Delphi 如何只捕获屏幕上鼠标点击的区域?
下面的代码在每次单击鼠标左键时生成桌面的屏幕截图。 但我想做一个屏幕截图,只在该地区发生鼠标点击,例如,如果某个按钮被点击在某个网站上,屏幕截图必须只有这个按钮 GIF 这是可能的吗 如果是的话,如果有人展示代码示例,我会非常高兴!提前谢谢Delphi 如何只捕获屏幕上鼠标点击的区域?,delphi,winapi,screenshot,mouse-coordinates,Delphi,Winapi,Screenshot,Mouse Coordinates,下面的代码在每次单击鼠标左键时生成桌面的屏幕截图。 但我想做一个屏幕截图,只在该地区发生鼠标点击,例如,如果某个按钮被点击在某个网站上,屏幕截图必须只有这个按钮 GIF 这是可能的吗 如果是的话,如果有人展示代码示例,我会非常高兴!提前谢谢 program Project1; {$APPTYPE CONSOLE} {$R *.res} uses Windows, Messages, SysUtils, Graphics, Imaging.PngImage; ty
program Project1;
{$APPTYPE CONSOLE}
{$R *.res}
uses
Windows,
Messages,
SysUtils,
Graphics,
Imaging.PngImage;
type
MouseLLHookStruct = record
end;
const
WH_MOUSE_LL = 14;
var
Msg: TMsg;
mHook: Cardinal;
procedure GetCursor(ScreenShotBitmap: TBitmap);
var
R: TRect;
Icon: TIcon;
II: TIconInfo;
CI: TCursorInfo;
begin
R := ScreenShotBitmap.Canvas.ClipRect;
Icon := TIcon.Create;
try
CI.cbSize := SizeOf(CI);
if GetCursorInfo(CI) then
if CI.Flags = CURSOR_SHOWING then
begin
Icon.Handle := CopyIcon(CI.hCursor);
if GetIconInfo(Icon.Handle, II) then
begin
ScreenShotBitmap.Canvas.Draw(CI.ptScreenPos.X - Integer(II.xHotspot) -
R.Left, CI.ptScreenPos.Y - Integer(II.yHotspot) - R.Top, Icon);
end;
end;
finally
Icon.Free;
end;
end;
procedure ScreenCapture;
var
DC: HDC;
Rect: TRect;
png: TPngImage;
Bitmap: TBitmap;
begin
png := TPngImage.Create;
Bitmap := TBitmap.Create;
GetWindowRect(GetDesktopWindow, Rect);
DC := GetWindowDC(GetDesktopWindow);
try
Bitmap.Width := Rect.Right - Rect.Left;
Bitmap.Height := Rect.Bottom - Rect.Top;
BitBlt(Bitmap.Canvas.Handle, 0, 0, Bitmap.Width, Bitmap.Height, DC, 0,
0, SRCCOPY);
GetCursor(Bitmap);
png.Assign(Bitmap);
png.SaveToFile('screenshot.png');
finally
ReleaseDC(GetDesktopWindow, DC);
png.Free;
Bitmap.Free;
end;
end;
function LowLevelMouseHookProc(nCode: LongInt; WPARAM: WPARAM; lParam: lParam)
: LRESULT; stdcall;
var
info: ^MouseLLHookStruct absolute lParam;
begin
Result := CallNextHookEx(mHook, nCode, WPARAM, lParam);
if (WPARAM = WM_LBUTTONUP) then
ScreenCapture;
end;
begin
mHook := SetWindowsHookEx(WH_MOUSE_LL, @LowLevelMouseHookProc, HInstance, 0);
while GetMessage(Msg, 0, 0, 0) do
begin
TranslateMessage(Msg);
DispatchMessage(Msg);
end;
UnhookWindowsHookEx(mHook);
end.
编辑: 我在VB.NET中找到了一个替代方案。但是用Delphi代码怎么可能是一个解决方案呢
Private Shared Function CaptureCursor(ByRef x As Integer, ByRef y As Integer) As Bitmap
Dim bmp As Bitmap
Dim hicon As IntPtr
Dim ci As New CURSORINFO()
Dim icInfo As ICONINFO
ci.cbSize = Marshal.SizeOf(ci)
If GetCursorInfo(ci) Then
hicon = CopyIcon(ci.hCursor)
If GetIconInfo(hicon, icInfo) Then
x = ci.ptScreenPos.X - CInt(icInfo.xHotspot)
y = ci.ptScreenPos.Y - CInt(icInfo.yHotspot)
Dim ic As Icon = Icon.FromHandle(hicon)
bmp = ic.ToBitmap()
ic.Dispose()
Return bmp
End If
End If
Return Nothing
End Function
'Insert on Timer tick event
Private Sub Screenshot()
Dim x As Integer
Dim y As Integer
Dim cursorBmp As Bitmap = CaptureCursor(x, y)
Dim bmp As New Bitmap(Cursor.Size.Width, Cursor.Size.Height)
Dim sourceLocation As Point = Control.MousePosition
sourceLocation.Offset(-16, -16)
Using g As Graphics = Graphics.FromImage(bmp)
g.CopyFromScreen(sourceLocation, Point.Empty, bmp.Size)
g.DrawImage(cursorBmp, x - sourceLocation.X, y - sourceLocation.Y)
cursorBmp.Dispose()
End Using
Me.PictureBox1.Image = bmp
End Sub
有一个简单的方法,你可以参考下面的代码 此代码可以获取包含鼠标位置的屏幕截图,只需使用
BitBlt
指定鼠标坐标和矩形大小(按钮大小),最终获得所需的BMP图像。使用DrawImage
将BMP图像绘制到矩形框中,如GIF所示
通过调用GetCursorInfo
可以获得鼠标坐标,并且可以根据需要指定矩形的大小
请注意,在获得鼠标坐标后,将它们传递到BitBlt
中时,需要分别减去左侧和上方半个矩形的大小
比如说,
BitBlt(Newhdc,
0,
0,
rect_x, //size of the rect
rect_y,
HDC,
x - half_rect_x, //x,y => mouse coordinates
y - half_rect_y, //half_rect_x, half_rect_y => the size of half the rectangle
SRCCOPY);
。您需要GIF显示的效果吗?
屏幕截图必须仅显示此按钮。
如果您只需单击按钮的一角,例如按钮的右下角。如何显示屏幕截图?我不知道如何在网页上获取按钮实例,但我认为这与CSS有关。如果您需要单击按钮的某个部分来显示按钮的整个屏幕截图,我认为这不是一件简单的事情。至少您需要熟悉网页上控件的布局和属性。@STRIVESSUN MSFT,您需要GIF显示的效果吗?
-是。
BitBlt(Newhdc,
0,
0,
rect_x, //size of the rect
rect_y,
HDC,
x - half_rect_x, //x,y => mouse coordinates
y - half_rect_y, //half_rect_x, half_rect_y => the size of half the rectangle
SRCCOPY);