如何在Django中定制EmailMultiAlternatives的电子邮件后端

背景：-

我的电子邮件后端是这样的：

EMAIL_HOST ='smtp.gmail.com' 
EMAIL_PORT = 587
EMAIL_HOST_USER = 'feedback@example.com' 
EMAIL_HOST_PASSWORD = 'XXX' 
EMAIL_USE_TLS = True

from django.core.mail import *

#retrieve emailbackend from settings.py
connection = get_connection(username, password)
#change connection parameters
connection.host='XXX'
msg = EmailMultiAlternatives(subject, text_content, from_email, [to], connection)
msg.attach_alternative(html_content, "text/html")

问题:-

我正在使用EmailMultiAlternations发送html邮件。 现在我想定义auth_user和auth_password，以便更改“from”。基本上，我想超越电子邮件主机用户，但希望发件人电子邮件冗长，即“支持团队”。怎样才能做到呢

subject, from_email, to = "hello", 'Support Team','to_user@gmail.com'
text = "hello"
html = "<strong>hello</strong>"
msg = EmailMultiAlternatives(subject, text_content, from_email, [to])
msg.attach_alternative(html_content, "text/html")
msg.send(fail_silently=False,auth_user = 'support@example.me',auth_password = 'XXX')

主题，从电子邮件发送至=“你好”，“支持团队”，发送至_user@gmail.com'
text=“你好”
html=“你好”
msg=emailmultialternations（主题、文本内容、发件人/电子邮件[收件人]）
msg.附加可选内容（html内容，“文本/html”）
msg.send（失败=False，身份验证=user）support@example.me，身份验证密码='XXX'）

您可以这样做：

EMAIL_HOST ='smtp.gmail.com' 
EMAIL_PORT = 587
EMAIL_HOST_USER = 'feedback@example.com' 
EMAIL_HOST_PASSWORD = 'XXX' 
EMAIL_USE_TLS = True

from django.core.mail import *

#retrieve emailbackend from settings.py
connection = get_connection(username, password)
#change connection parameters
connection.host='XXX'
msg = EmailMultiAlternatives(subject, text_content, from_email, [to], connection)
msg.attach_alternative(html_content, "text/html")

---

你可以这样做：

EMAIL_HOST ='smtp.gmail.com' 
EMAIL_PORT = 587
EMAIL_HOST_USER = 'feedback@example.com' 
EMAIL_HOST_PASSWORD = 'XXX' 
EMAIL_USE_TLS = True

from django.core.mail import *

#retrieve emailbackend from settings.py
connection = get_connection(username, password)
#change connection parameters
connection.host='XXX'
msg = EmailMultiAlternatives(subject, text_content, from_email, [to], connection)
msg.attach_alternative(html_content, "text/html")

---

不需要connection.close（）。它将引发一个错误，因为send_messages会关闭它打开的所有连接。当msg.send（）引发异常时，我可以使用此方法切换到备份SMTP服务器。非常好。您可以直接传入连接。不需要connection.close（）。它将引发一个错误，因为send_messages会关闭它打开的所有连接。当msg.send（）引发异常时，我可以使用此方法切换到备份SMTP服务器。很好。你可以直接通过连接。