Django 上传后如何重定向到“/summary/1/”（/summary/saved object id/）

上传后如何重定向到

/summary/1/

（/summary/saved object id/）

一种方法是

def upload(request):
        user = request.user
        upload_form = UploadForm(request.POST or None, request.FILES or None)
        if request.method == "POST":
                if upload_form.is_valid():
                        my_model = upload_form.save(commit=False)
                        my_model.user = user
                        print my_model.src
                        my_model.save()
                        return render_to_response('index.html',, context_instance=RequestContext(request))

        return render_to_response('index.html', {'upload_form': upload_form}, context_instance=RequestContext(request))

更好的变体是

return HttpResponseRedirect('/summary/'+id)

最好的变体是（这样您就不必在视图中硬编码URL）

如果你想用

return HttpResponseRedirect(reverse(yourViewNameHere, args=[id]))

一种方法是

def upload(request):
        user = request.user
        upload_form = UploadForm(request.POST or None, request.FILES or None)
        if request.method == "POST":
                if upload_form.is_valid():
                        my_model = upload_form.save(commit=False)
                        my_model.user = user
                        print my_model.src
                        my_model.save()
                        return render_to_response('index.html',, context_instance=RequestContext(request))

        return render_to_response('index.html', {'upload_form': upload_form}, context_instance=RequestContext(request))

更好的变体是

return HttpResponseRedirect('/summary/'+id)

最好的变体是（这样您就不必在视图中硬编码URL）

如果你想用

return HttpResponseRedirect(reverse(yourViewNameHere, args=[id]))

进口

然后

进口

然后

return HttpResponseRedirect('/summary/%s/' %object_id)