Elixir 将聊天信息解析到其他聊天室时出错

我在向聊天室发送消息时收到错误消息

房间_channel.ex

 def join("room:" <> _user, _, socket) do
    send self(), :after_join
    {:ok, socket}
  end

  def handle_info(:after_join, socket) do
     {_, value} = Redix.command(:redix, ["GET", socket.assigns.user])
    Presence.track(socket, socket.assigns.user, %{
      online_at: :os.system_time(:millisecond),
      status: value
    })
    push socket, "presence_state", Presence.list(socket)
    {:noreply, socket}
  end

  def handle_in("message:new", message, socket) do

    broadcast! socket, "message:new", %{
      user: socket.assigns.user,
      body: message,
      timestamp: :os.system_time(:millisecond)
    }
    PhoenixChat.Endpoint.subscribe("room:" <> message["to"]) 
    PhoenixChat.Endpoint.broadcast!("room:" <> message["to"], "message:new",%{
        user: socket.assigns.user,
        body: message,
        timestamp: :os.system_time(:millisecond)
   })
    milisecondstime = :os.system_time(:millisecond)
    [room, user] = String.split(Map.get(socket, :topic), ":")
    data = Poison.encode!(%{"created_at" => :os.system_time(:millisecond), "updated_at" => :os.system_time(:millisecond), "uuid" => UUID.uuid1(), "date" => :os.system_time(:millisecond), "from" => user, "to" => message["to"], "message" => message["value"]})
    Redix.command(:redix, ["SET", UUID.uuid1(), data]) 
    {:noreply, socket}
  end

从文档中：

注意：调用方必须负责防止重复订阅。从端点调用

subscribe/1

后，同样的流程适用于处理频道内的常规Elixir消息。通常，您只需中继

%Phoenix.Socket.Broadcast{}

事件和负载：

alias Phoenix.Socket.Broadcast
def handle_info(%Broadcast{topic: _, event: ev, payload: payload}, socket) do
  push socket, ev, payload
  {:noreply, socket}
end

def handle_info(:after_join, socket) do

alias Phoenix.Socket.Broadcast
def handle_info(%Broadcast{topic: _, event: ev, payload: payload}, socket) do
  push socket, ev, payload
  {:noreply, socket}
end