C# SQL帮助-从联接返回重复项
我的SQL查询连接多个表，因此它显示多个结果。我知道SELECT DISTINCT，但其中一个字段（'Account.Name'）偶尔会有所不同，因此它将此记录视为新行。有什么想法吗？以下是我的SQL：C# SQL帮助-从联接返回重复项,c#,asp.net,sql,C#,Asp.net,Sql,我的SQL查询连接多个表，因此它显示多个结果。我知道SELECT DISTINCT，但其中一个字段（'Account.Name'）偶尔会有所不同，因此它将此记录视为新行。有什么想法吗？以下是我的SQL： SELECT DISTINCT d.ID, ISNULL(d.OnHold, 0) AS 'OnHold', d.OnHoldReason AS 'On Hold Reason', d.LegacyID AS 'Consignment#',
SELECT DISTINCT
d.ID, ISNULL(d.OnHold, 0) AS 'OnHold', d.OnHoldReason AS 'On Hold Reason', d.LegacyID AS 'Consignment#', d.IntConNo AS 'Consignment Ref',
CASE WHEN JobType = 'O' THEN 'Outward' ELSE 'Collection' END AS 'Job Type', d.TripDate AS 'Delivery Date', d.DeliveryTown AS 'Delivery Town',
d.DeliveryPostcode AS 'Delivery Postcode', d.VehicleReg AS 'Vehicle Reg', d.RequiredCollectionDate AS 'Req. Collection Date',
d.VehicleReg AS 'Vehicle Registration', CASE WHEN d .DeliveryStatus = 2 THEN 'OK' END AS 'Delivery Status', d.ItemsignedBy AS 'POD Signed By',
d.BaseRate AS 'Base Rate', d.FuelSurcharge AS 'Fuel Surcharge', d.AdditionalCharges AS 'Additional Charges',
d.BaseRate + d.FuelSurcharge + d.AdditionalCharges AS 'Value', CASE WHEN InvoiceNumber IS NULL THEN CONVERT(bit, 0) ELSE CONVERT(bit, 1)
END AS Tagged, CASE WHEN di.Total = di.Delivered THEN 'Recieved' ELSE 'Not Recieved' END AS 'Items', Account.Name
FROM Deliveries AS d LEFT OUTER JOIN
(SELECT Consignment, COUNT(*) AS Total, COUNT(CASE WHEN Status = 2 THEN 1 END) AS Delivered
FROM Items
GROUP BY Consignment) AS di ON d.ID = di.Consignment INNER JOIN
Account ON d.Customer = Account.InvoiceAccount
WHERE (d.InvoiceNumber IS NULL) AND (d.TripDate > 29 / 11 / 2010)
ORDER BY 'Consignment#'
最简单的解决方案是用GROUPBY替换DISTINCT。缺点是只返回一个accountname get 其他的解决办法可能是
- 创建一个函数，返回连接的帐户名
- 使用子选择仅返回一个名称
SELECT d.ID
, ISNULL(d.OnHold, 0) AS 'OnHold'
, d.OnHoldReason AS 'On Hold Reason'
, d.LegacyID AS 'Consignment#'
, d.IntConNo AS 'Consignment Ref'
, CASE WHEN JobType = 'O' THEN 'Outward' ELSE 'Collection' END AS 'Job Type'
, d.TripDate AS 'Delivery Date'
, d.DeliveryTown AS 'Delivery Town'
, d.DeliveryPostcode AS 'Delivery Postcode'
, d.VehicleReg AS 'Vehicle Reg'
, d.RequiredCollectionDate AS 'Req. Collection Date'
, d.VehicleReg AS 'Vehicle Registration'
, CASE WHEN d .DeliveryStatus = 2 THEN 'OK' END AS 'Delivery Status', d.ItemsignedBy AS 'POD Signed By'
, d.BaseRate AS 'Base Rate'
, d.FuelSurcharge AS 'Fuel Surcharge'
, d.AdditionalCharges AS 'Additional Charges'
, d.BaseRate + d.FuelSurcharge + d.AdditionalCharges AS 'Value'
, CASE WHEN InvoiceNumber IS NULL THEN CONVERT(bit, 0) ELSE CONVERT(bit, 1) END AS Tagged
, CASE WHEN di.Total = di.Delivered THEN 'Recieved' ELSE 'Not Recieved' END AS 'Items'
, MIN(Account.Name)
FROM Deliveries AS d
LEFT OUTER JOIN (
SELECT Consignment
, COUNT(*) AS Total
, COUNT(CASE WHEN Status = 2 THEN 1 END) AS Delivered
FROM Items
GROUP BY
Consignment
) AS di ON d.ID = di.Consignment
INNER JOIN Account ON d.Customer = Account.InvoiceAccount
