报。只要一个变量就可以了，我错在哪里了

{
    public partial class Form1 : Form
    {
        System.Timers.Timer timer;

        public Form1()
        {
            InitializeComponent();
        }

        private void Form1_Load(object sender, EventArgs e)
        {
            timer = new System.Timers.Timer();
            timer.Interval = 1000;
            timer.Elapsed += Timer_Elapsed;
        }

        private void Timer_Elapsed(object sender, ElapsedEventArgs e)
        {
            DateTime currentTime = DateTime.Now;


            string[] DailyTime = { 093000, 093500 };

            if (((currentTime.Hour * 10000)  + (currentTime.Minute *100)  + currentTime.Second) == DailyTime) 
            {
                timer.Stop();
                try 
                {
                    SoundPlayer player = new SoundPlayer();
                    player.SoundLocation = @"C:\Windows\Media\Time interval alarm\FiveH.wav";
                    player.Play();

计时器初始化方法：

private async void InitializeTimer()
{
     while (!timer.Enabled) //keep looping until timer is initialized
     {
         //if the minute is a multiple of 5 (:00, :05, ...) start the timer
         if (DateTime.Now.Minute % 5 == 0 && DateTime.Now.Second == 0)
         {
             timer.Start();
             TriggerAlarm(); //trigger the alarm initially instead of having to wait 5min
         }
         else
         {
             await Task.Delay(100);
         }            
     }        
}

您可以将时间和报警路径存储在字典中：

Dictionary<TimeSpan, string> dict = new Dictionary<TimeSpan, string>()
{
    { new TimeSpan(9, 30, 0), @"C:\Windows\Media\Time interval alarm\FiveH.wav" },
    { new TimeSpan(9, 35, 0), @"C:\Windows\Media\Time interval alarm\Whatever.wav" },
    { new TimeSpan(9, 40, 0), @"C:\Windows\Media\Time interval alarm\Whatever1.wav" },
    { new TimeSpan(9, 45, 0), @"C:\Windows\Media\Time interval alarm\Whatever2.wav" },
    //...
    { new TimeSpan(16, 0, 0), @"C:\Windows\Media\Time interval alarm\Whatever3.wav" }
};

播放声音的方法

private static void TriggerAlarm()
{
    TimeSpan alarmTime = new TimeSpan(DateTime.Now.Hour, DateTime.Now.Minute, 0);
    if (dict.TryGetValue(alarmTime, out string alarmFile))
    {
        using (SoundPlayer player = new SoundPlayer(alarmFile))
        {
            player.Play();
        }
    }
    else
    {
        //this alarm time is not found in the dictionary, 
        //therefore, no alarm should be played at this time (e.g. 16:05:00)
    }
}

---

您得到了什么错误？错误CS0029无法将类型“int”隐式转换为“string”PM-错误CS0029无法将类型“int”隐式转换为“string”PM-错误CS0019运算符“==”不能应用于类型“int”和

string[]DailyTime={093000，093500}的操作数我怀疑这个编译。稍后，您将尝试将此字符串数组等于整数。。。不可能。错误完全是意料之中的。非常感谢您抽出时间，但这一次最终不会奏效，因为例如；第三次，它应该播放另一个文件。如果它是一个在这些时间的代码，它的工作效果最好。。。。播放这个，然后在这些时间播放那个。例如，在9:45我希望程序播放一个显示为15而不是5的文件，然后在9:50播放上一个显示为5的文件
private void Timer_Elapsed(object sender, ElapsedEventArgs e)
{
    TriggerAlarm();
}

private static void TriggerAlarm()
{
    TimeSpan alarmTime = new TimeSpan(DateTime.Now.Hour, DateTime.Now.Minute, 0);
    if (dict.TryGetValue(alarmTime, out string alarmFile))
    {
        using (SoundPlayer player = new SoundPlayer(alarmFile))
        {
            player.Play();
        }
    }
    else
    {
        //this alarm time is not found in the dictionary, 
        //therefore, no alarm should be played at this time (e.g. 16:05:00)
    }
}