如何在Docker Compose文件环境变量中转义此JSON字符串?
这是我的docker文件如何在Docker Compose文件环境变量中转义此JSON字符串?,docker,docker-compose,yaml,escaping,Docker,Docker Compose,Yaml,Escaping,这是我的docker文件 version: '2.1' services: myservice: environment: - MYENVVAR={"1": "Hello"} 当我运行docker compose ERROR: yaml.parser.ParserError: while parsing a block mapping in "./my_docker_compose_.yml", line 6, column 9 expected <bloc
version: '2.1'
services:
myservice:
environment:
- MYENVVAR={"1": "Hello"}
当我运行docker compose
ERROR: yaml.parser.ParserError: while parsing a block mapping
in "./my_docker_compose_.yml", line 6, column 9
expected <block end>, but found '}'
in "./my_docker_compose_.yml", line 6, column 111
错误:yaml.parser.parserror:在分析块映射时
在“/my_docker_compose_.yml”中,第6行第9列
应为,但找到“}”
在“/my_docker_compose_.yml”第6行第111列中
如何正确转义JSON对象,使其作为环境变量的值发送到容器中
MYENVVAR
?您应该将此变量定义为:
'FOOBAR={“foo”:“bar”}'
简言之:
version: '3.3'
services:
nginx:
ports:
- '80:80'
volumes:
- '/var/run/docker.sock:/tmp/docker.sock:ro'
restart: always
logging:
options:
max-size: 1g
environment:
- 'FOOBAR={"foo": "bar"}'
- a=test
image: nginx
docker缺陷跟踪系统也提出了类似的问题:
您可以在线验证或试验docker compose设置
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