WHERE (d.InvoiceNumber IS NULL)
AND (d.TripDate > 29 / 11 / 2010)
GROUP BY
d.ID
, ISNULL(d.OnHold, 0)
, d.OnHoldReason
, d.LegacyID
, d.IntConNo
, CASE WHEN JobType = 'O' THEN 'Outward' ELSE 'Collection' END
, d.TripDate
, d.DeliveryTown
, d.DeliveryPostcode
, d.VehicleReg
, d.RequiredCollectionDate
, d.VehicleReg
, CASE WHEN d .DeliveryStatus = 2 THEN 'OK' END AS 'Delivery Status', d.ItemsignedBy
, d.BaseRate
, d.FuelSurcharge
, d.AdditionalCharges
, d.BaseRate + d.FuelSurcharge + d.AdditionalCharges
, CASE WHEN InvoiceNumber IS NULL THEN CONVERT(bit, 0) ELSE CONVERT(bit, 1) END
, CASE WHEN di.Total = di.Delivered THEN 'Recieved' ELSE 'Not Recieved' END
ORDER BY
'Consignment#'
最简单的解决方案是用GROUPBY替换DISTINCT。缺点是只返回一个accountname get 其他的解决办法可能是
- 创建一个函数，返回连接的帐户名
- 使用子选择仅返回一个名称
SELECT d.ID
, ISNULL(d.OnHold, 0) AS 'OnHold'
, d.OnHoldReason AS 'On Hold Reason'
, d.LegacyID AS 'Consignment#'
, d.IntConNo AS 'Consignment Ref'
, CASE WHEN JobType = 'O' THEN 'Outward' ELSE 'Collection' END AS 'Job Type'
, d.TripDate AS 'Delivery Date'
, d.DeliveryTown AS 'Delivery Town'
, d.DeliveryPostcode AS 'Delivery Postcode'
, d.VehicleReg AS 'Vehicle Reg'
, d.RequiredCollectionDate AS 'Req. Collection Date'
, d.VehicleReg AS 'Vehicle Registration'
, CASE WHEN d .DeliveryStatus = 2 THEN 'OK' END AS 'Delivery Status', d.ItemsignedBy AS 'POD Signed By'
, d.BaseRate AS 'Base Rate'
, d.FuelSurcharge AS 'Fuel Surcharge'
, d.AdditionalCharges AS 'Additional Charges'
, d.BaseRate + d.FuelSurcharge + d.AdditionalCharges AS 'Value'
, CASE WHEN InvoiceNumber IS NULL THEN CONVERT(bit, 0) ELSE CONVERT(bit, 1) END AS Tagged
, CASE WHEN di.Total = di.Delivered THEN 'Recieved' ELSE 'Not Recieved' END AS 'Items'
, MIN(Account.Name)
FROM Deliveries AS d
LEFT OUTER JOIN (
SELECT Consignment
, COUNT(*) AS Total
, COUNT(CASE WHEN Status = 2 THEN 1 END) AS Delivered
FROM Items
GROUP BY
Consignment
) AS di ON d.ID = di.Consignment
INNER JOIN Account ON d.Customer = Account.InvoiceAccount
WHERE (d.InvoiceNumber IS NULL)
AND (d.TripDate > 29 / 11 / 2010)
GROUP BY
d.ID
, ISNULL(d.OnHold, 0)
, d.OnHoldReason
, d.LegacyID
, d.IntConNo
, CASE WHEN JobType = 'O' THEN 'Outward' ELSE 'Collection' END
, d.TripDate
, d.DeliveryTown
, d.DeliveryPostcode
, d.VehicleReg
, d.RequiredCollectionDate
, d.VehicleReg
, CASE WHEN d .DeliveryStatus = 2 THEN 'OK' END AS 'Delivery Status', d.ItemsignedBy
, d.BaseRate
, d.FuelSurcharge
, d.AdditionalCharges
, d.BaseRate + d.FuelSurcharge + d.AdditionalCharges
, CASE WHEN InvoiceNumber IS NULL THEN CONVERT(bit, 0) ELSE CONVERT(bit, 1) END
, CASE WHEN di.Total = di.Delivered THEN 'Recieved' ELSE 'Not Recieved' END
ORDER BY
'Consignment#'
如果Account.Name不同，则它是一条新记录。我不清楚你想限制什么。如果不希望看到Account.Name的所有实例，则不要返回它或使用子选择或存储过程将所有Account.Name实例一起生成聚合字段（即连接）。如果Account.Name不同，则它是一条新记录。我不清楚你想限制什么。如果您不想看到Account.Name的所有实例，请不要返回它，也不要使用sub-select或存储过程来生成包含所有Account.Name实例的聚合字段（即连接）。谢谢，伙计，我想我会选择sub-select路线。谢谢，伙计，我想我会选择sub-select路线。