Date 计算未来几周的活动数量
我需要计算下几个星期的活动数量。但我的方法太慢(工作时间超过1.5小时)。如何加快这个脚本的速度?目前,我在每个Date 计算未来几周的活动数量,date,calendar,applescript,Date,Calendar,Applescript,我需要计算下几个星期的活动数量。但我的方法太慢(工作时间超过1.5小时)。如何加快这个脚本的速度?目前,我在每个weekNumber中每次都会获得日历中的所有事件。。。这很慢,但我不知道如何才能只获取一次所有事件,并为每个事件设置周数 tell application "Calendar" set theCalendars to name of calendars repeat with theCalendar in theCalendars set lis
weekNumber
中每次都会获得日历中的所有事件。。。这很慢,但我不知道如何才能只获取一次所有事件,并为每个事件设置周数
tell application "Calendar"
set theCalendars to name of calendars
repeat with theCalendar in theCalendars
set listCurrentCalendar to {}
set end of listCurrentCalendar to theCalendar
repeat with weekNumber from 1 to 13
set currentWeekMonday to my DateOfThisInstanceOfThisWeekdayBeforeOrAfterThisDate(current date, Monday, weekNumber)
set nextWeekMonday to my DateOfThisInstanceOfThisWeekdayBeforeOrAfterThisDate(current date, Monday, weekNumber + 1)
set numberOfEvents to 0
set TheEvents to events of calendar theCalendar
repeat with anEvent in TheEvents
set eventStartDate to start date of anEvent
if eventStartDate ≥ currentWeekMonday and eventStartDate ≤ nextWeekMonday then
set numberOfEvents to numberOfEvents + 1
end if
end repeat
set end of listCurrentCalendar to numberOfEvents
end repeat
set end of listData to listCurrentCalendar
end repeat
end tell
以下是一个为期两周的示例:
set myEvents to {}
tell application "iCal"
set myCalendars to calendars
repeat with aCalendar in myCalendars
set calEvents to (every event of aCalendar whose start date > (current date) and end date < ((current date) + (2 * weeks)))
if calEvents ≠ {} then set myEvents to myEvents & calEvents
end repeat
end tell
将myEvents设置为{}
告诉应用程序“iCal”
将myCalendars设置为日历
在myCalendars中使用aCalendar重复此操作
将calEvents设置为(开始日期>(当前日期)和结束日期<((当前日期)+(2*周))的aCalendar的每个事件)
如果加热炉≠ {}然后将myEvents设置为myEvents&calEvents
结束重复
结束语