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Django 无法分配"&书信电报;SimpleLazyObject:<;用户:管理员>&燃气轮机&引用;:&引用;“项目经理”;必须是一个";Profil";实例_Django_Django Models_Django Forms - Fatal编程技术网

Django 无法分配"&书信电报;SimpleLazyObject:<;用户:管理员>&燃气轮机&引用;:&引用;“项目经理”;必须是一个";Profil";实例

Django 无法分配"&书信电报;SimpleLazyObject:<;用户:管理员>&燃气轮机&引用;:&引用;“项目经理”;必须是一个";Profil";实例,django,django-models,django-forms,Django,Django Models,Django Forms,您好,我在开始保存表单时出现此错误 Cannot assign "<SimpleLazyObject: <User: admin>>": "Project.manager" must be a "Profil" instance. project.model.py project.views.py project.forms.py 我希望每个用户或经理都能通过表单链接到他们发布的项目。 如何通过保存模型来链接这两个模型 谢谢代替 project.manager = re

您好,我在开始保存表单时出现此错误

Cannot assign "<SimpleLazyObject: <User: admin>>": "Project.manager" must be a "Profil" instance.
project.model.py

project.views.py

project.forms.py

我希望每个用户或经理都能通过表单链接到他们发布的项目。 如何通过保存模型来链接这两个模型

谢谢

代替

project.manager = request.user
你应使用:

project.manager = request.user.profil

错误似乎很明显:将用户而不是profile分配给项目对象。但是,您显示的代码在Project中没有manager字段;请确保显示您正在使用的实际代码。是。我错误地忘记在project.models.py中添加manager字段
def project_new(request):
   if request.method == 'POST':
       form = ProjectForm(request.POST)
       if form.is_valid():
           project = form.save(commit = False)
           project.manager = request.user
           project.save()

   else:
       form = ProjectForm()


   return render(request, 'project/project_new.html', {'form': form})
class ProjectForm(forms.ModelForm):

   title = forms.CharField(label='Titre')
   description = forms.CharField(widget=CKEditorUploadingWidget())
   category = forms.ModelChoiceField(queryset =  Category.objects.all(), label='Catégorie')

#description = forms.CharField(widget=forms.Textarea(attrs={'cols': 80, 'rows': 20}))


   class Meta:
       model = Project
       fields = ('title', 'nb_days', 'slogan', 'category', 'description')
project.manager = request.user
project.manager = request.user.profil