Rails在where()中将datetime转换为date
我有以下问题: 我需要将where select中的日期时间字段转换为日期字段Rails在where()中将datetime转换为date,date,ruby-on-rails-4,where-clause,Date,Ruby On Rails 4,Where Clause,我有以下问题: 我需要将where select中的日期时间字段转换为日期字段 scope :after_start_date, lambda { |value| where('end_time <= (?)', value) if value} scope:在开始日期之后,lambda{| value | where('end|u time您可以使用ruby方法创建自己的日期/时间显示 time.strftime(字符串)=>string %a - The abbreviated
scope :after_start_date, lambda { |value| where('end_time <= (?)', value) if value}
scope:在开始日期之后,lambda{| value | where('end|u time您可以使用ruby方法创建自己的日期/时间显示
time.strftime(字符串)=>string
%a - The abbreviated weekday name (``Sun'')
%A - The full weekday name (``Sunday'')
%b - The abbreviated month name (``Jan'')
%B - The full month name (``January'')
%c - The preferred local date and time representation
%d - Day of the month (01..31)
%H - Hour of the day, 24-hour clock (00..23)
%I - Hour of the day, 12-hour clock (01..12)
%j - Day of the year (001..366)
%m - Month of the year (01..12)
%M - Minute of the hour (00..59)
%p - Meridian indicator (``AM'' or ``PM'')
%S - Second of the minute (00..60)
%U - Week number of the current year,
starting with the first Sunday as the first
day of the first week (00..53)
%W - Week number of the current year,
starting with the first Monday as the first
day of the first week (00..53)
%w - Day of the week (Sunday is 0, 0..6)
%x - Preferred representation for the date alone, no time
%X - Preferred representation for the time alone, no date
%y - Year without a century (00..99)
%Y - Year with century
%Z - Time zone name
%% - Literal ``%'' character
t = Time.now
t.strftime("Printed on %m/%d/%Y") #=> "Printed on 04/09/2003"
t.strftime("at %I:%M%p") #=> "at 08:56AM"
例如:
date = Date.parse('2014-09-08 00:00:00 UTC')
# => Mon, 08 Sep 2014
date.strftime('%d-%m-%Y')
# => "08-09-2014"
并相应地在数据库中搜索..我希望这可能对您有所帮助
编辑:
如果您想从SQL Server获取数据并将datetime转换为date,那么我更新了我的问题描述。因此,我希望问题更清楚。@user3726033:那么您的意思是要将DB存储数据的datetime转换为date???@user3726033:检查我的答案中的编辑部分…如果它对您有帮助,您可以进行升级投票并接受;)